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0.创建/声明一个数组
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String[] aArray = new String[5];String[] bArray = {"a","b","c", "d", "e"};String[] cArray = new String[]{"a","b","c","d","e"}; |
1.Java中打印数组
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int[] intArray = { 1, 2, 3, 4, 5 };String intArrayString = Arrays.toString(intArray);// print directly will print reference valueSystem.out.println(intArray);// [I@7150bd4dSystem.out.println(intArrayString);// [1, 2, 3, 4, 5] |
2.用数组创建一个ArrayList
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String [ ] stringArray = { "a" , "b" , "c" , "d" , "e" } ; ArrayList < String > arrayList = new ArrayList < String > ( Arrays . asList ( stringArray ) ) ; System . out . println ( arrayList ) ; // [A，B，C，D，E] |
3，检查数组中是否包含特定的值
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String[] stringArray = { "a", "b", "c", "d", "e" };boolean b = Arrays.asList(stringArray).contains("a");System.out.println(b); |
4.结合两个数组
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int[] intArray = { 1, 2, 3, 4, 5 };int[] intArray2 = { 6, 7, 8, 9, 10 };// Apache Commons Lang libraryint[] combinedIntArray = ArrayUtils.addAll(intArray, intArray2); |
5.声明一个数组的方法
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method(new String[]{"a", "b", "c", "d", "e"}); |
6，加入所提供的数组中的元素连接成一个字符串
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// containing the provided list of elements// Apache common langString j = StringUtils.join(new String[] { "a", "b", "c" }, ", ");System.out.println(j);// a, b, c |
7. Array与List之间的转换
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String[] stringArray = { "a", "b", "c", "d", "e" };ArrayList<String> arrayList = new ArrayList<String>(Arrays.asList(stringArray));String[] stringArr = new String[arrayList.size()];arrayList.toArray(stringArr);for (String s : stringArr)System.out.println(s); |
8.数组转换成set
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Set<String> set = new HashSet<String>(Arrays.asList(stringArray));System.out.println(set);//[d, e, b, c, a] |
9.数组反向输出
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int[] intArray = { 1, 2, 3, 4, 5 };ArrayUtils.reverse(intArray);System.out.println(Arrays.toString(intArray));//[5, 4, 3, 2, 1] |
10.删除数组元素
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int[] intArray = { 1, 2, 3, 4, 5 };int[] removed = ArrayUtils.removeElement(intArray, 3);//create a new arraySystem.out.println(Arrays.toString(removed)); |
最后一下int转换成byte数组
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byte[] bytes = ByteBuffer.allocate(4).putInt(8).array();for (byte t : bytes) {System.out.format("0x%x ", t);} |
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原文地址：http://www.cnblogs.com/cnsdhzzl/p/5594733.html
