C中的无符号整数在java中的处理

public class ShortOverflow {
    
    public static void main(String[] args) {
        System.out.println("java中没有无符号整数，所以");
        System.out.println("java中short最大:"+Short.MAX_VALUE);
        System.out.println("其16进制数:"+Integer.toHexString(Short.MAX_VALUE));
        System.out.println("其2进制数:"+Integer.toBinaryString(Short.MAX_VALUE));
        System.out.println("16位最大值:"+0xFFFF);
        System.out.println("===============================");
        show(32769);
    }
    
    private static void show(int num){
        System.out.println("=============转化演示=============");
        System.out.println("原来:"+num);
        System.out.println("二进制:"+Integer.toBinaryString(num));
        
        System.out.println("强转short:"+(short)(num));
        if(num>65535){
            System.out.println("该数超过了16位，强转只会保留后16位");
        }
        System.out.println("二进制:"+Integer.toBinaryString((short)(num)));
        System.out.println("强转short后与原int数是否相等:"+((short)(num)==num));
        System.out.println("还原:"+((short)(num) & 0xFFFF));
        
        System.out.println("强转char:"+(char)(num));
    }
}