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Given a binary tree, return all root-to-leaf paths.
For example, given the following binary tree:
1 / 2 3 5
All root-to-leaf paths are:
["1->2->5", "1->3"]
Credits:
Special thanks to @jianchao.li.fighter for adding this problem and creating all test cases.
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1 /** 2 * Definition for a binary tree node. 3 * public class TreeNode { 4 * int val; 5 * TreeNode left; 6 * TreeNode right; 7 * TreeNode(int x) { val = x; } 8 * } 9 */ 10 public class Solution { 11 List<String> ans = new ArrayList<String>(); 12 public List<String> binaryTreePaths(TreeNode root) { 13 if(root == null) return ans; 14 String tmp = "" + root.val; 15 DFS(ans,root,tmp); 16 return ans; 17 } 18 19 public void DFS(List<String> ans, TreeNode node, String tmp){ 20 if(node.left == null && node.right == null){ 21 ans.add(tmp); 22 return; 23 } 24 if(node.left != null) DFS(ans,node.left,tmp+"->"+node.left.val); 25 if(node.right != null) DFS(ans,node.right,tmp+"->"+node.right.val); 26 } 27 }
用递归即可。
257. Binary Tree Paths java solutions
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原文地址:http://www.cnblogs.com/guoguolan/p/5614950.html