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/** * 单表查询 * * className:实体类的名字 * vals:查询的属性 * pNames:条件的名字 * pVals:条件的值 */ @Override public List<Object> get(String className,String[] vals,Object[] pNames,Object[] pVals){ if(StringUtils.isEmpty(className)) { throw new NullParameterException("实体类的名字没有写"); } StringBuffer hql = new StringBuffer(); if(vals.length != 0) { hql.append("SELECT "); for(int i=0; i<vals.length;i++) { hql.append("p."); hql.append(vals[i]); if(i != vals.length-1) { hql.append(", "); } } } hql.append(" FROM "); hql.append(className); hql.append(" p"); if(pNames.length>0 && pVals.length>0 && pNames.length==pVals.length) { hql.append(" WHERE "); for(int i=0;i<pNames.length;i++) { hql.append(" p."); hql.append(pNames[i]); hql.append("="); hql.append(pVals[i]); if(i<pNames.length-1) { hql.append(" AND "); } } } System.out.println(hql.toString()); return null; }
1. userDao.get("VerificationCode", new String[] {"val1","val2"}, new Object[]{"p1","p2","p3"}, new Object[] {"pv1","pv2","pv3"});
输出:SELECT p.val1, p.val2 FROM VerificationCode p WHERE p.p1=pv1 AND p.p2=pv2 AND p.p3=pv3
2. userDao.get("VerificationCode", new String[] {}, new Object[]{"p1","p2","p3"}, new Object[] {"pv1","pv2","pv3"});
输出: FROM VerificationCode p WHERE p.p1=pv1 AND p.p2=pv2 AND p.p3=pv3
3. userDao.get("VerificationCode", new String[] {}, new Object[]{}, new Object[] {});
输出:FROM VerificationCode p
4.userDao.get("VerificationCode", new String[] {"p1"}, new Object[]{}, new Object[] {});
输出:SELECT p.p1 FROM VerificationCode p
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原文地址:http://www.cnblogs.com/wwzyy/p/5619606.html