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1. Use a for loop to traverse the videos and bookmarks array at the same time. For each video and bookmark pair, create a {videoId, bookmarkId} pair and add it to the videoIdAndBookmarkIdPairs array.
function() { var videos = [ { "id": 70111470, "title": "Die Hard", "boxart": "http://cdn-0.nflximg.com/images/2891/DieHard.jpg", "uri": "http://api.netflix.com/catalog/titles/movies/70111470", "rating": 4.0, }, { "id": 654356453, "title": "Bad Boys", "boxart": "http://cdn-0.nflximg.com/images/2891/BadBoys.jpg", "uri": "http://api.netflix.com/catalog/titles/movies/70111470", "rating": 5.0, }, { "id": 65432445, "title": "The Chamber", "boxart": "http://cdn-0.nflximg.com/images/2891/TheChamber.jpg", "uri": "http://api.netflix.com/catalog/titles/movies/70111470", "rating": 4.0, }, { "id": 675465, "title": "Fracture", "boxart": "http://cdn-0.nflximg.com/images/2891/Fracture.jpg", "uri": "http://api.netflix.com/catalog/titles/movies/70111470", "rating": 5.0, } ], bookmarks = [ {id: 470, time: 23432}, {id: 453, time: 234324}, {id: 445, time: 987834} ], counter, videoIdAndBookmarkIdPairs = []; for(counter = 0; counter < Math.min(videos.length, bookmarks.length); counter++) { videoIdAndBookmarkIdPairs.push({ videoId: videos[counter].id, bookmarkId: bookmarks[counter].id }) } return videoIdAndBookmarkIdPairs; }
2. Let‘s add a static zip() function to the Array type. The zip function accepts a combiner function, traverses each array at the same time, and calls the combiner function on the current item on the left-hand-side and right-hand-side. The zip function requires an item from each array in order to call the combiner function, therefore the array returned by zip will only be as large as the smallest input array.
// JSON.stringify(Array.zip([1,2,3],[4,5,6], function(left, right) { return left + right })) === ‘[5,7,9]‘ Array.zip = function(left, right, combinerFunction) { var counter, results = []; for(counter = 0; counter < Math.min(left.length, right.length); counter++) { // Add code here to apply the combinerFunction to the left and right-hand items in the respective arrays results.push(combinerFunction(left[counter], right[counter])) } return results; };
3. Let‘s repeat exercise 1, but this time lets use your new zip() function. For each video and bookmark pair, create a {videoId, bookmarkId} pair.
function() { var videos = [ { "id": 70111470, "title": "Die Hard", "boxart": "http://cdn-0.nflximg.com/images/2891/DieHard.jpg", "uri": "http://api.netflix.com/catalog/titles/movies/70111470", "rating": 4.0, }, { "id": 654356453, "title": "Bad Boys", "boxart": "http://cdn-0.nflximg.com/images/2891/BadBoys.jpg", "uri": "http://api.netflix.com/catalog/titles/movies/70111470", "rating": 5.0, }, { "id": 65432445, "title": "The Chamber", "boxart": "http://cdn-0.nflximg.com/images/2891/TheChamber.jpg", "uri": "http://api.netflix.com/catalog/titles/movies/70111470", "rating": 4.0, }, { "id": 675465, "title": "Fracture", "boxart": "http://cdn-0.nflximg.com/images/2891/Fracture.jpg", "uri": "http://api.netflix.com/catalog/titles/movies/70111470", "rating": 5.0, } ], bookmarks = [ {id: 470, time: 23432}, {id: 453, time: 234324}, {id: 445, time: 987834} ]; return Array. zip( videos, bookmarks, (video,bookmark ) => ({videoId: video.id, bookmarkId: bookmark.id})) }
[Javascript] Implement zip function
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原文地址：http://www.cnblogs.com/Answer1215/p/5620587.html
