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https://leetcode.com/problems/lru-cache/
Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get
and set
.
get(key)
- Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.set(key, value)
- Set or insert the value if the key is not already present. When the cache reached its capacity, it should invalidate the least recently used item before inserting a new item.
class pair { public int key; public int value; public pair(int k, int v) { super(); this.key = k; this.value = v; } public void setValue(int value) { this.value = value; } } class cmp implements Comparator { public int compare(Object o1, Object o2) { pair p1 = (pair) o1; pair p2 = (pair) o2; if(p1.key < p2.key) { return -1; } else if(p1.key == p2.key) { if(p1.value == p2.value) { return 0; } else if(p1.value < p2.value) { return -1; } else { return 1; } } else { return 1; } } } public class LRUCache { public Set<pair> stack = null; public HashMap<Integer, Integer> mapping = null; public TreeMap<Integer, Integer> timeToKey = null; public TreeMap<Integer, Integer> keyToTime = null; public int cap = 0; public int counter = 0; public LRUCache(int capacity) { this.mapping = new HashMap<Integer, Integer> (); this.timeToKey = new TreeMap<Integer, Integer> (); this.keyToTime = new TreeMap<Integer, Integer> (); this.cap = capacity; this.counter = 0; } public int get(int key) { if(!mapping.containsKey(key)) { return -1; } else { counter++; int value = mapping.get(key); int time = keyToTime.get(key); keyToTime.put(key, counter); timeToKey.remove(time); timeToKey.put(counter, key); return value; } } public void set(int key, int value) { counter++; if(mapping.containsKey(key)) { int time = keyToTime.get(key); keyToTime.put(key, counter); timeToKey.remove(time); timeToKey.put(counter, key); mapping.put(key, value); } else { if(mapping.size() < cap) { mapping.put(key, value); keyToTime.put(key, counter); timeToKey.put(counter, key); } else { int lru = timeToKey.pollFirstEntry().getValue(); mapping.remove(lru); mapping.put(key, value); keyToTime.put(key, counter); timeToKey.put(counter, key); } } } }
leetcode@ [146] LRU Cache (TreeMap)
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原文地址:http://www.cnblogs.com/fu11211129/p/5631623.html