android get/post如何实现多参数请求

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可使用android自带的httpclient框架实现。

1.  GET 方式传递参数

//先将参数放入List，再对参数进行URL编码

List<BasicNameValuePair> params = new LinkedList<BasicNameValuePair>();

params.add(new BasicNameValuePair("param1", "数据"));    //增加参数1

params.add(new BasicNameValuePair("param2", "value2"));//增加参数2

String param = URLEncodedUtils.format(params, "UTF-8");//对参数编码

String baseUrl = "服务器接口完整URL";

HttpGet getMethod = new HttpGet(baseUrl + "?" + param);//将URL与参数拼接

HttpClient httpClient = new DefaultHttpClient();

try {

    HttpResponse response = httpClient.execute(getMethod); //发起GET请求

    Log.i(TAG, "resCode = " + response.getStatusLine().getStatusCode()); //获取响应码

    Log.i(TAG, "result = " + EntityUtils.toString(response.getEntity(), "utf-8"));//获取服务器响应内容

} catch (ClientProtocolException e) {

    e.printStackTrace();

} catch (IOException e) {

    e.printStackTrace();

}

2. POST方式 方式传递参数

//和GET方式一样，先将参数放入List

params = new LinkedList<BasicNameValuePair>();

params.add(new BasicNameValuePair("param1", "Post方法"));//增加参数1

params.add(new BasicNameValuePair("param2", "第二个参数"));//增加参数2

try {

    HttpPost postMethod = new HttpPost(baseUrl);//创建一个post请求

    postMethod.setEntity(new UrlEncodedFormEntity(params, "utf-8")); //将参数填入POST Entity中

    HttpResponse response = httpClient.execute(postMethod); //执行POST方法

    Log.i(TAG, "resCode = " + response.getStatusLine().getStatusCode()); //获取响应码

    Log.i(TAG, "result = " + EntityUtils.toString(response.getEntity(), "utf-8")); //获取响应内容

} catch (UnsupportedEncodingException e) {

    e.printStackTrace();

} catch (ClientProtocolException e) {

    e.printStackTrace();

} catch (IOException e) {

    e.printStackTrace();

}

android get/post如何实现多参数请求

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原文地址：http://www.cnblogs.com/to-creat/p/5672893.html