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用动态规划方法求解活动选择问题,与贪心算法相比,显然是庞然大物,大材小用了,贪心算法可以非常简洁的求解活动选择问题
动态规划:
1 #include <iostream> 2 #include <vector> 3 #include <limits> 4 #define INF numeric_limits<int>::max() 5 using namespace std; 6 int act_select(int s[],int f[],int n,int **c,int **r); 7 void print_res(int **r,int start,int end); 8 int main(){ 9 int s[]={-1,1,3,0,5,3,5,6,8,8,2,12,INF}; 10 int f[]={-1,4,5,6,7,9,9,10,11,12,14,16,INF}; 11 int n=11; 12 int **c=new int*[n+2]; 13 int **r=new int*[n+2]; 14 for(int i=0;i<n+2;++i){ 15 c[i]=new int[n+2]; 16 r[i]=new int[n+2]; 17 for(int j=0;j<n+2;++j){ 18 c[i][j]=0; 19 r[i][j]=-1; 20 } 21 } 22 cout<<"The max length of the bcs is "<<act_select(s,f,n,c,r)<<endl; 23 print_res(r,0,n+1); 24 cout<<endl; 25 for(int i=0;i<n+2;++i){ 26 delete[] c[i]; 27 delete[] r[i]; 28 } 29 delete[] c; 30 delete[] r; 31 return 0; 32 } 35 36 int act_select(int s[],int f[],int n,int **c,int **r){ 37 vector<int> v; 38 v.reserve(n); 39 for(int l=1;l<=n;++l){ 40 for(int i=0;i<=n-l;++i){ 41 int j=i+l+1; 42 v.resize(0); 43 for(int k=i+1;k<=j;++k) 44 if(s[k]>f[i]&&f[k]<s[j]) 45 v.push_back(k); 46 for(vector<int>::iterator p=v.begin();p!=v.end();++p){ 47 int temp=c[i][*p]+1+c[*p][j]; 48 if(temp>c[i][j]){ 49 c[i][j]=temp; 50 r[i][j]=*p; 51 } 52 } 53 } 54 } 55 return c[0][n+1]; 56 } 57 58 void print_res(int **r,int start,int end){ 59 int m=r[start][end]; 60 if(m==-1) 61 return; 62 print_res(r,start,m); 63 cout<<m<<" "; 64 print_res(r,m,end); 65 }
代码中添加了a0和a12作为伪活动,辅助问题求解!
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原文地址:http://www.cnblogs.com/cq-shihao/p/5679311.html