01、去除字符串中的html标记及标记中的内容
【叶子函数分享一】去除字符串中的html标记及标记中的内容 --1、创建函数 create function [dbo].[clearhtml] (@maco varchar(8000)) returns varchar(8000) as begin declare @i int while 1 = 1 begin set @i=len(@maco) set @maco=replace(@maco, substring(@maco,charindex(‘<‘,@maco), charindex(‘>‘,@maco)-charindex(‘<‘,@maco)+1),space(0)) if @i=len( @maco ) break end set @maco=replace(@maco,‘ ‘,‘‘) set @maco=replace(@maco,‘ ‘,‘‘) set @maco=ltrim(rtrim(@maco)) set @maco=replace(@maco,char(9),‘‘) set @maco=replace(@maco,char(10),‘‘) set @maco=replace(@maco,char(13),‘‘) return (@maco) end --2、测试示例 declare @mark varchar(8000) set @mark=‘<body><div id=u><a href=http://passport.baidu.com/?login&tpl=mn>登录</a></div><center><img src=http://www.baidu.com/img/baidu_logo.gif width=270 height=129 usemap="#mp" id=lg><br><br><br><br><table cellpadding=0 cellspacing=0 id=l><tr><td><div id=m><a onclick=s(this) href=http://news.baidu.com>新 闻</a><b>网 页</b><a onclick=s(this) href=http://tieba.baidu.com>贴 吧</a><a onclick=s(this) href=http://zhidao.baidu.com>知 道</a><a onclick=s(this) href=http://mp3.baidu.com>MP3</a><a onclick=s(this) href=http://image.baidu.com>图 片</a><a onclick=s(this) href=http://video.baidu.com>视 频</a></div></td></tr></table> <table cellpadding=0 cellspacing=0 style="margin-left:15px"><tr valign=top><td style="height:62px;padding-left:92px" nowrap><div style="position:relative"><form name=f action=/s><input type=text name=wd id=kw size=42 maxlength=100> <input type=submit value=百度一下id=sb><div id=sug onselectstart="return false"></div><span id=hp><a href=/search/jiqiao.html>帮助</a><br><a href=/gaoji/advanced.html>高级</a></span></form></div></td></tr></table> </body>‘ select dbo.clearhtml (@mark) --3、运行结果 /* new --------------------------------------- 登录新闻网页贴吧知道MP3图片视频帮助高级 */ /* 但是上面的函数还存在问题,如果内容中有“《》”或是“<<>>”这样的标记,则不能达到我们的要求。 */ --加强版 create function [dbo].[clearhtml_V2] (@maco varchar(8000)) returns varchar(8000) as begin declare @randchar_one nvarchar(200) declare @randchar_two nvarchar(200) if(charindex(‘<<‘,@maco)>0) begin set @randchar_one=‘D4678B36-B958-4274-B81E-BBA636CFB427‘; set @randchar_two=‘49E374CC-9E1A-4850-897C-27074DE32E7F‘; set @maco=replace(@maco,‘<<‘,@randchar_one) set @maco=replace(@maco,‘>>‘,@randchar_two) end declare @i int while 1 = 1 begin set @i=len(@maco) set @maco=replace(@maco, substring(@maco,charindex(‘<‘,@maco), charindex(‘>‘,@maco)-charindex(‘<‘,@maco)+1),space(0)) if @i=len( @maco ) break end set @maco=replace(@maco,‘ ‘,‘‘) set @maco=replace(@maco,‘ ‘,‘‘) set @maco=ltrim(rtrim(@maco)) set @maco=replace(@maco,char(9),‘‘) set @maco=replace(@maco,char(10),‘‘) set @maco=replace(@maco,char(13),‘‘) if(charindex(@randchar_one,@maco)>0) begin set @maco=replace(@maco,‘D4678B36-B958-4274-B81E-BBA636CFB427‘,‘<<‘) set @maco=replace(@maco,‘49E374CC-9E1A-4850-897C-27074DE32E7F‘,‘>>‘) end return (@maco) end select dbo.clearhtml_V2(‘<p>aaaa</p><<本草纲目>><a href="www.baidu.com" />‘) --运行结果: /* aaaa<<本草纲目>> */ 特别说明:如果数据量比较大,尽量避免使用自定义函数,以免严重影响性能.
02、去除字符串中连续的分割符
--创建函数 create function [dbo].[m_delrepeatsplit] ( @str varchar(2000), @split nvarchar(200) ) returns nvarchar(2000) as begin --begin declare declare @count int,@i int,@isnull int declare @newchar nvarchar(200),@nn nvarchar(300) set @count=len(@str);set @i=1;set @isnull=1;set @nn=‘‘; --end declare --begin while while @i<@count+1 begin set @newchar=substring(@str,@i,1) if(@isnull=1) begin set @nn=@nn+@newchar; if(@newchar=@split) begin set @isnull=0; end else begin set @isnull=1; end end else begin if(@newchar=@split) begin set @isnull=0; end else begin set @nn=@nn+@newchar; set @isnull=1; end end set @i=@i+1; end --end while return @nn end --2、测试示例 declare @str nvarchar(200) set @str=‘1 2 3 4 555 6 7 7‘; declare @split nvarchar(200) set @split=‘ ‘; select dbo.m_delrepeatsplit(@str,@split) as newchar --3、运行结果 /* newchar ------------------ 2 3 4 555 6 7 7 */
03、求第一个字符串中第二个串的个数
--创建函数 create function [dbo].[m_count] ( @str_one nvarchar(200), --第一个字符串 @str_two nvarchar(200) --第二个字符串 ) returns int as begin declare @sqlcount int select @sqlcount=(len(@str_one)-len(replace(@str_one,@str_two,‘‘)))/len(@str_two) return @sqlcount end --测试示例 select dbo.m_count(‘sqlserver‘,‘e‘) as [count] --运行结果 /* count ----------- */
04、综合模糊查询
--创建函数 create function [dbo].[m_fuzzyquery_v1] ( @str nvarchar(2000) ) returns nvarchar(2000) as begin declare @count int,@i int; declare @newchar nvarchar(200),@nn nvarchar(300),@hh nvarchar(200) set @count=len(@str);set @i=1;set @nn=‘‘; while @i<@count+1 begin set @newchar=substring(@str,@i,1)+‘%‘ set @nn=@nn+@newchar; set @i=@i+1; end set @hh=‘%‘+@nn return @hh end --测试数据 declare @table table (connect varchar(30)) insert into @table select ‘我爱程序‘ union all select ‘我的程序生活‘ union all select ‘绝对无聊的生活‘ union all select ‘活得好累‘ union all select ‘程序员的生活‘ union all select ‘序论‘ union all select ‘生机‘ union all select ‘生活杂志‘ union all select ‘我只是随便写写‘ union all select ‘真的是要来搜索的‘ union all select ‘程序员一生的活路‘ --普通的模糊查询 select * from @table where connect like ‘%程序生活%‘ --运行结果 /* connect ------------------------------ 我的程序生活 */ --应用函数查询 select * from @table where connect like ( select dbo.[m_fuzzyquery_v1](‘程序生活‘)) --运行结果 /* connect ------------------------------ 我的程序生活 程序员的生活 程序员一生的活路 */
05、将十进制转成十六进制
--创建函数 create function [dbo].[hex](@cardno int ) returns varchar (100) as begin declare @temp_mod int declare @i int declare @result varchar(100) declare @temp_x int declare @result_values int set @result=‘‘ set @i=1 set @temp_x=0 while @cardno>0 begin set @temp_mod=@cardno%16 set @cardno=@cardno/16 set @result=(case @temp_mod when 10 then ‘A‘ when 11 then ‘B‘ when 12 then ‘C‘ when 13 then ‘D‘ when 14 then ‘E‘ when 15 then ‘F‘ else ltrim(str(@temp_mod)) end )+@result end return @result end --测试示例 select [dbo].[hex](1808) as Hex --运行结果 /* Hex ---------- */ --第二版 /**************************** 整数转换成进制 作者:不得闲 QQ: 75492895 Email: appleak46@yahoo.com.cn ****************************/ go Create Function IntToHex(@IntNum int) returns varchar(16) as begin declare @Mods int,@res varchar(16) set @res=‘‘ while @IntNum <> 0 begin set @Mods =@IntNum % 16 if @Mods > 9 set @res = Char(Ascii(‘A‘)+@Mods-10)+@res else set @res = Cast(@Mods as varchar(4)) + @res set @IntNum = @IntNum/16 end return @res end --测试示例 select dbo.IntToHex(1808) --运行结果 /* */
06、求两个字符串中相同的汉字及字母的个数
--创建函数 create function [dbo].[funcomparestring] ( @stra nvarchar(200), @strb nvarchar(200) ) returns int as begin declare @strbase nvarchar(200) declare @rank int select @rank=0 if len(@stra)>len(@strb) select @rank=count(*) from funsplitchar(@strb) where item in(select item from funsplitchar(@stra)) else select @rank=count(*) from funsplitchar(@stra) where item in(select item from funsplitchar(@strb)) return @rank end go --创建第二种函数 create function [dbo].[funcomparestring_new] ( @stra nvarchar(200), @strb nvarchar(200) ) returns int as begin declare @strbase nvarchar(200) declare @rank int select @rank=0 if len(@stra)>len(@strb) select @rank=count(*) from funsplitchar(@strb) where item in(select distinct item from funsplitchar(@stra)) else select @rank=count(*) from ( select distinct * from funsplitchar(@stra) where item in(select distinct item from funsplitchar(@strb)) ) bb return @rank end --以上两个函数有什么不同呢?下面我用个例子来给大家说明一下: --测试示例 select [dbo].[funCompareString](‘中国Chinese之家‘,‘中国人是Chinese‘) --结果为:9 select [dbo].[funCompareString_new](‘中国Chinese之家‘,‘中国人是Chinese‘) --结果为:8 --在这两个字符串中,‘ese‘与‘ese‘的重复在第一个函数算个字符重复, --而在第二个函数中算个字符重复。 --也就是说在第二个函数中,多次相同的重复不累积计算例如ese中的e。
07、生成n位随机字符串
--1、借助newid() go --创建视图(因为在函数中无法直接使用newid()) create view vnewid as select newid() N‘MacoId‘; go --创建函数 create function getrandstr(@n int) returns varchar(max) as begin declare @i int set @i=ceiling(@n/32.00) declare @j int set @j=0 declare @k varchar(max) set @k=‘‘ while @j<@i begin select @k=@k+replace(cast(MacoId as varchar(36)),‘-‘,‘‘) from vnewid set @j=@j+1 end set @k=substring(@k,1,@n) return @k end --测试示例 select dbo.getrandstr(75) --运行结果 /* D185504AD09C4D5796F7016983E67414CEE25162EA9F43D195D43328A4CF01AC7C586521D8E */ --我们可以发现结果中的字母都是大写的,或是都是小写的。 --换种方法来写下: go --创建函数 create function [dbo].[m_rand](@mycount int) returns nvarchar(2000) as begin declare @maco_wang table (id varchar(1)) declare @maco_number int,@number int; declare @my_one nvarchar(max),@my_two nvarchar(max) set @my_one=‘‘;set @maco_number=0; set @number =48; while (@number>=48 and @number<=57) or (@number>=65 and @number<=90) or (@number>=97 and @number<=122) begin insert into @maco_wang select char(@number) set @number=@number+1; if(@number=58) begin set @number=65 end if(@number=91) begin set @number=97 end end while @maco_number<@mycount begin select @my_two=id from @maco_wang order by (select MacoId from dbo.m_macoview); set @my_one=@my_two+@my_one; set @maco_number=@maco_number+1; end return @my_one end --测试用例 select [dbo].[m_rand](75) --运行结果 /* 5nN0w4o4VOkjacB5so2uvCuw2ZRrnBhxEi4IcsEOHzBbStKmR1p8ASH4N4XaxhDoDEtkX8bZ0CR */
08、取出字符串中的汉字、字母或是数字
go --创建函数(得到字符串中的汉字) create function [dbo].[m_getchinese] ( @chinese nvarchar(max) ) returns varchar(100) as begin while patindex(‘%[^吖-咗]%‘,@chinese) > 0 begin set @chinese = stuff(@chinese,patindex(‘%[^吖-咗]%‘,@chinese),1,N‘‘); end return @chinese end go --创建函数(得到字符串中的字母) create function [dbo].[m_getstr](@maco varchar(100)) returns varchar(max) as begin while patindex(‘%[^a-z]%‘,@maco) > 0 begin set @maco=stuff(@maco,patindex(‘%[^a-z]%‘,@maco),1,‘‘) end return @maco end go --创建函数(得到字符串中的数字) create function [dbo].[m_getnumber] ( @mysql_one nvarchar(200) ) returns varchar(200) begin declare @mysql_two varchar(200) select @mysql_two= substring(@mysql_one,patindex(‘%[0-9.]%‘,@mysql_one),patindex(‘%[^0-9.]%‘,substring(@mysql_one,patindex(‘%[0-9.]%‘,@mysql_one), len(@mysql_one)-patindex(‘%[0-9.]%‘,@mysql_one)+1))-1) return @mysql_two; end --测试 select dbo.[m_getchinese](‘China2009中国HRB4-1v‘) select dbo.[m_getstr](‘China2009中国HRB4-1v‘) select dbo.[m_getnumber](‘China2009中国HRB4-1v‘) --运行结果 /* ----------- 中国 ----------- ChinaHRBv ----------- */ --说明一下 --上面这个取数字是可以取浮点型的 select dbo.[m_getnumber] (‘字段.456A(AA)A‘)--正常 select dbo.[m_getnumber] (‘CHinese2.1day‘)--正常 select dbo.[m_getnumber] (‘Name5.01From‘)--正常 select dbo.[m_getnumber] (‘9898Address‘)--正常 select dbo.[m_getnumber] (‘aaaaaForm2.3333‘)--错误 --修正函数 go /* 取出字符串中间的数字(第二版)*/ create function [dbo].[m_getnumberV2.0] ( @mysql_one nvarchar(200) ) returns varchar(200) begin declare @mysql_two varchar(200) declare @sql_one int declare @sql_two int select @sql_one= patindex(‘%[0-9.]%‘,@mysql_one) select @sql_two= patindex(‘%[^0-9.]%‘, substring(@mysql_one,patindex(‘%[0-9.]%‘,@mysql_one),len(@mysql_one)-patindex(‘%[0-9.]%‘,@mysql_one)+1)) if @sql_two=0 begin select @mysql_two= substring (@mysql_one,@sql_one,len(@mysql_one)+1-@sql_one) end else begin select @mysql_two=substring (@mysql_one,@sql_one,@sql_two-1) end return @mysql_two; end --测试示例 select dbo.[m_getnumberV2.0] (‘字段.456A(AA)A‘)--正常 select dbo.[m_getnumberV2.0] (‘CHinese2.1day‘)--正常 select dbo.[m_getnumberV2.0] (‘Name5.01From‘)--正常 select dbo.[m_getnumberV2.0] (‘9898Address‘)--正常 select dbo.[m_getnumberV2.0] (‘aaaaaForm2.3333‘)--正常
09、根据字符分割字符串的三种写法
go --创建函数(第一版) create function [dbo].[m_split](@c varchar(2000),@split varchar(2)) returns @t table(col varchar(200)) as begin while(charindex(@split,@c)<>0) begin insert @t(col) values (substring(@c,1,charindex(@split,@c)-1)) set @c = stuff(@c,1,charindex(@split,@c),‘‘) end insert @t(col) values (@c) return end --下面两种是在论坛看到高手们发的 go --创建函数(第二版)(fredrickhu(小F)) create function [dbo].[f_split](@s varchar(8000), @split varchar(10) ) returns table as return (select substring(@s,number,charindex(@split,@s+@split,number)-number)as col from master..spt_values where type=‘p‘ and number<=len(@s+‘a‘) and charindex(@split,@split+@s,number)=number) go --创建函数(第三版)(dawugui(爱新觉罗.毓华)) create function [dbo].[d_split] (@inputstr varchar(8000),@seprator varchar(10)) returns @temp table (a varchar(200)) as begin declare @i int set @inputstr = rtrim(ltrim(@inputstr)) set @i = charindex(@seprator, @inputstr) while @i >= 1 begin insert @temp values(left(@inputstr, @i - 1)) set @inputstr = substring(@inputstr, @i + 1, len(@inputstr) - @i) set @i = charindex(@seprator, @inputstr) end if @inputstr <> ‘/‘ insert @temp values(@inputstr) return end --测试示例 declare @sql varchar(20) set @sql=‘A,B,C,D,E‘ select * from dbo.m_split(@sql,‘,‘) select * from dbo.f_split(@sql,‘,‘) select * from dbo.d_split(@sql,‘,‘) --运行结果(结果是相同的) /* col --------- A B C D E */
10、将数字转换千分位分隔形式
--创建函数(原创:dobear_0922) create function [dbo].[getformatstring](@dec decimal(28,8), @n int) returns varchar(32) as begin declare @str varchar(32), @len int, @left varchar(32), @right varchar(32),@end varchar(32) if @n!=‘0‘ begin set @str= round(@dec,@n) select @left=left(@str,charindex(‘.‘,@str)-1),@len=len(@left)-2 while @len>1 begin select @left=stuff(@left,@len,0,‘,‘), @len=@len-3 end select @right=left(stuff(@str,1,charindex(‘.‘,@str),‘‘), @n),@len=4 while @len <=len(@right) begin select @right=stuff(@right,@len,0,‘,‘), @len=@len+4 end set @end= @left+‘.‘+@right end else begin set @str= round(@dec,@n) select @left=left(@str,charindex(‘.‘,@str)-1),@len=len(@left)-2 while @len>1 begin select @left=stuff(@left,@len,0,‘,‘), @len=@len-3 end select @right=left(stuff(@str,1,charindex(‘.‘,@str),‘‘), @n),@len=4 while @len <=len(@right) begin select @right=stuff(@right,@len,0,‘,‘), @len=@len+4 end set @end= @left end return @end end --测试示例 select [dbo].[getformatstring](2645433,2) --运行结果 /* 2,645,433.00 */ --如果小数点后面不需要处理的话,我们可以不用函数直接: select convert(varchar, convert(money, 2645433), 1) /* 2,645,433.00 */
11、取汉字首字母的两个函数
go --创建取汉字首字母函数(第一版) create function [dbo].[f_getpy_V1] (@str nvarchar(4000)) returns nvarchar(4000) as begin declare @word nchar(1),@py nvarchar(4000) set @py=‘‘ while len(@str)>0 begin set @word=left(@str,1) set @py = @py+ (case when unicode(@word) between 19968 and 19968+20901 then ( select top 1 py from ( select ‘a‘ as py, N‘驁‘ as word union all select ‘B‘,N‘簿‘ union all select ‘C‘,N‘錯‘ union all select ‘D‘,N‘鵽‘ union all select ‘E‘,N‘樲‘ union all select ‘F‘,N‘鰒‘ union all select ‘G‘,N‘腂‘ union all select ‘H‘,N‘夻‘ union all select ‘J‘,N‘攈‘ union all select ‘K‘,N‘穒‘ union all select ‘L‘,N‘鱳‘ union all select ‘M‘,N‘旀‘ union all select ‘N‘,N‘桛‘ union all select ‘O‘,N‘漚‘ union all select ‘P‘,N‘曝‘ union all select ‘Q‘,N‘囕‘ union all select ‘R‘,N‘鶸‘ union all select ‘S‘,N‘蜶‘ union all select ‘T‘,N‘籜‘ union all select ‘W‘,N‘鶩‘ union all select ‘X‘,N‘鑂‘ union all select ‘Y‘,N‘韻‘ union all select ‘Z‘,N‘咗‘ ) T where word>=@word collate Chinese_PRC_CS_AS_KS_WS order by py asc ) else @word end) set @str=right(@str,len(@str)-1) end return @PY end go --创建取汉字首字母函数(第二版) create function [dbo].[f_getpy_V2](@Str varchar(500)=‘‘) returns varchar(500) as begin declare @strlen int,@return varchar(500),@ii int declare @n int,@c char(1),@chn nchar(1) select @strlen=len(@str),@return=‘‘,@ii=0 set @ii=0 while @ii<@strlen begin select @ii=@ii+1,@n=63,@chn=substring(@str,@ii,1) if @chn>‘z‘ select @n = @n +1 ,@c = case chn when @chn then char(@n) else @c end from( select top 27 * from ( select chn = ‘吖‘ union all select ‘八‘ union all select ‘嚓‘ union all select ‘咑‘ union all select ‘妸‘ union all select ‘发‘ union all select ‘旮‘ union all select ‘铪‘ union all select ‘丌‘ --because have no ‘i‘ union all select ‘丌‘ union all select ‘咔‘ union all select ‘垃‘ union all select ‘嘸‘ union all select ‘拏‘ union all select ‘噢‘ union all select ‘妑‘ union all select ‘七‘ union all select ‘呥‘ union all select ‘仨‘ union all select ‘他‘ union all select ‘屲‘ --no ‘u‘ union all select ‘屲‘ --no ‘v‘ union all select ‘屲‘ union all select ‘夕‘ union all select ‘丫‘ union all select ‘帀‘ union all select @chn) as a order by chn COLLATE Chinese_PRC_CI_AS ) as b else set @c=‘a‘ set @return=@return+@c end return(@return) end --测试示例 select dbo.[f_getpy_V1](‘王立国‘) as V11 select dbo.[f_getpy_V2](‘王立国‘) as V21 select dbo.[f_getpy_V1](‘重复‘) as V21 select dbo.[f_getpy_V2](‘重复‘) as V22 --运行结果 /* V11 -------- WLG V21 -------- WLG V21 -------- ZF V22 -------- ZF */ --由上我们可以看到,两种方法都没有解决多音字的问题。
12、根据身份证得到生日函数
go --创建函数(函数来自csdn,作者不详) create function [dbo].[Get_birthday] ( @idcardno nvarchar(50) ) returns varchar(10) as begin declare @birthday datetime if (len(@idcardno)=15 or len(@idcardno)=16) and substring(@idcardno,9,2) between 1 and 12 and substring(@idcardno,11,2) between 1 and 31 set @birthday= convert(varchar(10),‘19‘+substring(@idcardno,7,2)+‘-‘+substring(@idcardno,9,2)+‘-‘+substring(@idcardno,11,2),120) else if len(@idcardno)=18 and substring(@idcardno,7,2)>=19 and substring(@idcardno,11,2) between 1 and 12 and substring(@idcardno,13,2) between 1 and 31 set @birthday= convert(varchar(10),substring(@idcardno,7,4)+‘-‘+substring(@idcardno,11,2)+‘-‘+substring(@idcardno,13,2),120) else set @birthday=null return(convert(varchar(10),@birthday,120)) end --测试示例 select dbo.[Get_birthday](‘222222198306043213‘) --运行结果 /* 1983-06-04 */
13、根据身份证计算性别函数
Go --创建函数(函数来自csdn,作者不详) create function [dbo].[Get_sex] ( @idcardno nvarchar(50) ) returns int as begin declare @sex int if (len(@idcardno)=18 and isnumeric(substring(@idcardno,17,1))=1 ) set @sex= (case when substring(@idcardno,17,1) in(1,3,5,7,9) then 1 when substring(@idcardno,17,1) in(2,4,6,7,0) then 2 else 0 end) else if (len(@idcardno)=15 and isnumeric(substring(@idcardno,15,1))=1 ) set @sex= (case when substring(@idcardno,15,1) in(1,3,5,7,9) then 1 when substring(@idcardno,15,1) in(2,4,6,7,0) then 2 else 0 end) else set @sex=0 return(@sex) end --测试示例 select dbo.[Get_sex](‘222222198306043213‘) --运行结果(1表示男0表示女) /* */
14、将身份证的15位号码升级为18位
go --创建函数(此函数来自于csdn,作者不详) create function [dbo].[id15to18] (@id15 char(15)) returns char(18) as begin declare @id18 char(18) declare @s1 as integer declare @s2 as integer declare @s3 as integer declare @s4 as integer declare @s5 as integer declare @s6 as integer declare @s7 as integer declare @s8 as integer declare @s9 as integer declare @s10 as integer declare @s11 as integer declare @s12 as integer declare @s13 as integer declare @s14 as integer declare @s15 as integer declare @s16 as integer declare @s17 as integer declare @s18 as integer set @s1=substring(@id15,1,1) set @s2=substring(@id15,2,1) set @s3=substring(@id15,3,1) set @s4=substring(@id15,4,1) set @s5=substring(@id15,5,1) set @s6=substring(@id15,6,1) set @s7=1 set @s8=9 set @s9=substring(@id15,7,1) set @s10=substring(@id15,8,1) set @s11=substring(@id15,9,1) set @s12=substring(@id15,10,1) set @s13=substring(@id15,11,1) set @s14=substring(@id15,12,1) set @s15=substring(@id15,13,1) set @s16=substring(@id15,14,1) set @s17=substring(@id15,15,1) set @s18=((@s1*7)+(@s2*9)+(@s3*10)+(@s4*5)+(@s5*8)+(@s6*4)+(@s7*2)+(@s8*1) +(@s9*6)+(@s10*3)+(@s11*7)+(@s12*9)+(@s13*10)+(@s14*5)+(@s15*8)+(@s16 *4)+(@s17*2))%11 set @id18=substring(@id15,1,6)+‘19‘+substring(@id15,7,9) +case when @s18=0 then ‘1‘ when @s18=1 then ‘0‘ when @s18=2 then ‘x‘ when @s18=3 then ‘9‘ when @s18=4 then ‘8‘ when @s18=5 then ‘7‘ when @s18=6 then ‘6‘ when @s18=7 then ‘5‘ when @s18=8 then ‘4‘ when @s18=9 then ‘3‘ when @s18=10 then ‘2‘ end return @id18 end --测试示例 select [dbo].[id15to18](‘222222830604321‘) --运行结果 /* */
15、通过身份证获得户籍
go --创建函数(此函数来自于csdn,作者不详) create function [dbo].[f_getcityfromcid] (@cid varchar(18)) returns varchar(50) as begin declare @acity varchar(1000) set @acity = ‘____,____,____,____,____,____,____,____,____,____,____,北京__,天津__,河北__,山西__,内蒙古_,____,____,____,____,____,辽宁__,吉林__,黑龙江_,____,____,____,____,____,____,____,上海__,江苏__,浙江__,安微__,福建__,江西__,山东__,____,____,____,河南__,湖北__,湖南__,广东__,广西__,海南__,____,____,____,重庆__,四川__,贵州__,云南__,西藏__,____,____,____,____,____,____,陕西__,甘肃__,青海__,宁夏__,新疆__,____,____,____,____,____,台湾__,____,____,____,____,____,____,____,____,____,香港__,澳门__,____,____,____,____,____,____,____,____,国外__,‘ select @acity=replace(@acity,‘ ‘,‘‘); set @cid = upper(@cid) if (len(@cid) <> 18 or patindex(‘%[^0-9x]%‘,@cid) > 0) return ‘这不是合法的身份证‘ if substring(@acity,cast(left(@cid,2) as int)* 5+1,4) = ‘‘ return ‘这身份证的地区码不存在‘ return ‘您的户籍是:‘+replace(substring(@acity,cast(left(@cid,2) as int)* 5+1,4),‘_‘,‘‘) end --测试示例 select dbo.[f_getcityfromcid](‘222222198306043213‘) --运行结果 /* 您的户籍是:吉林 */
16、多个数据项的字符串取指定位置字符
-- Author: happyflsytone -- Date:2008-11-05 14:59:34 -- 创建函数 create function [dbo].[split_str] ( @s varchar(8000), --包含多个数据项的字符串 @index int, --要获取的数据项的位置 @split varchar(10) --数据分隔符 ) returns varchar(100) as begin if @s is null return(null) begin declare @splitlen int select @splitlen=len(@split+‘A‘)-2 end while @index>1 and charindex(@split,@s+@split)>0 begin select @index=@index-1,@s=stuff(@s,1,charindex(@split,@s+@split)+@splitlen,‘‘) end return(isnull(left(@s,charindex(@split,@s+@split)-1),‘‘)) end --测试示例 select dbo.split_str(‘1-2-3-4‘,3,‘-‘) --运行结果 /* */
17、中缀算术转后缀算术表达式并计算的函数
--创建函数(原创:cson_cson) create function dbo.js(@bds varchar(1000)) returns float as begin declare @i int,@j int declare @c1 char(1),@c2 char(1),@c varchar(100) declare @v1 float,@v2 float,@v float declare @t table(id int identity(1,1),s varchar(100)) declare @s table(id int identity(1,1),s varchar(100)) declare @sv table(id int identity(1,1),v float) select @i = 0,@j = len(@bds),@c2 = ‘‘,@c = ‘‘ while @i<@j begin select @c1 = @c2,@i = @i+1 select @c2 = substring(@bds,@i,1) if charindex(@c2,‘.0123456789‘) > 0 or (@c2 = ‘-‘ and @c1 in(‘‘,‘*‘,‘-‘,‘+‘,‘/‘,‘(‘)) begin select @c = @c + @c2 continue end if @c <> ‘‘ begin insert @t(s) select @c select @c = ‘‘ end if charindex(@c2,‘)‘)>0 begin insert @t(s) select s from @s where id > isnull((select max(id) from @s where s in(‘(‘)),0) order by id desc delete @s where id >= isnull((select max(id) from @s where s in(‘(‘)),0) continue end if charindex(@c2,‘+-)‘)>0 begin insert @t(s) select s from @s where id > isnull((select max(id) from @s where s in(‘(‘)),0) order by id desc delete @s where id > isnull((select max(id) from @s where s in(‘(‘)),0) if @c2 <> ‘)‘ insert @s(s) select @c2 continue end if charindex(@c2,‘*/‘)>0 begin insert @t(s) select s from @s where id > isnull((select max(id) from @s where s in(‘(‘,‘+‘,‘-‘)),0) order by id desc delete @s where id > isnull((select max(id) from @s where s in(‘(‘,‘+‘,‘-‘)),0) insert @s select @c2 continue end if charindex(@c2,‘(‘)>0 insert @s select @c2 end if @c <> ‘‘ insert @t(s) select @c insert @t(s) select s from @s order by id desc select @i = 0,@j = max(id) from @t while @i < @j begin select @i = @i + 1 select @c = s from @t where id = @i if @c = ‘(‘ continue if @c not in(‘*‘,‘-‘,‘+‘,‘/‘) begin insert @sv(v) select convert(float,@c) continue end select @v2 = v from @sv delete @sv where id = (select max(id) from @sv) select @v1 = v from @sv delete @sv where id = (select max(id) from @sv) select @v = case @c when ‘+‘ then @v1 + @v2 when ‘-‘ then @v1 - @v2 when ‘*‘ then @v1 * @v2 when ‘/‘ then @v1 / @v2 end insert @sv(v) select @v end select @v = v from @sv return @v end --测试示例 declare @bds varchar(100) select @bds = ‘1+(2+3)*4-9‘ select dbo.js(@bds) as func --运行结果 /* func ---------------------- */
18、人民币小写金额转大写
--1、人民币小写金额转大写(第一版) ==================================================================== -- Title: 人民币小写金额转大写 -- Author: dobear Mail(MSN): dobear_0922@hotmail.com -- Environment: Vista + SQL2005 -- Date: 2008-06-12 -- Remark: dobear原创,转载请注明出处,有问题请发Mail告之 -- ==================================================================== go --创建函数 create function [dbo].[fn_getformatmoney] (@money numeric(14,2)) returns nvarchar(32) as begin declare @money_num nvarchar(20) --存储金额的字符形式 , @money_chn nvarchar(32) --存储金额的中文大写形式 , @n_chn nvarchar(1), @i int --临时变量 select @money_chn=case when @money>=0 then ‘‘ else ‘(负)‘ end , @money=abs(@money) , @money_num=stuff(str(@money, 15, 2), 13, 1, ‘‘) --加前置空格补齐到位(去掉小数点) , @i=patindex(‘%[1-9]%‘, @money_num) --找到金额最高位 while @i>=1 and @i<=14 begin set @n_chn=substring(@money_num, @i, 1) if @n_chn<>‘0‘ or (substring(@money_num,@i+1,1)<>‘0‘ and @i not in(4, 8, 12, 14)) --转换阿拉伯数字为中文大写形式 set @money_chn=@money_chn+substring(‘零壹贰叁肆伍陆柒捌玖‘, @n_chn+1, 1) if @n_chn<>‘0‘ or @i in(4, 8, 12) --添加中文单位 set @money_chn=@money_chn+substring(‘仟佰拾亿仟佰拾万仟佰拾圆角分‘,@i,1) set @i=@i+1 end set @money_chn=replace(@money_chn, ‘亿万‘, ‘亿‘) --当金额为x亿零万时去掉万 if @money=0 set @money_chn=‘零圆整‘ --当金额为零时返回‘零圆整‘ if @n_chn=‘0‘ set @money_chn=@money_chn+‘整‘ --当金额末尾为零分时以‘整‘结尾 return @money_chn --返回大写金额 end go --测试示例 select dbo.fn_getformatmoney(4545.44) --运行结果 /* 肆仟伍佰肆拾伍圆肆角肆分 */ --2、人民币小写金额转大写(第二版) /*编写者:(博客天地www.inbaidu.com ) 创建时间: 功能:小写金额转换成大写 参数:@LowerMoney 小写金额加上小数点最长可以保留位 输出:大写金额 简介:SQL版小写金额转换成大写金额(最多可以精确到小数点四位) 注: Decimal 数据类型最多可存储个数字 转载:请保留以上信息,谢谢!!! ********************************************************/ go --创建函数 create function [dbo].[lowertoupper](@lowermoney decimal(38,4)) returns varchar(200) --返回的大写金额的字符 as begin declare @lowerstr varchar(50) --小写金额 declare @upperstr varchar(200) --大写金额 declare @uppertmp varchar(15) --大写金额的临时字符串 declare @i int --递增量 declare @lowerlen int --小写金额的总长度 set @lowerstr = @lowermoney --把decimal型的值全部赋给字符串变量注:(赋值过去的话如在字符串变量中是显示.0000 因为小数位精确到四位,没有的话,它会自动补) set @lowerstr = replace(@lowerstr,‘.‘,‘‘) --把小数点替换成空字符 --精确到小数点的四位角分厘毫 set @lowerlen = len(@lowerstr) --获取小写金额的总长度(包括四个小数位) select @i = 1,@upperstr = ‘‘,@uppertmp = ‘‘ --设置默认初始值 while @i <= @lowerlen begin set @uppertmp = case when substring(@lowerstr,@lowerlen - @i + 1,1) = ‘0‘ and @i = 5 and (convert(int,right(@lowerstr,4)) = 0 or @lowerlen > 5) then ‘元‘ --注:如果个位为的话,并且四位小数都是或者它的长度超过(也就是超过元),则为元 --when substring(@lowerstr,@lowerlen - @i + 1,1) = ‘0‘ then ‘‘ else + case substring(@lowerstr,@lowerlen - @i + 1,1) --看当前位是数字几,就直接替换成汉字繁体大写 when ‘0‘ then ‘零‘ when ‘1‘ then ‘壹‘ when ‘2‘ then ‘贰‘ when ‘3‘ then ‘叁‘ when ‘4‘ then ‘肆‘ when ‘5‘ then ‘伍‘ when ‘6‘ then ‘陆‘ when ‘7‘ then ‘柒‘ when ‘8‘ then ‘捌‘ when ‘9‘ then ‘玖‘ end + case @i when 1 then ‘毫‘ when 2 then ‘厘‘ when 3 then ‘分‘ when 4 then ‘角‘ when 5 then ‘元‘ when 9 then ‘萬‘ when 13 then ‘亿‘ when 17 then ‘兆‘ when 21 then ‘京‘ when 25 then ‘垓‘ when 29 then ‘杼‘ when 33 then ‘穰‘ when 37 then ‘沟‘ --decimal型最大长度是后面的就不用再考虑了 else + case @i%4 when 2 then ‘拾‘ --拾10 14 18 22 26 30 34 38 ………… when 3 then ‘佰‘ --佰11 15 19 23 27 31 35 39 ………… when 0 then ‘仟‘ --仟12 16 20 24 28 32 36 40 ………… end end end set @upperstr = isnull(@uppertmp,‘‘) + isnull(@upperstr,‘‘) set @i = @i + 1 end if convert(int,right(@lowerstr,4)) = 0 set @upperstr = left(@upperstr,len(@upperstr)-8) + ‘整‘ --判断小数位数是不是都是,是就可以取整 while patindex(‘%零[仟佰拾角分厘毫零]%‘,@upperstr) <> 0 --把零拾或零佰或零零变成一个零 begin set @upperstr = stuff(@upperstr,patindex(‘%零[仟佰拾角分厘毫零]%‘,@upperstr),2,‘零‘) end while patindex(‘%[沟穰杼垓京兆亿萬]零[沟穰杼垓京兆亿萬]%‘,@upperstr) <> 0 --把零萬或零亿的清空掉 begin select @upperstr = stuff(@upperstr,patindex(‘%[沟穰杼垓京兆亿萬]零[沟穰杼垓京兆亿萬]%‘,@upperstr)+1,2,‘‘) end while patindex(‘%[仟佰拾]零[沟穰杼垓京兆亿萬]%‘,@upperstr) <> 0 --把类似拾零萬或佰零萬或仟零萬中间的零清空掉 begin select @upperstr = stuff(@upperstr,patindex(‘%[仟佰拾]零[沟穰杼垓京兆亿萬]%‘,@upperstr)+1,1,‘‘) end if patindex(‘%_零[元]%‘,@upperstr) <> 0 --把类似拾零元或百零元中间的零清空掉 begin select @upperstr = stuff(@upperstr,patindex(‘%_零[元]%‘,@upperstr) + 1,1,‘‘) end else if (patindex(‘零[元]%‘,@upperstr) <> 0) and (convert(int,right(@lowerstr,4)) <> 0) --判断当前否是零元开头,并且后面的四个小数不为 begin select @upperstr = stuff(@upperstr,patindex(‘零[元]%‘,@upperstr),2,‘‘) --把零元清空掉 end if right(@upperstr,1) = ‘零‘ set @upperstr = left(@upperstr,len(@upperstr)-1) --如果最后一位是零也清空掉 if @upperstr = ‘元整‘ set @upperstr = ‘零‘ + @upperstr --如果只是的话,就显示零元整 return @upperstr --返回大写金额 end --测试示例 Select dbo.LowerToUpper(120000000) --壹亿贰仟萬元整 Select dbo.LowerToUpper(102000000) --壹亿零贰佰萬元整 Select dbo.LowerToUpper(100200000) --壹亿零贰拾萬元整 Select dbo.LowerToUpper(100020000) --壹亿零贰萬元整 Select dbo.LowerToUpper(100002000) --壹亿贰仟元整 --运行结果 /* 壹亿贰仟萬元整 壹亿零贰佰萬元整 壹亿零贰拾萬元整 壹亿零贰萬元整 壹亿贰仟元整 */
19、向左填充指定字符串
go --创建函数(该函数来自csdn,作者不详) create function [dbo].[padleft] ( @str varchar(50), --需要填充的字符串 @totalwidth int, --填充后的长度 @paddingchar char(1)--填充使用的字符 ) returns varchar(1000) as begin declare @s varchar(100) set @s = @str if ( len(@str) < @totalwidth) begin declare @i int declare @strlen int declare @temp varchar(100) set @i = 1; set @strlen = @totalwidth - len(@str) set @temp = ‘‘; while(@i <= @strlen ) begin set @temp = @temp + @paddingchar; set @i = @i + 1; end set @s = @temp + @str end return (@s) end go --测试示例 declare @table table (id nvarchar(20)) insert into @table select ‘1‘ union all select ‘2‘ union all select ‘3‘ union all select ‘4‘ union all select ‘5‘ union all select ‘6‘ select dbo.padleft(id,2,‘0‘) as id from @table --运行结果 /* id ------- */ go --创建函数(第二版)(作者:maco_wang) create function padleftV2 ( @sql varchar(200), --需填充的字符串 @char varchar(4), --填充使用的字符 @len int --填充后的长度 ) returns varchar(200) as begin return (right(replicate(@char,@len)+@sql,@len)) end go --测试示例 declare @table table(id int) insert into @table(id) select 1 union all select 3 union all select 6 select dbo.padleftV2(cast(id as varchar),‘0‘,10) as id from @table --运行结果 /* id ------------- */
20、将整型数字转换为大写汉字
go --创建函数(该函数来自csdn,作者不详) create function [dbo].[m_NumToChinese](@num bigint) returns varchar(20) as begin declare @result varchar(20),@symbol varchar(2) if @num<0 select @symbol=‘负‘,@result=‘‘,@num=abs(@num) else select @symbol=‘‘,@result=‘‘ while @num<>0 select @result=substring(‘零壹贰叁肆伍陆柒捌玖拾‘,@num%10+1,1)+@result,@num=@num/10 return @symbol+@result end --测试示例 select dbo.[m_NumToChinese](12345678) --运行结果 /* 壹贰叁肆伍陆柒捌 */
21、检查给定串是否存在于由区间及点集的结合内
------------------------------------ -- Author: happyflystone -- Date:2009-07-20 -- Parameter: @CardString -- 被查询的串,形如:-13300001234,13300002230,13300002300 -- @CardNo 要查询的串 -- Return : int 0 -- 不存在于搜索串的范围内 -- 1 -- 存在于 -- 转载请注明出处。更多请访问:http://blog.csdn.net/happyflystone -- 原帖地址:http://blog.csdn.net/happyflystone/archive/2009/07/21/4365264.aspx ------------------------------------ --创建函数 Create function IsInCardString(@CardString varchar(8000),@CardNo varchar(11)) returns int as begin declare @temp table(a varchar(200)) declare @i int set @CardString = rtrim(ltrim(@CardString))+‘,‘ set @i = charindex(‘,‘, @CardString) while @i >= 1 begin insert @temp values(left(@CardString, @i - 1)) set @CardString = substring(@CardString, @i + 1, len(@CardString) - @i) set @i = charindex(‘,‘, @CardString) end if exists(select 1 from ( select case when charindex(‘-‘,a) > 0 then left(a,11) else a end as s, case when charindex(‘-‘,a) > 0 then right(a,11) else a end as e from @temp ) a where @CardNo between s and e) set @i= 1 else set @i= 0 return @i end go --测试示例 declare @CardString varchar(1000) set @CardString =‘13300000000-13300001234,13300002230,13300002300,13300002302,13300004101-13300004204,13300004212,13300004310‘ declare @CardNo varchar(1000) set @CardNo = ‘13300000001‘ --存在 select dbo.IsInCardString(@CardString,@CardNo) as result1 set @CardNo = ‘13300001235‘ --不存在 select dbo.IsInCardString(@CardString,@CardNo) as result2 --运行结果 /* result1 ----------- result2 ----------- */
22、根据日期返回星座
go --创建函数(CSDN fredrickhu(小F)提供) create function udf_GetStar (@ datetime) RETURNS varchar(100) -- 返回日期所属星座 BEGIN RETURN ( select max(star) from ( select ‘魔羯座‘ as star,1 as [month],1 as [day] union all select ‘水瓶座‘,1,20 union all select ‘双鱼座‘,2,19 union all select ‘牡羊座‘,3,21 union all select ‘金牛座‘,4,20 union all select ‘双子座‘,5,21 union all select ‘巨蟹座‘,6,22 union all select ‘狮子座‘,7,23 union all select ‘处女座‘,8,23 union all select ‘天秤座‘,9,23 union all select ‘天蝎座‘,10,24 union all select ‘射手座‘,11,22 union all select ‘魔羯座‘,12,22 ) stars where dateadd(month,[month] - 1,dateadd(year,year(@) - year(0),0)) + [day] - 1 = ( select max(dateadd(month,[month] - 1,dateadd(year,year(@) - year(0),0)) + [day] - 1) from ( select ‘魔羯座‘ as star,1 as [month],1 as [day] union all select ‘水瓶座‘,1,20 union all select ‘双鱼座‘,2,19 union all select ‘牡羊座‘,3,21 union all select ‘金牛座‘,4,20 union all select ‘双子座‘,5,21 union all select ‘巨蟹座‘,6,22 union all select ‘狮子座‘,7,23 union all select ‘处女座‘,8,23 union all select ‘天秤座‘,9,23 union all select ‘天蝎座‘,10,24 union all select ‘射手座‘,11,22 union all select ‘魔羯座‘,12,22 ) stars where @ >= dateadd(month,[month] - 1,dateadd(year,year(@) - year(0),0)) + [day] - 1 ) ) end --测试示例 select dbo.udf_GetStar(‘2010-05-04‘) select dbo.udf_GetStar(‘2009-01-04‘) select dbo.udf_GetStar(‘2007-12-04‘) --运行结果 /* 金牛座 魔羯座 射手座 */
23、计算两个日期之间的工作日
go --创建函数(CSDN fredrickhu(小F)提供) CREATE FUNCTION f_WorkDay ( @dt_begin datetime, --计算的开始日期 @dt_end datetime --计算的结束日期 )RETURNS int AS BEGIN DECLARE @workday int,@i int,@bz bit,@dt datetime IF @dt_begin> @dt_end SELECT @bz=1,@dt=@dt_begin,@dt_begin=@dt_end,@dt_end=@dt ELSE SET @bz=0 SELECT @i=DATEDIFF(Day,@dt_begin,@dt_end)+1, @workday=@i/7*5, @dt_begin=DATEADD(Day,@i/7*7,@dt_begin) WHILE @dt_begin <=@dt_end BEGIN SELECT @workday=CASE WHEN (@@DATEFIRST+DATEPART(Weekday,@dt_begin)-1)%7 BETWEEN 1 AND 5 THEN @workday+1 ELSE @workday END, @dt_begin=@dt_begin+1 END RETURN(CASE WHEN @bz=1 THEN -@workday ELSE @workday END) END GO --测试示例 select dbo.f_WorkDay(‘2011-02-22‘,‘2011-03-14‘) as ‘工作日‘ --运行结果 /* 工作日 ----------- */
24、根据年月生成日历函数
go --创建函数(第一版)(作者:dobear_0922) create function fn_Calendar(@year int, @month int) returns nvarchar(max) as begin declare @result nvarchar(max), @Enter nvarchar(8) select @Enter = char(13)+char(10), @result = ‘ Sun Mon Tue Wed Thu Fri Sat‘ + @Enter --表头 declare @start datetime, @end datetime select @start = rtrim(@year)+‘-‘+rtrim(@month)+‘-1‘, @end = dateadd(mm, 1, @start) set @result = @result+replicate(‘ ‘, (datepart(dw, @start)+@@datefirst+6)%7) --第一行前面的空格 while datediff(d, @start, @end)>0 begin if (datepart(dw, @start)+@@datefirst)%7 = 1 select @result = @result+@Enter --是否换行 select @result = @result+right(‘ ‘+rtrim(day(@start)), 4), @start = dateadd(d, 1, @start) end return @result end go --测试示例 set datefirst 3 print dbo.fn_Calendar(2007, 12) select dbo.fn_Calendar(2007, 12) set datefirst 7 --运行结果 /* Sun Mon Tue Wed Thu Fri Sat 3 4 5 6 7 8 10 11 12 13 14 15 17 18 19 20 21 22 24 25 26 27 28 29 31 */ go --创建函数(第二版)(作者:libin_ftsafe) create function f_calendar(@year int,@month int) returns @t table(日varchar(4),一varchar(4),二varchar(4),三varchar(4),四varchar(4),五varchar(4),六varchar(4)) as begin declare @a table(id int identity(0,1),date datetime) insert into @a(date) select top 31 rtrim(@year)+‘-‘+rtrim(@month)+‘-1‘ from sysobjects update @a set date=dateadd(dd,id,date) insert into @t select max(case datepart(dw,date) when 7 then rtrim(day(date)) else ‘‘ end), max(case datepart(dw,date) when 1 then rtrim(day(date)) else ‘‘ end), max(case datepart(dw,date) when 2 then rtrim(day(date)) else ‘‘ end), max(case datepart(dw,date) when 3 then rtrim(day(date)) else ‘‘ end), max(case datepart(dw,date) when 4 then rtrim(day(date)) else ‘‘ end), max(case datepart(dw,date) when 5 then rtrim(day(date)) else ‘‘ end), max(case datepart(dw,date) when 6 then rtrim(day(date)) else ‘‘ end) from @a where month(date)=@month group by (case datepart(dw,date) when 7 then datepart(week,date)+1 else datepart(week,date) end) return end go --测试示例 set datefirst 1 select * from dbo.f_calendar(2007,12) --运行结果 /* 日 一 二 三 四 五 六 ---- ---- ---- ---- ---- ---- ---- 3 4 5 6 7 8 10 11 12 13 14 15 17 18 19 20 21 22 24 25 26 27 28 29 31 */
25、从第一个汉字开始分割字符串
go --创建函数 create function [dbo].[m_splitNchinese] ( @str_one nvarchar(100) ) returns @result table (colone nvarchar(20),coltwo nvarchar(20)) as begin insert @result select left(@str_one,patindex(‘%[^_@0-9a-z]%‘,@str_one)-1) , right(@str_one,len(@str_one)-patindex(‘%[^_@0-9a-z]%‘,@str_one)+1) return end --测试示例 select * from [dbo].[m_splitNchinese] (‘Chinese中国‘) --运行结果 /* colone coltwo -------------------- -------------------- Chinese 中国 */
26、过滤掉字符串中重复的字符
go --创建函数(此函数来自csdn,作者不详) create function [dbo].[m_distinctStr](@s varchar(max)) returns varchar(100) as begin if @s is null return(null) declare @new varchar(50),@index int,@temp varchar(50) while len(@s)>0 begin set @new=isnull(@new,‘‘)+left(@s,1) set @s=replace(@s,left(@s,1),‘‘) end return @new end --测试示例 select dbo.[m_distinctStr](‘Chinese‘) as str1 select dbo.[m_distinctStr](‘张三李四李四张三刘六‘) as str2 --运行结果结果 /* str1 --------- Chines str2 ------------ 张三李四刘六 */
27、根据日期得到星期的函数
--最直接的方式就是用case when判断,这里用表变量来处理的 go --创建函数 create function [dbo].[m_getweek](@date nvarchar(2000)) returns varchar(2000) AS begin declare @weekday nvarchar(300) declare @table table (id int ,weekday nvarchar(200)) insert into @table select 0,‘星期天‘ union select 1,‘星期一‘ union select 2,‘星期二‘ union select 3,‘星期三‘ union select 4,‘星期四‘ union select 5,‘星期五‘ union select 6,‘星期六‘ select @weekday=weekday from @table where id=(datepart(dw,@date)-1) return @weekday end --测试示例 select [dbo].[m_getweek](getdate()) as 星期 --今天的星期 /* 星期 -------- 星期六 */
28、根据年度判断是否是闰年
--创建函数 create function [dbo].[fn_IsLeapYear] ( @year int ) returns varchar(14) as begin declare @returnvalue varchar(14) declare @setvalue int set @setvalue=datepart(mm,dateadd(dd,1,cast((cast(@year as varchar(4))+ ‘0228‘) as datetime))) if(@setvalue=2) set @returnvalue=‘闰年‘ else set @returnvalue=‘非闰年‘ return (cast (@year as varchar(8))+‘年:‘+@returnvalue) end go --测试示例 select dbo.[fn_IsLeapYear] (year(getdate())) select dbo.[fn_IsLeapYear] (2008) --运行结果 /* 2011年:非闰年 2008年:闰年 */
29、完善SQL农历转换函数
-------------------------------------------------------------------- -- Author : 原著: 改编:htl258(Tony) -- Date : 2010-04-24 06:39:55 -- Version:Microsoft SQL Server 2008 (RTM) - 10.0.1600.22 (Intel X86) -- Jul 9 2008 14:43:34 -- Copyright (c) 1988-2008 Microsoft Corporation -- Developer Edition on Windows NT 5.1 <X86> (Build 2600: Service Pack 3) -- Blog : http://blog.csdn.net/htl258 -- 原帖地址: -- http://blog.csdn.net/htl258/archive/2010/04/24/5523183.aspx -- Subject: 完善SQL农历转换函数(显示中文格式,加入润月的显示) -------------------------------------------------------------------------- --注:由于找一时找不到原版作者,所以暂未填入。大家有知道的告知一下,谢谢! --创建基础数据表 if object_id(‘SolarData‘) is not null drop table SolarData go create table SolarData ( yearid int not null, data char(7) not null, dataint int not null ) --插入数据 insert into SolarData select 1900,‘0x04bd8‘,19416 union all select 1901,‘0x04ae0‘,19168 union all select 1902,‘0x0a570‘,42352 union all select 1903,‘0x054d5‘,21717 union all select 1904,‘0x0d260‘,53856 union all select 1905,‘0x0d950‘,55632 union all select 1906,‘0x16554‘,91476 union all select 1907,‘0x056a0‘,22176 union all select 1908,‘0x09ad0‘,39632 union all select 1909,‘0x055d2‘,21970 union all select 1910,‘0x04ae0‘,19168 union all select 1911,‘0x0a5b6‘,42422 union all select 1912,‘0x0a4d0‘,42192 union all select 1913,‘0x0d250‘,53840 union all select 1914,‘0x1d255‘,119381 union all select 1915,‘0x0b540‘,46400 union all select 1916,‘0x0d6a0‘,54944 union all select 1917,‘0x0ada2‘,44450 union all select 1918,‘0x095b0‘,38320 union all select 1919,‘0x14977‘,84343 union all select 1920,‘0x04970‘,18800 union all select 1921,‘0x0a4b0‘,42160 union all select 1922,‘0x0b4b5‘,46261 union all select 1923,‘0x06a50‘,27216 union all select 1924,‘0x06d40‘,27968 union all select 1925,‘0x1ab54‘,109396 union all select 1926,‘0x02b60‘,11104 union all select 1927,‘0x09570‘,38256 union all select 1928,‘0x052f2‘,21234 union all select 1929,‘0x04970‘,18800 union all select 1930,‘0x06566‘,25958 union all select 1931,‘0x0d4a0‘,54432 union all select 1932,‘0x0ea50‘,59984 union all select 1933,‘0x06e95‘,28309 union all select 1934,‘0x05ad0‘,23248 union all select 1935,‘0x02b60‘,11104 union all select 1936,‘0x186e3‘,100067 union all select 1937,‘0x092e0‘,37600 union all select 1938,‘0x1c8d7‘,116951 union all select 1939,‘0x0c950‘,51536 union all select 1940,‘0x0d4a0‘,54432 union all select 1941,‘0x1d8a6‘,120998 union all select 1942,‘0x0b550‘,46416 union all select 1943,‘0x056a0‘,22176 union all select 1944,‘0x1a5b4‘,107956 union all select 1945,‘0x025d0‘,9680 union all select 1946,‘0x092d0‘,37584 union all select 1947,‘0x0d2b2‘,53938 union all select 1948,‘0x0a950‘,43344 union all select 1949,‘0x0b557‘,46423 union all select 1950,‘0x06ca0‘,27808 union all select 1951,‘0x0b550‘,46416 union all select 1952,‘0x15355‘,86869 union all select 1953,‘0x04da0‘,19872 union all select 1954,‘0x0a5d0‘,42448 union all select 1955,‘0x14573‘,83315 union all select 1956,‘0x052d0‘,21200 union all select 1957,‘0x0a9a8‘,43432 union all select 1958,‘0x0e950‘,59728 union all select 1959,‘0x06aa0‘,27296 union all select 1960,‘0x0aea6‘,44710 union all select 1961,‘0x0ab50‘,43856 union all select 1962,‘0x04b60‘,19296 union all select 1963,‘0x0aae4‘,43748 union all select 1964,‘0x0a570‘,42352 union all select 1965,‘0x05260‘,21088 union all select 1966,‘0x0f263‘,62051 union all select 1967,‘0x0d950‘,55632 union all select 1968,‘0x05b57‘,23383 union all select 1969,‘0x056a0‘,22176 union all select 1970,‘0x096d0‘,38608 union all select 1971,‘0x04dd5‘,19925 union all select 1972,‘0x04ad0‘,19152 union all select 1973,‘0x0a4d0‘,42192 union all select 1974,‘0x0d4d4‘,54484 union all select 1975,‘0x0d250‘,53840 union all select 1976,‘0x0d558‘,54616 union all select 1977,‘0x0b540‘,46400 union all select 1978,‘0x0b5a0‘,46496 union all select 1979,‘0x195a6‘,103846 union all select 1980,‘0x095b0‘,38320 union all select 1981,‘0x049b0‘,18864 union all select 1982,‘0x0a974‘,43380 union all select 1983,‘0x0a4b0‘,42160 union all select 1984,‘0x0b27a‘,45690 union all select 1985,‘0x06a50‘,27216 union all select 1986,‘0x06d40‘,27968 union all select 1987,‘0x0af46‘,44870 union all select 1988,‘0x0ab60‘,43872 union all select 1989,‘0x09570‘,38256 union all select 1990,‘0x04af5‘,19189 union all select 1991,‘0x04970‘,18800 union all select 1992,‘0x064b0‘,25776 union all select 1993,‘0x074a3‘,29859 union all select 1994,‘0x0ea50‘,59984 union all select 1995,‘0x06b58‘,27480 union all select 1996,‘0x055c0‘,21952 union all select 1997,‘0x0ab60‘,43872 union all select 1998,‘0x096d5‘,38613 union all select 1999,‘0x092e0‘,37600 union all select 2000,‘0x0c960‘,51552 union all select 2001,‘0x0d954‘,55636 union all select 2002,‘0x0d4a0‘,54432 union all select 2003,‘0x0da50‘,55888 union all select 2004,‘0x07552‘,30034 union all select 2005,‘0x056a0‘,22176 union all select 2006,‘0x0abb7‘,43959 union all select 2007,‘0x025d0‘,9680 union all select 2008,‘0x092d0‘,37584 union all select 2009,‘0x0cab5‘,51893 union all select 2010,‘0x0a950‘,43344 union all select 2011,‘0x0b4a0‘,46240 union all select 2012,‘0x0baa4‘,47780 union all select 2013,‘0x0ad50‘,44368 union all select 2014,‘0x055d9‘,21977 union all select 2015,‘0x04ba0‘,19360 union all select 2016,‘0x0a5b0‘,42416 union all select 2017,‘0x15176‘,86390 union all select 2018,‘0x052b0‘,21168 union all select 2019,‘0x0a930‘,43312 union all select 2020,‘0x07954‘,31060 union all select 2021,‘0x06aa0‘,27296 union all select 2022,‘0x0ad50‘,44368 union all select 2023,‘0x05b52‘,23378 union all select 2024,‘0x04b60‘,19296 union all select 2025,‘0x0a6e6‘,42726 union all select 2026,‘0x0a4e0‘,42208 union all select 2027,‘0x0d260‘,53856 union all select 2028,‘0x0ea65‘,60005 union all select 2029,‘0x0d530‘,54576 union all select 2030,‘0x05aa0‘,23200 union all select 2031,‘0x076a3‘,30371 union all select 2032,‘0x096d0‘,38608 union all select 2033,‘0x04bd7‘,19415 union all select 2034,‘0x04ad0‘,19152 union all select 2035,‘0x0a4d0‘,42192 union all select 2036,‘0x1d0b6‘,118966 union all select 2037,‘0x0d250‘,53840 union all select 2038,‘0x0d520‘,54560 union all select 2039,‘0x0dd45‘,56645 union all select 2040,‘0x0b5a0‘,46496 union all select 2041,‘0x056d0‘,22224 union all select 2042,‘0x055b2‘,21938 union all select 2043,‘0x049b0‘,18864 union all select 2044,‘0x0a577‘,42359 union all select 2045,‘0x0a4b0‘,42160 union all select 2046,‘0x0aa50‘,43600 union all select 2047,‘0x1b255‘,111189 union all select 2048,‘0x06d20‘,27936 union all select 2049,‘0x0ada0‘,44448 GO --=============================================================== --创建农历日期函数 if object_id(‘fn_GetLunar‘) is not null drop function fn_GetLunar go create function dbo.fn_GetLunar(@solarday datetime) returns nvarchar(30) as begin declare @soldata int declare @offset int declare @ilunar int declare @i int declare @j int declare @ydays int declare @mdays int declare @mleap int declare @mleap1 int declare @mleapnum int declare @bleap smallint declare @temp int declare @year nvarchar(10) declare @month nvarchar(10) declare @day nvarchar(10) declare @chinesenum nvarchar(10) declare @outputdate nvarchar(30) set @offset=datediff(day,‘1900-01-30‘,@solarday) --确定农历年开始 set @i=1900 --set @offset=@soldata while @i<2050 and @offset>0 begin set @ydays=348 set @mleapnum=0 select @ilunar=dataint from solardata where yearid=@i --传回农历年的总天数 set @j=32768 while @j>8 begin if @ilunar & @j >0 set @ydays=@ydays+1 set @j=@j/2 end --传回农历年闰哪个月1-12 , 没闰传回0 set @mleap = @ilunar & 15 --传回农历年闰月的天数,加在年的总天数上 if @mleap > 0 begin if @ilunar & 65536 > 0 set @mleapnum=30 else set @mleapnum=29 set @ydays=@ydays+@mleapnum end set @offset=@offset-@ydays set @i=@i+1 end if @offset <= 0 begin set @offset=@offset+@ydays set @i=@i-1 end --确定农历年结束 set @year=@i --确定农历月开始 set @i = 1 select @ilunar=dataint from solardata where yearid=@year --判断那个月是润月 set @mleap = @ilunar & 15 set @bleap = 0 while @i < 13 and @offset > 0 begin --判断润月 set @mdays=0 if (@mleap > 0 and @i = (@mleap+1) and @bleap=0) begin--是润月 set @i=@i-1 set @bleap=1 set @mleap1= @mleap --传回农历年闰月的天数 if @ilunar & 65536 > 0 set @mdays = 30 else set @mdays = 29 end else --不是润月 begin set @j=1 set @temp = 65536 while @j<=@i begin set @temp=@temp/2 set @j=@j+1 end if @ilunar & @temp > 0 set @mdays = 30 else set @mdays = 29 end --解除润月 if @bleap=1 and @i= (@mleap+1) set @bleap=0 set @offset=@offset-@mdays set @i=@i+1 end if @offset <= 0 begin set @offset=@offset+@mdays set @i=@i-1 end --确定农历月结束 set @month=@i --确定农历日结束 set @day=ltrim(@offset) --输出日期 set @chinesenum=N‘〇一二三四五六七八九十‘ while len(@year)>0 select @outputdate=isnull(@outputdate,‘‘) + substring(@chinesenum,left(@year,1)+1,1) , @year=stuff(@year,1,1,‘‘) set @outputdate=@outputdate+N‘年‘ + case @mleap1 when @month then N‘润‘ else ‘‘ end if cast(@month as int)<10 set @outputdate=@outputdate + case @month when 1 then N‘正‘ else substring(@chinesenum,left(@month,1)+1,1) end else if cast(@month as int)>=10 set @outputdate=@outputdate + case @month when ‘10‘ then N‘十‘ when 11 then N‘十一‘ else N‘十二‘ end set @outputdate=@outputdate + N‘月‘ if cast(@day as int)<10 set @outputdate=@outputdate + N‘初‘ + substring(@chinesenum,left(@day,1)+1,1) else if @day between ‘10‘ and ‘19‘ set @outputdate=@outputdate + case @day when ‘10‘ then N‘初十‘ else N‘十‘+ substring(@chinesenum,right(@day,1)+1,1) end else if @day between ‘20‘ and ‘29‘ set @outputdate=@outputdate + case @day when ‘20‘ then N‘二十‘ else N‘廿‘ end + case @day when ‘20‘ then N‘‘ else substring(@chinesenum,right(@day,1)+1,1) end else set @outputdate=@outputdate+N‘三十‘ return @outputdate end GO --测试示例 select dbo.fn_GetLunar(getdate()) as [改编日期(农历)], getdate() as [改编日期(公历)] /* 改编日期(农历) 改编日期(公历) ------------------------------ ----------------------- 二〇一一年二月十六 2011-03-20 11:24:35.577 */ select convert(char(10),dateadd(d,number,‘2008-1-1‘),23) as 公历, dbo.fn_GetLunar(dateadd(d,number,‘2008-1-1‘)) as 农历 from master..spt_values where type=‘p‘ /* 公历 农历 ---------- ------------------------------ 2008-01-01 二〇〇七年十一月廿三 2008-01-02 二〇〇七年十一月廿四 2008-01-03 二〇〇七年十一月廿五 2008-01-04 二〇〇七年十一月廿六 2008-01-05 二〇〇七年十一月廿七 2008-01-06 二〇〇七年十一月廿八 2008-01-07 二〇〇七年十一月廿九 2008-01-08 二〇〇七年十二月初一 2008-01-09 二〇〇七年十二月初二 2008-01-10 二〇〇七年十二月初三 ............... 2013-07-31 二〇一三年六月廿四 2013-08-01 二〇一三年六月廿五 2013-08-02 二〇一三年六月廿六 2013-08-03 二〇一三年六月廿七 2013-08-04 二〇一三年六月廿八 2013-08-05 二〇一三年六月廿九 2013-08-06 二〇一三年六月三十 2013-08-07 二〇一三年七月初一 2013-08-08 二〇一三年七月初二 2013-08-09 二〇一三年七月初三 (2048 行受影响) */ --2048行记录:秒
30、SQL简繁转换函数
--原帖地址:http://blog.csdn.net/htl258/archive/2010/04/20/5506045.aspx
--全部的简繁对照
declare @jall nvarchar(4000),@fall nvarchar(4000)
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declare @j nvarchar(2000),@f nvarchar(2000)
select @j=‘皑蔼碍爱翱袄奥坝罢摆败颁办绊帮绑镑谤剥饱宝报鲍辈贝钡狈备惫绷笔毕毙币闭边编贬变辩辫标鳖别瘪濒滨宾摈饼并拨钵铂驳卜补财参蚕残惭惨灿苍舱仓沧厕侧册测层诧搀掺蝉馋谗缠铲产阐颤场尝长偿肠厂畅钞车彻尘沉陈衬撑称惩诚骋痴迟驰耻齿炽冲虫宠畴踌筹绸丑橱厨锄雏础储触处传疮闯创锤纯绰辞词赐聪葱囱从丛凑蹿窜错达带贷担单郸掸胆惮诞弹当挡党荡档捣岛祷导盗灯邓敌涤递缔颠点垫电淀钓调迭谍叠钉顶锭订丢东动栋冻斗犊独读赌镀锻断缎兑队对吨顿钝夺堕鹅额讹恶饿儿尔饵贰发罚阀珐矾钒烦范贩饭访纺飞诽废费纷坟奋愤粪丰枫锋风疯冯缝讽凤肤辐抚辅赋复负讣妇缚该钙盖干赶秆赣冈刚钢纲岗皋镐搁鸽阁铬个给龚宫巩贡钩沟构购够蛊顾剐关观馆惯贯广规硅归龟闺轨诡柜贵刽辊滚锅国过骇韩汉号阂鹤贺横轰鸿红后壶护沪户哗华画划话怀坏欢环还缓换唤痪焕涣黄谎挥辉毁贿秽会烩汇讳诲绘荤浑伙获货祸击机积饥讥鸡绩缉极辑级挤几蓟剂济计记际继纪夹荚颊贾钾价驾歼监坚笺间艰缄茧检碱硷拣捡简俭减荐槛鉴践贱见键舰剑饯渐溅涧将浆蒋桨奖讲酱胶浇骄娇搅铰矫侥脚饺缴绞轿较秸阶节茎鲸惊经颈静镜径痉竞净纠厩旧驹举据锯惧剧鹃绢杰洁结诫届紧锦仅谨进晋烬尽劲荆觉决诀绝钧军骏开凯颗壳课垦恳抠库裤夸块侩宽矿旷况亏岿窥馈溃扩阔蜡腊莱来赖蓝栏拦篮阑兰澜谰揽览懒缆烂滥捞劳涝乐镭垒类泪篱离里鲤礼丽厉励砾历沥隶俩联莲连镰怜涟帘敛脸链恋炼练粮凉两辆谅疗辽镣猎临邻鳞凛赁龄铃凌灵岭领馏刘龙聋咙笼垄拢陇楼娄搂篓芦卢颅庐炉掳卤虏鲁赂禄录陆驴吕铝侣屡缕虑滤绿峦挛孪滦乱抡轮伦仑沦纶论萝罗逻锣箩骡骆络妈玛码蚂马骂吗买麦卖迈脉瞒馒蛮满谩猫锚铆贸么霉没镁门闷们锰梦谜弥觅幂绵缅庙灭悯闽鸣铭谬谋亩钠纳难挠脑恼闹馁内拟腻撵捻酿鸟聂啮镊镍柠狞宁拧泞钮纽脓浓农疟诺欧鸥殴呕沤盘庞赔喷鹏骗飘频贫苹凭评泼颇扑铺朴谱栖凄脐齐骑岂启气弃讫牵扦钎铅迁签谦钱钳潜浅谴堑枪呛墙蔷强抢锹桥乔侨翘窍窃钦亲寝轻氢倾顷请庆琼穷趋区躯驱龋颧权劝却鹊确让饶扰绕热韧认纫荣绒软锐闰润洒萨鳃赛叁伞丧骚扫涩杀纱筛晒删闪陕赡缮伤赏烧绍赊摄慑设绅审婶肾渗声绳胜圣师狮湿诗尸时蚀实识驶势适释饰视试寿兽枢输书赎属术树竖数帅双谁税顺说硕烁丝饲耸怂颂讼诵擞苏诉肃虽随绥岁孙损笋缩琐锁獭挞抬态摊贪瘫滩坛谭谈叹汤烫涛绦讨腾誊锑题体屉条贴铁厅听烃铜统头秃图涂团颓蜕脱鸵驮驼椭洼袜弯湾顽万网韦违围为潍维苇伟伪纬谓卫温闻纹稳问瓮挝蜗涡窝卧呜钨乌污诬无芜吴坞雾务误锡牺袭习铣戏细虾辖峡侠狭厦吓锨鲜纤咸贤衔闲显险现献县馅羡宪线厢镶乡详响项萧嚣销晓啸蝎协挟携胁谐写泻谢锌衅兴汹锈绣虚嘘须许叙绪续轩悬选癣绚学勋询寻驯训讯逊压鸦鸭哑亚讶阉烟盐严颜阎艳厌砚彦谚验鸯杨扬疡阳痒养样瑶摇尧遥窑谣药爷页业叶医铱颐遗仪彝蚁艺亿忆义诣议谊译异绎荫阴银饮隐樱婴鹰应缨莹萤营荧蝇赢颖哟拥佣痈踊咏涌优忧邮铀犹游诱舆鱼渔娱与屿语吁御狱誉预驭鸳渊辕园员圆缘远愿约跃钥岳粤悦阅云郧匀陨运蕴酝晕韵杂灾载攒暂赞赃脏凿枣灶责择则泽贼赠扎札轧铡闸栅诈斋债毡盏斩辗崭栈战绽张涨帐账胀赵蛰辙锗这贞针侦诊镇阵挣睁狰争帧郑证织职执纸挚掷帜质滞钟终种肿众诌轴皱昼骤猪诸诛烛瞩嘱贮铸筑驻专砖转赚桩庄装妆壮状锥赘坠缀谆着浊兹资渍踪综总纵邹诅组钻‘
,@f=‘皚藹礙愛翺襖奧壩罷擺敗頒辦絆幫綁鎊謗剝飽寶報鮑輩貝鋇狽備憊繃筆畢斃幣閉邊編貶變辯辮標鼈別癟瀕濱賓擯餅並撥缽鉑駁蔔補財參蠶殘慚慘燦蒼艙倉滄廁側冊測層詫攙摻蟬饞讒纏鏟産闡顫場嘗長償腸廠暢鈔車徹塵沈陳襯撐稱懲誠騁癡遲馳恥齒熾沖蟲寵疇躊籌綢醜櫥廚鋤雛礎儲觸處傳瘡闖創錘純綽辭詞賜聰蔥囪從叢湊躥竄錯達帶貸擔單鄲撣膽憚誕彈當擋黨蕩檔搗島禱導盜燈鄧敵滌遞締顛點墊電澱釣調叠諜疊釘頂錠訂丟東動棟凍鬥犢獨讀賭鍍鍛斷緞兌隊對噸頓鈍奪墮鵝額訛惡餓兒爾餌貳發罰閥琺礬釩煩範販飯訪紡飛誹廢費紛墳奮憤糞豐楓鋒風瘋馮縫諷鳳膚輻撫輔賦複負訃婦縛該鈣蓋幹趕稈贛岡剛鋼綱崗臯鎬擱鴿閣鉻個給龔宮鞏貢鈎溝構購夠蠱顧剮關觀館慣貫廣規矽歸龜閨軌詭櫃貴劊輥滾鍋國過駭韓漢號閡鶴賀橫轟鴻紅後壺護滬戶嘩華畫劃話懷壞歡環還緩換喚瘓煥渙黃謊揮輝毀賄穢會燴彙諱誨繪葷渾夥獲貨禍擊機積饑譏雞績緝極輯級擠幾薊劑濟計記際繼紀夾莢頰賈鉀價駕殲監堅箋間艱緘繭檢堿鹼揀撿簡儉減薦檻鑒踐賤見鍵艦劍餞漸濺澗將漿蔣槳獎講醬膠澆驕嬌攪鉸矯僥腳餃繳絞轎較稭階節莖鯨驚經頸靜鏡徑痙競淨糾廄舊駒舉據鋸懼劇鵑絹傑潔結誡屆緊錦僅謹進晉燼盡勁荊覺決訣絕鈞軍駿開凱顆殼課墾懇摳庫褲誇塊儈寬礦曠況虧巋窺饋潰擴闊蠟臘萊來賴藍欄攔籃闌蘭瀾讕攬覽懶纜爛濫撈勞澇樂鐳壘類淚籬離裏鯉禮麗厲勵礫曆瀝隸倆聯蓮連鐮憐漣簾斂臉鏈戀煉練糧涼兩輛諒療遼鐐獵臨鄰鱗凜賃齡鈴淩靈嶺領餾劉龍聾嚨籠壟攏隴樓婁摟簍蘆盧顱廬爐擄鹵虜魯賂祿錄陸驢呂鋁侶屢縷慮濾綠巒攣孿灤亂掄輪倫侖淪綸論蘿羅邏鑼籮騾駱絡媽瑪碼螞馬罵嗎買麥賣邁脈瞞饅蠻滿謾貓錨鉚貿麽黴沒鎂門悶們錳夢謎彌覓冪綿緬廟滅憫閩鳴銘謬謀畝鈉納難撓腦惱鬧餒內擬膩攆撚釀鳥聶齧鑷鎳檸獰甯擰濘鈕紐膿濃農瘧諾歐鷗毆嘔漚盤龐賠噴鵬騙飄頻貧蘋憑評潑頗撲鋪樸譜棲淒臍齊騎豈啓氣棄訖牽扡釺鉛遷簽謙錢鉗潛淺譴塹槍嗆牆薔強搶鍬橋喬僑翹竅竊欽親寢輕氫傾頃請慶瓊窮趨區軀驅齲顴權勸卻鵲確讓饒擾繞熱韌認紉榮絨軟銳閏潤灑薩鰓賽三傘喪騷掃澀殺紗篩曬刪閃陝贍繕傷賞燒紹賒攝懾設紳審嬸腎滲聲繩勝聖師獅濕詩屍時蝕實識駛勢適釋飾視試壽獸樞輸書贖屬術樹豎數帥雙誰稅順說碩爍絲飼聳慫頌訟誦擻蘇訴肅雖隨綏歲孫損筍縮瑣鎖獺撻擡態攤貪癱灘壇譚談歎湯燙濤縧討騰謄銻題體屜條貼鐵廳聽烴銅統頭禿圖塗團頹蛻脫鴕馱駝橢窪襪彎灣頑萬網韋違圍爲濰維葦偉僞緯謂衛溫聞紋穩問甕撾蝸渦窩臥嗚鎢烏汙誣無蕪吳塢霧務誤錫犧襲習銑戲細蝦轄峽俠狹廈嚇鍁鮮纖鹹賢銜閑顯險現獻縣餡羨憲線廂鑲鄉詳響項蕭囂銷曉嘯蠍協挾攜脅諧寫瀉謝鋅釁興洶鏽繡虛噓須許敘緒續軒懸選癬絢學勳詢尋馴訓訊遜壓鴉鴨啞亞訝閹煙鹽嚴顔閻豔厭硯彥諺驗鴦楊揚瘍陽癢養樣瑤搖堯遙窯謠藥爺頁業葉醫銥頤遺儀彜蟻藝億憶義詣議誼譯異繹蔭陰銀飲隱櫻嬰鷹應纓瑩螢營熒蠅贏穎喲擁傭癰踴詠湧優憂郵鈾猶遊誘輿魚漁娛與嶼語籲禦獄譽預馭鴛淵轅園員圓緣遠願約躍鑰嶽粵悅閱雲鄖勻隕運蘊醞暈韻雜災載攢暫贊贓髒鑿棗竈責擇則澤賊贈紮劄軋鍘閘柵詐齋債氈盞斬輾嶄棧戰綻張漲帳賬脹趙蟄轍鍺這貞針偵診鎮陣掙睜猙爭幀鄭證織職執紙摯擲幟質滯鍾終種腫衆謅軸皺晝驟豬諸誅燭矚囑貯鑄築駐專磚轉賺樁莊裝妝壯狀錐贅墜綴諄著濁茲資漬蹤綜總縱鄒詛組鑽‘
--生成码表
create table codetable(gb nchar(1),big nchar(1))
select top 1298 id=identity(int,1,1) into #t from syscolumns a,syscolumns b
insert codetable
select substring(@j,id,1),substring(@f,id,1)
from #t
where id<=len(@j)
drop table #t
go
/*--简繁转换函数
利用编码对照表,实现简体-->繁体,繁体-->简体的转换
注意,转换函数使用的是unicode编码
--邹建.07--*/
IF NOT OBJECT_ID(‘[dbo].[f_GB2BIG]‘) IS NULL
DROP FUNCTION [dbo].[f_GB2BIG]
GO
CREATE FUNCTION f_GB2BIG(
@str nvarchar(4000), --要转换的字符串
@toBIG bit --转换标志,为,表示GB-->BIG,否则是BIG-->GB
)RETURNS nvarchar(4000)
AS
BEGIN
IF @toBIG=1
SELECT @str=REPLACE(@str,gb,big)
FROM codetable
WHERE CHARINDEX(gb,@str)>0
ELSE
SELECT @str=replace(@str,big,gb)
FROM codetable
WHERE charindex(big,@str)>0
RETURN(@str)
END
GO
--测试示例
--转换为繁体
select dbo.f_GB2BIG(‘我是中国人‘,1)
--转换为简体
select dbo.f_GB2BIG(‘我是中國人‘,0)
--运行结果
/*
我是中國人
我是中国人
*/
/*
本文来自CSDN博客,转载请标明出处:http://blog.csdn.net/htl258/archive/2010/04/20/5506045.aspx
*/
31、自定义函数实现位操作
--原帖地址:http://blog.csdn.net/Haiwer/archive/2007/07/21/1701476.aspx --问题: --比如两个字符串分别是‘000111011001‘和‘010011010011‘ --需要求他们的与,结果是000011010001 /************************************************/ /* 字符串与操作 */ /* 版本: 1.0 */ /* 作者: Haiwer */ /* 版权所有 */ /* 调用事例:select dbo.fn_and(‘000111011001‘,‘010011010011‘)*/ /* 2007.07.21整理 */ /************************************************/ go --创建函数 CREATE function [dbo].[fn_And]( @A1 varchar(300), @A2 varchar(300) ) returns varchar(300) as begin declare @r varchar(300) set @r=‘‘ while len(@A1) >0 begin set @r=@r+cast(cast(left(@A1,1) as tinyint) & cast(left(@A2,1) as tinyint) as varchar) set @A1=stuff(@A1,1,1,‘‘) set @A2=stuff(@A2,1,1,‘‘) end return @r end --测试示例 select dbo.fn_and(‘000111011001‘,‘010011010011‘) --运行结果 /* */ --问题:有表tab数据如下 /* m_test‘@table ID Val A 3 A 2 A 1 B 4 B 2 C 1 C 2 C 8 C 16 B 32‘ */ --求每个id的聚合或,要求的结果如下 /* ID Val A 3 --3 or 2 or 1 =3 B 38 --4 or 2 or 32=38 C 27 -- 1 or 2 or 8 or 16=27 */ go --创建测试数据 create table tab(ID varchar(1),Val int) insert into tab select ‘A‘,3 union all select ‘A‘,2 union all select ‘A‘,1 union all select ‘B‘,4 union all select ‘B‘,2 union all select ‘C‘,1 union all select ‘C‘,2 union all select ‘C‘,8 union all select ‘C‘,16 union all select ‘B‘,32 --用函数实现 /************************************************/ /* 聚合或操作函数 */ /* 版本: 1.0 */ /* 作者: Haiwer */ /* 版权所有 */ /* 调用事例: */ /* select id,[dbo].[fn_聚合或](id) as 聚合或from tab group by id */ /* 2007.07.21整理 */ /************************************************/ go --创建函数 create function [dbo].[fn_聚合或] ( @id varchar(10) ) returns int as begin declare @r int set @r=0 select @r=@r | val from tab where id=@id return @r end go --测试示例 select id,[dbo].[fn_聚合或](id) as 聚合或from tab group by id --运行结果 /* id 聚合或 ---- ----------- A 3 B 38 C 27 */ --本文来自CSDN博客 --转载请标明出处: --http://blog.csdn.net/Haiwer/archive/2007/07/21/1701476.aspx
32、求某段时间内星期几的天数
--原帖地址:http://blog.csdn.net/DengXingJie/archive/2011/02/25/6208762.aspx /* ********************************************** Program ID: FUN_GetDaysOfWeek Purpose : 求某段时间内某一星期日期的天数 Author : Jesse Date : 2011.02.19 ********************************************** */ go Create Function dbo.FUN_GetDaysOfWeek( @DateS smalldatetime,--开始时间 @DateE smalldatetime,--结束 @WeekValue int) --星期的某一天:-周日、-周一...7-周六 Returns nvarchar(100) As Begin declare @sResult nvarchar(100), --结果描述 @nResult int, --结果天数 @nWeekValue int, --起始日期是星期几(1-周日、-周一...7-周六) @nDays int, --时间段内的天数 @nBeforeDays int, --起始日期到第一次相符日期的天数 @sWeekName varchar(20), --所求日期的星期名称 @tmpDate smalldatetime set @WeekValue=@WeekValue % 7 if @WeekValue=0 set @WeekValue=7 --如果起始日期大于终止日期,则对换 if @DateS>@DateE select @tmpDate=@DateE,@DateE=@DateS,@DateS=@tmpDate --取得起始日期的星期数,与设置无关(1-周日、-周一...7-周六) select @nWeekValue=(Datepart(dw,@DateS)+(@@Datefirst %7))%7 if @nWeekValue=0 set @nWeekValue=7 set @sWeekName=DateName(dw,DateAdd(d,@WeekValue-@nWeekValue,@DateS)) if @WeekValue>=@nWeekValue set @nBeforeDays=@WeekValue-@nWeekValue else set @nBeforeDays=7-abs(@WeekValue-@nWeekValue) --取得时间段内的天数 select @nDays=Datediff(d,@DateS,@DateE)+1 if @nDays<@nBeforeDays select @nResult=0 else select @nResult=ceiling((@nDays-@nBeforeDays)/7.0) set @sResult=N‘日期区间:‘+ convert(varchar(10),@DateS,120)+ N‘ 到‘ +convert(varchar(10),@DateE,120) +‘ 之间‘ +@sWeekName +N‘ 共有‘+cast(@nResult as varchar(100))+N‘ 天‘ Return @sResult end go --测试示例 select dbo.FUN_GetDaysOfWeek(‘2011-03-01‘,‘2011-05-31‘,1) --运行结果 /* 日期区间:2011-03-01 到2011-05-31 之间Sunday 共有13 天 */
33、根据进舍位或四舍五入来求值
--原帖地址: --http://blog.csdn.net/DengXingJie/archive/2011/02/25/6208613.aspx /* *************************************** Program ID: FUN_GetValueByRoundMode Purpose : 根据进舍位或四舍五入来求值 Author : Jesse Date : 2011.02.14 *************************************** */ go --创建函数 Create function dbo.FUN_GetValueByRoundMode ( @Value decimal(18,6), --需进行运算的值 @Bit int, --小数位数 @RoundMode char(1)) --求值方式:-四舍五入、-舍去、-进位 Returns decimal(18,6) As begin declare @Result decimal(18,6) set @Value=isnull(@Value,0) if @RoundMode=‘1‘ --舍去 Select @Result=Round(@Value,@Bit,1) else if @RoundMode=‘2‘ --进位 Begin if @Value>Round(@Value,@Bit,1) --确保在有尾数的情况下才进位 Select @Result=Round(@Value,@Bit,1)+1.0/Power(10,@Bit) else Select @Result=Round(@Value,@Bit,1) end else Select @Result=Round(@Value,@Bit) Return Isnull(@Result,0) end --测试示例 select dbo.FUN_GetValueByRoundMode(9.82458,3,‘0‘) select dbo.FUN_GetValueByRoundMode(9.82458,3,‘1‘) select dbo.FUN_GetValueByRoundMode(9.82458,3,‘2‘) --运行结果 /* 9.825000 9.824000 9.825000 */
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Microsoft SQL Server 自定义函数整理大全
原文地址:http://rmlifejun.blog.51cto.com/7683304/1828648