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1、冒泡排序
public class BubbleSort{ public static void main(String[] args){ int score[] = {67, 69, 75, 87, 89, 90, 99, 100}; for (int i = 0; i < score.length -1; i++){ //最多做n-1趟排序 for(int j = 0 ;j < score.length - i - 1; j++){ //对当前无序区间score[0......length-i-1]进行排序(j的范围很关键,这个范围是在逐步缩小的) if(score[j] < score[j + 1]){ //把小的值交换到后面 int temp = score[j]; score[j] = score[j + 1]; score[j + 1] = temp; } } System.out.print("第" + (i + 1) + "次排序结果:"); for(int a = 0; a < score.length; a++){ System.out.print(score[a] + "\t"); } System.out.println(""); } System.out.print("最终排序结果:"); for(int a = 0; a < score.length; a++){ System.out.print(score[a] + "\t"); } } }
2、折半查找
public class BinarySearch { /** * 二分查找算法 * * @param srcArray 有序数组 * @param key 查找元素 * @return key的数组下标,没找到返回-1 */ public static void main(String[] args) { int srcArray[] = {3,5,11,17,21,23,28,30,32,50,64,78,81,95,101}; System.out.println(binSearch(srcArray, 0, srcArray.length - 1, 81)); } // 二分查找递归实现 public static int binSearch(int srcArray[], int start, int end, int key) { int mid = (end - start) / 2 + start; if (srcArray[mid] == key) { return mid; } if (start >= end) { return -1; } else if (key > srcArray[mid]) { return binSearch(srcArray, mid + 1, end, key); } else if (key < srcArray[mid]) { return binSearch(srcArray, start, mid - 1, key); } return -1; } // 二分查找普通循环实现 public static int binSearch(int srcArray[], int key) { int mid = srcArray.length / 2; if (key == srcArray[mid]) { return mid; } int start = 0; int end = srcArray.length - 1; while (start <= end) { mid = (end - start) / 2 + start; if (key < srcArray[mid]) { end = mid - 1; } else if (key > srcArray[mid]) { start = mid + 1; } else { return mid; } } return -1; } }
计算中间位置使用:
int mid = (end - start) / 2 + start;
防止加法运算时可能导致的整数越界
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原文地址:http://www.cnblogs.com/Donnnnnn/p/5728780.html