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C语言实现井子格游戏

时间:2016-08-02 16:55:04      阅读:135      评论:0      收藏:0      [点我收藏+]

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C语言简单实现一个9宫格的井子格游戏,任意一方完成三连即获胜!

    int winner = 0;
    int player = 0;
    int col = 0;
    int row = 0;
    int choice = 0;
    char board[3][3] = {
        {1,2,3},
        {4,5,6},
        {7,8,9}
    };
    for (int i = 0; i < 9 && winner == 0; i++) {
        printf("\n\n");
        printf(" %c | %c | %c \n",board[0][0],board[0][1],board[0][2]);
        printf("---+---+---\n");
        printf(" %c | %c | %c \n",board[1][0],board[1][1],board[1][2]);
        printf("---+---+---\n");
        printf(" %c | %c | %c \n",board[2][0],board[2][1],board[2][2]);

        player = i % 2 + 1;
        do {
            printf("玩家%d请输入你要选择的位置来放置%c:",player,(player == 1)?X:Z);
            scanf("%d",&choice);
            col = --choice % 3;
            row = choice / 3;
        } while (choice < 0 || choice > 8 || board[row][col] > 57);
        board[row][col] = player == 1 ? X : Z;
        /****判断是否有人胜出*****/
        if ((board[0][0]==board[1][1]&&board[0][0]==board[2][2])  
||(board[0][2]==board[1][1]&&board[0][2]==board[2][0])) { winner = player; }else{ for (int i = 0; i < 3; i++) { if ((board[i][0]==board[i][1]&&board[i][0]==board[i][2])
||(board[0][i]==board[1][i]&&board[0][i]==board[2][i])) { winner = player; } } } } printf("\n\n"); printf(" %c | %c | %c \n",board[0][0],board[0][1],board[0][2]); printf("---+---+---\n"); printf(" %c | %c | %c \n",board[1][0],board[1][1],board[1][2]); printf("---+---+---\n"); printf(" %c | %c | %c \n",board[2][0],board[2][1],board[2][2]); printf("**********玩家%d赢了!!!**********\n\n",winner);

 

C语言实现井子格游戏

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原文地址:http://www.cnblogs.com/CrazySL/p/5729532.html

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