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在实现微信图片上传时,因为文件是一个文件,无法向字符串一样通过参数一样直接写在请求地址中,
我自己做了一个页面抓取了一下请求,自己用C#代码拼接了一个请求。
public string HttpUploadFile() { string url = "https://api.weixin.qq.com/cgi-bin/media/upload?access_token=****************&type=image"; #region 本地图片 string path = "E:\\110.jpg"; int pos = path.LastIndexOf("\\"); string fileName = path.Substring(pos + 1); FileStream fs = new FileStream(path, FileMode.Open, FileAccess.Read); byte[] bArr = new byte[fs.Length]; fs.Read(bArr, 0, bArr.Length); fs.Close(); #endregion #region 获取从表单中提交的图片 //var file = context.Request.Files[0]; //byte[] bArr = new byte[file.InputStream.Length]; //file.InputStream.Read(bArr, 0, bArr.Length); //file.InputStream.Close(); #endregion HttpWebRequest request = WebRequest.Create(url) as HttpWebRequest; request.Method = "POST"; string boundary = DateTime.Now.Ticks.ToString("X"); // 随机分隔线 request.ContentType = "multipart/form-data;charset=utf-8;boundary=" + boundary; byte[] itemBoundaryBytes = Encoding.UTF8.GetBytes("\r\n--" + boundary + "\r\n"); byte[] endBoundaryBytes = Encoding.UTF8.GetBytes("\r\n--" + boundary + "--\r\n"); //请求头部信息 StringBuilder sbHeader = new StringBuilder(string.Format("Content-Disposition:form-data;name=\"file\";filename=\"{0}\"\r\nContent-Type:application/octet-stream\r\n\r\n", fileName)); byte[] postHeaderBytes = Encoding.UTF8.GetBytes(sbHeader.ToString()); Stream postStream = request.GetRequestStream(); postStream.Write(itemBoundaryBytes, 0, itemBoundaryBytes.Length); postStream.Write(postHeaderBytes, 0, postHeaderBytes.Length); postStream.Write(bArr, 0, bArr.Length); postStream.Write(endBoundaryBytes, 0, endBoundaryBytes.Length); postStream.Close(); //发送请求并获取相应回应数据 HttpWebResponse response = request.GetResponse() as HttpWebResponse; Stream respStream = response.GetResponseStream(); StreamReader sw = new StreamReader(respStream, Encoding.UTF8); string str = sw.ReadToEnd(); return str; }
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原文地址:http://www.cnblogs.com/xinxinzhihuo/p/5732724.html