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Fragment中加载网页(WebView)监听Back键 ,实现返回上一页的功能

时间:2016-08-08 17:43:03      阅读:311      评论:0      收藏:0      [点我收藏+]

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首先创建一个抽象类BackHandledFragment,该类有一个抽象方法onBackPressed(),所有BackHandledFragment的子类在onBackPressed方法中处理各自对Back事件的消费逻辑。onBackPressed返回布尔值,宿主Activity将会根据该方法的返回值判断子Fragment是否有消费Back事件。此外,宿主FragmentActivity还会保持一份当前Fragment的引用,当用户按下Back键时,宿主Activity会判断当前Fragment是否需要消费该事件,如果没有Fragment消费才会自己消费。

public abstract class BackHandledFragment extends Fragment{

    protected BackHandledInterface mBackHandledInterface;

    /**
     * 所有继承BackHandledFragment的子类都将在这个方法中实现物理Back键按下后的逻辑
     * FragmentActivity捕捉到物理返回键点击事件后会首先询问Fragment是否消费该事件
     * 如果没有Fragment消息时FragmentActivity自己才会消费该事件
     */
    public abstract boolean onBackPressed();

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        if(!(getActivity() instanceof BackHandledInterface)){
            throw new ClassCastException("Hosting Activity must implement BackHandledInterface");
        }else{
            this.mBackHandledInterface = (BackHandledInterface)getActivity();
        }
    }

    @Override
    public void onStart() {
        super.onStart();
        //告诉FragmentActivity,当前Fragment在栈顶
        mBackHandledInterface.setSelectedFragment(this);
    }
}
宿主FragmentActivity需要实现BackHandledIntegerface,子Fragment会通过该接口告诉宿主FragmentActivity自己是当前屏幕可见的Fragment。

public interface BackHandledInterface {
    void setSelectedFragment(BackHandledFragment selectedFragment);
}

所以在Fragment的onCreate中会判断宿主FragmentActivity是否已继承了该接口。在Fragment的onStart()方法中就会调用该接口告诉宿主FragmentActivity自己是当前屏幕可见的Fragment。
宿主FragmentActivity就可以在onBackPressed()方法中对Back事件进行判断处理了。

public class MainActivity extends FragmentActivity implements BackHandledInterface{

	private BackHandledFragment mBackHandedFragment;
	private boolean hadIntercept;

	@Override
	public void setSelectedFragment(BackHandledFragment selectedFragment) {
		this.mBackHandedFragment = selectedFragment;
	}
	
	@Override
	public void onBackPressed() {
		if(mBackHandedFragment == null || !mBackHandedFragment.onBackPressed()){
			if(getSupportFragmentManager().getBackStackEntryCount() == 0){
				super.onBackPressed(); //退出
			}else{
				getSupportFragmentManager().popBackStack(); //fragment 出栈
			}
		}
	}
}

Fragment需要继承抽象类BackHandledFragment,并覆写抽象方法onBackPressed(),在抽象方法中判断WebView是否可以返回到之前打开的网页

public class WorkFragment extends BackHandledFragment {

    private WebView webView;
    private WebSettings webSettings;

    private String url = "https://www.baidu.com/";
    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {

        View view = inflater.inflate(R.layout.work_fragment,container,false);
        webView = (WebView)view.findViewById(R.id.workWebView);

        webSettings = webView.getSettings();
        webSettings.setJavaScriptEnabled(true);
        webSettings.setUseWideViewPort(true);
        webSettings.setLoadWithOverviewMode(true);

        webView.setWebViewClient(new MyWebViewClient());
        webView.loadUrl(url);

        return view;
    }

    private class MyWebViewClient extends WebViewClient {
        @Override
        public boolean shouldOverrideUrlLoading(WebView view, String url) {
            //    return super.shouldOverrideUrlLoading(view, url);
            view.loadUrl(url);
            return true;
        }

        @Override
        public void onReceivedError(WebView view, int errorCode,
                                    String description, String failingUrl) {
            //     super.onReceivedError(view, errorCode, description, failingUrl);
            //  Toast.makeText(this,"网页加载错误!",0).show();
        }
    }
    @Override
    public  boolean onBackPressed(){

        if(webView.canGoBack()){
            webView.goBack();
            Log.v("webView.goBack()", "webView.goBack()");
            return true;

        }else{
            Log.v("Conversatio退出","Conversatio退出");
            return false;
        }

    }

}



Fragment中加载网页(WebView)监听Back键 ,实现返回上一页的功能

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原文地址:http://blog.csdn.net/wei_chong_chong/article/details/52153615

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