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原题如下
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner scan =new Scanner(System.in); int n, m; while (scan.hasNext()) { n = scan.nextInt(); String c=scan.nextLine(); //m = scan.nextInt(); while(n!=0){ n--; String s=scan.nextLine(); int judge; if(s.matches("[a-z_A-Z][a-z_A-Z0-9]{0,}")) judge=1; else judge=0; if(judge==1) System.out.println("yes"); else System.out.println("no"); } } } }
这道水题主要有两点需要注意,一是读取空格的问题需要用到scan.nextLine();二是matches的用法
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原文地址:http://www.cnblogs.com/cwenliu/p/5752504.html