标签:数组
219. Contains Duplicate II
Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j]and the difference between i and j is at most k.
题目大意:
找到数组中两个相同元素,如果这两个元素的距离小于等于k,则返回true。如果任意两个相同元素的距离都大于k,或者没有两个元素是相同的,那么返回false。
代码如下:
class Solution {
public:
bool containsNearbyDuplicate(vector<int>& nums, int k) {
unordered_map<int ,int> myMap;
for(int i = 0;i < nums.size();i++)
{
if(myMap.find(nums[i]) == myMap.end())
{
myMap.insert(pair<int,int>(nums[i],i));
}
else
{
if(i - myMap[nums[i]] <= k)
{
return true;
}
else
myMap[nums[i]] = i;
}
}
return false;
}
};2016-08-12 01:54:29
本文出自 “做最好的自己” 博客,请务必保留此出处http://qiaopeng688.blog.51cto.com/3572484/1837133
leetCode 219. Contains Duplicate II 数组
标签:数组
原文地址:http://qiaopeng688.blog.51cto.com/3572484/1837133