标签:数组
189. Rotate Array
Rotate an array of n elements to the right by k steps.
For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4].
Note:
Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem.
题目大意:
将数组整体向右移动k位,多出来的移到数组前面。
思路:
用一个新数组来替换它即可。
代码如下:
class Solution {
public:
void rotate(vector<int>& nums, int k) {
if(k == 0 || nums.size() == 1 || nums.size() == 0)
return;
if(k > nums.size())
k = k % nums.size();
int i,count;
count = 0;
i = nums.size() - k;
vector<int> tmp;
while(count != nums.size() )
{
if(i >= nums.size() )
{
i -= nums.size();
}
tmp.push_back(nums[i]);
i++;
count++;
}
nums.swap(tmp);
}
};2016-08-12 01:09:11
本文出自 “做最好的自己” 博客,请务必保留此出处http://qiaopeng688.blog.51cto.com/3572484/1837128
标签:数组
原文地址:http://qiaopeng688.blog.51cto.com/3572484/1837128