协助开发导入库时,他提醒我,库里有存储过程的定义。我使用了--routines 的选项,可是导入时,出了问题:
1.提示无法创建该存储过程,原来是忘了打开 log_bin_trust_function_creators 变量,
set global log_bin_trust_function_creators=on; 后,成功创建,从服务器也需要此操作
才行,如果二进制日志是 ROW 的话,即使从上有此存储过程,也是不会调用的。
2.等到导入成功后,却又出现了无法调用的问题,搜索了 http://www.2cto.com/database/201403/288436.html 这篇文章,记录下此问题。
创建一个 definer 为 user_admin 的存储过程
mysql> DELIMITER // mysql> CREATE DEFINER=‘user_admin‘ PROCEDURE num1() -> BEGIN -> SELECT COUNT(id) FROM itopserver; -> END // Query OK, 0 rows affected, 1 warning (0.00 sec) mysql> DELIMITER ;
2. 创建一个用户,并赋于其 相关权限
mysql> create user user_itop identified by ‘123456‘; Query OK, 0 rows affected (0.00 sec) mysql> grant select,insert,delete,update on itop.* to ‘user_test‘@‘%‘; Query OK, 0 rows affected (0.00 sec) mysql> show grants for user_test@‘%‘; +---------------------------------------------------------------------+ | Grants for user_test@% | +---------------------------------------------------------------------+ | GRANT USAGE ON *.* TO ‘user_test‘@‘%‘ | | GRANT SELECT, INSERT, UPDATE, DELETE ON `itop`.* TO ‘user_test‘@‘%‘ | +---------------------------------------------------------------------+ 2 rows in set (0.00 sec)
3. 使用 user_test 连接 mysql 并执行刚才创建的 procedure
mysql> call num1; ERROR 1370 (42000): execute command denied to user ‘user_test‘@‘%‘ for routine ‘itop.num1‘
4. 这样看是权限的问题,因为只给了他操作表的方法。 增加其 itop 的 execute 权限
mysql> grant execute on itop.* to user_test@‘%‘; Query OK, 0 rows affected (0.00 sec) mysql> show grants for user_test@‘%‘; +----------------------------------------------------------------------------------------------------------+ | Grants for user_test@% | +----------------------------------------------------------------------------------------------------------+ | GRANT USAGE ON *.* TO ‘user_test‘@‘%‘ IDENTIFIED BY PASSWORD ‘*6BB4837EB74329105EE4568DDA7DC67ED2CA2AD9‘ | | GRANT SELECT, INSERT, UPDATE, DELETE, EXECUTE ON `itop`.* TO ‘user_test‘@‘%‘ | +----------------------------------------------------------------------------------------------------------+ 2 rows in set (0.00 sec)
5. 重新使用此用户连接 Mysql 执行刚才定义的存储过程
mysql> use itop; mysql> call num1(); ERROR 1449 (HY000): The user specified as a definer (‘user_admin‘@‘%‘) does not exist
现在可以调用该存储过程了,但是提示存储过程定义中的definer不存在,
原来仅仅是连接到MySQL服务器的用户具有执行存储过程的权限是远远不够的,
最终要通过存储过程定义中指定的definer来执行存储过程。
6. 说 user_admin 不存在,那就创建 user_admin 这个用户
mysql> grant select,insert,delete,update on itop.* to ‘user_admin‘@‘%‘ identified by ‘123456‘; Query OK, 0 rows affected (0.00 sec) mysql> show grants for user_admin@‘%‘; +-----------------------------------------------------------------------------------------------------------+ | Grants for user_admin@% | +-----------------------------------------------------------------------------------------------------------+ | GRANT USAGE ON *.* TO ‘user_admin‘@‘%‘ IDENTIFIED BY PASSWORD ‘*6BB4837EB74329105EE4568DDA7DC67ED2CA2AD9‘ | | GRANT SELECT, INSERT, UPDATE, DELETE ON `itop`.* TO ‘user_admin‘@‘%‘ | +-----------------------------------------------------------------------------------------------------------+ 2 rows in set (0.00 sec)
7. 重新使用 "user_test" 用户连接 Mysql 执行刚才定义的存储过程
mysql> use itop; mysql> call num1(); ERROR 1370 (42000): execute command denied to user ‘user_admin‘@‘%‘ for routine ‘itop.num1‘
8. 看来不仅仅是连接到MySQL服务器的用户需要具有存储过程上的执行权限,存储过程定义者同样需要该权限。
mysql> grant execute on itop.* to ‘user_admin‘@‘%‘; Query OK, 0 rows affected (0.00 sec) mysql> show grants for user_admin; +-----------------------------------------------------------------------------------------------------------+ | Grants for user_admin@% | +-----------------------------------------------------------------------------------------------------------+ | GRANT USAGE ON *.* TO ‘user_admin‘@‘%‘ IDENTIFIED BY PASSWORD ‘*6BB4837EB74329105EE4568DDA7DC67ED2CA2AD9‘ | | GRANT SELECT, INSERT, UPDATE, DELETE, EXECUTE ON `itop`.* TO ‘user_admin‘@‘%‘ | +-----------------------------------------------------------------------------------------------------------+ 2 rows in set (0.00 sec)
9. 重新使用 "user_test" 用户连接 Mysql 执行刚才定义的存储过程
mysql> use itop; mysql> call num1(); +-----------+ | COUNT(id) | +-----------+ | 372 | +-----------+ 1 row in set (0.00 sec) Query OK, 0 rows affected (0.00 sec)
可以执行了
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原文地址:http://beyondhf.blog.51cto.com/8953234/1838301