标签:
假设对图片上任意点(x,y),绕一个坐标点(rx0,ry0)逆时针旋转RotaryAngle角度后的新的坐标设为(x‘, y‘),有公式:
x‘= (x - rx0)*cos(RotaryAngle) + (y - ry0)*sin(RotaryAngle) + rx0 ;
y‘=-(x - rx0)*sin(RotaryAngle) + (y - ry0)*cos(RotaryAngle) + ry0 ;
/// <summary>
/// 对一个坐标点按照一个中心进行旋转
/// </summary>
/// <param name="center">中心点</param>
/// <param name="p1">要旋转的点</param>
/// <param name="angle">旋转角度,笛卡尔直角坐标</param>
/// <returns></returns>
private Point PointRotate(Point center, Point p1, double angle)
{
Point tmp = new Point();
double angleHude = angle * Math.PI / 180;/*角度变成弧度*/
double x1 = (p1.X - center.X) * Math.Cos(angleHude) + (p1.Y - center.Y ) * Math.Sin(angleHude) + center .X;
double y1 = -(p1.X - center.X) * Math.Sin(angleHude) + (p1.Y - center.Y) * Math.Cos(angleHude) + center.Y;
tmp.X = (int)x1;
tmp.Y = (int)y1;
return tmp;
}
标签:
原文地址:http://www.cnblogs.com/MachineVision/p/5778677.html