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配置Bean的细节
?尽量使用scope=”singleton”,不要使用prototype，因为这样对我们的性能影响较大
②如何给集合类型注入值
Java中主要的map,set,list / 数组
Collection col = new ArrayList();
col能够使用的方法（点出来的方法）取决于左边的数据类型
beans.xml
<?xml version="1.0" encoding="utf-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:tx="http://www.springframework.org/schema/tx" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd"> <bean id="department" class="com.litao.collection.Department"> <property name="name" value="财务部" /> <!-- 给数组注入值 --> <property name="empName"> <list> <value>小明</value> <value>小明小明</value> <value>小明小明小明小明</value> </list> </property> <!-- 给list注入值 list中可以有相同的对象 --> <property name="empList"> <list> <ref bean="emp1"/> <ref bean="emp2"/> <ref bean="emp2"/> <ref bean="emp2"/> <ref bean="emp2"/> </list> </property> <!-- 给set注入值 set中不能有相同的对象 --> <property name="empsets"> <set> <ref bean="emp1"/> <ref bean="emp2"/> <ref bean="emp2"/> <ref bean="emp2"/> <ref bean="emp2"/> <ref bean="emp2"/> </set> </property> <!-- 给map注入值 map中也不能有相同的对象，后面的会把前面的覆盖，map只要key一样就可以装配value对应的bean --> <property name="empMaps"> <map> <entry key="1" value-ref="emp1"></entry> <entry key="2" value-ref="emp2"></entry> <entry key="2" value-ref="emp2"></entry> </map> </property> </bean> <bean id="emp1" class="com.litao.collection.Employee"> <property name="name" value="北京" /> <property name="id" value="1" /> </bean> <bean id="emp2" class="com.litao.collection.Employee"> <property name="name" value="天津" /> <property name="id" value="2" /> </bean> </beans>
Employee.java
package com.litao.collection;
public class Employee {
private String name;
private int id;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
}
Department.java
package com.litao.collection;
import java.util.List;
import java.util.Map;
import java.util.Set;
public class Department {
private String name;
private String[] empName;
private List<Employee> empList;
private Set<Employee> empsets;
private Map<String,Employee> empMaps;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String[] getEmpName() {
return empName;
}
public void setEmpName(String[] empName) {
this.empName = empName;
}
public List<Employee> getEmpList() {
return empList;
}
public void setEmpList(List<Employee> empList) {
this.empList = empList;
}
public Set<Employee> getEmpsets() {
return empsets;
}
public void setEmpsets(Set<Employee> empsets) {
this.empsets = empsets;
}
public Map<String, Employee> getEmpMaps() {
return empMaps;
}
public void setEmpMaps(Map<String, Employee> empMaps) {
this.empMaps = empMaps;
}
}
App1.java
package com.litao.collection;
import java.util.Iterator;
import java.util.Map;
import java.util.Map.Entry;
import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;
public class App1 {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
ApplicationContext ac = new ClassPathXmlApplicationContext("com/litao/collection/beans.xml");
Department department = (Department)ac.getBean("department");
System.out.println(department.getName());
for (String emName : department.getEmpName()) {
System.out.println(emName);
}
System.out.println("************通过list集合取出数据**************");
for(Employee e: department.getEmpList()){
System.out.println("name=" + e.getName() + " " + e.getId());
}
//set取得时候不能保证顺序，list取时可以保证顺序
System.out.println("************通过set集合取出数据**************");
for(Employee e: department.getEmpsets()){
System.out.println("name=" + e.getName());
}
System.out.println("************通过map集合取出数据**************");
//1.用迭代器
Map<String,Employee> empmaps = department.getEmpMaps();
Iterator it = empmaps.keySet().iterator();
while (it.hasNext()) {
String key = (String)it.next();
//System.out.println(key);
Employee emp = empmaps.get(key);
System.out.println("key="+key+" "+emp.getName());
}
//2.最简洁的方法
for(Entry<String,Employee> entry1:department.getEmpMaps().entrySet()){
System.out.println(entry1.getKey() + " " + entry1.getValue().getName());
}
}
}
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原文地址：http://www.cnblogs.com/litao0505/p/5781093.html
