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(LeetCode)Happy Number -- 寻找快乐数

时间:2016-08-22 12:42:57      阅读:198      评论:0      收藏:0      [点我收藏+]

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Write an algorithm to determine if a number is "happy".

A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.

Example: 19 is a happy number

  • 12 + 92 = 82
  • 82 + 22 = 68
  • 62 + 82 = 100
  • 12 + 02 + 02 = 1

Credits:
Special thanks to @mithmatt and @ts for adding this problem and creating all test cases.

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解题分析:

题意就是寻找一个符合每一位的平方和相加最后等于 1 的数,被称为Happy Number.

方法一,循环判断,如果满足要求,则返回True,不满足,返回False, 判断循环的话,可以用Dict记录之前的,重复出现

视为循环,则返回False.

# -*- coding:utf-8 -*-
__author__ = 'jiuzhang'
class Solution(object):
    def isHappy(self, n):
        num_dict = {}
        while True:
            num_dict[n] = True
            sum = 0
            while(n > 0):
                sum += (n % 10) * (n % 10)
                n /= 10
            if sum == 1:
                return True
            elif sum in num_dict:
                return False
            else:
                n = sum


方法二 : 在方法一的基础上进行修改,先计算出100以下的Happy Number 。其余的在套用公式。

# -*- coding:utf-8 -*-
__author__ = 'jiuzhang'
'''
optimized code
'''
class Solution(object):
    def isHappy(self, n):
        happySet = set([1, 7, 10, 13, 19, 23, 28, 31, 32, 44, 49, 68, 70, 79, 82, 86, 91, 94, 97])
        while n > 99:
            n = sum([int(x) * int(x) for x in list(str(n))])
        return n in happySet



(LeetCode)Happy Number -- 寻找快乐数

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原文地址:http://blog.csdn.net/u012965373/article/details/52274844

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