1 # !/usr/bin/env python
2 # -*- coding:utf-8 -*-
3 import random
4
5 schr = [chr(s) for s in range(65,91)]
6 bchr = [chr(b) for b in range(97,123)]
7 num = [str(n) for n in range(0,10)]
8 signs = [‘!‘,‘@‘,‘#‘,‘$‘,‘%‘,‘^‘,‘&‘,‘*‘,‘(‘,‘)‘,‘+‘,‘-‘,‘_‘,‘=‘,‘<‘,‘>‘,‘`‘,‘|‘,‘[‘,‘]‘,‘{‘,‘}‘,‘?‘,‘/‘]
9 codes = schr + bchr + num + signs
10
11 def shuffle(codes):
12 for i in range(5):
13 random.shuffle(codes)
14 return codes
15
16 def get_code(codes):
17 codes = shuffle(codes)
18 rand_start = random.randint(0,len(codes)-12)
19 rand_end = rand_start + 12
20 return ‘‘.join(codes[rand_start:rand_end])
21
22 print get_code(codes)本文出自 “bobo的运维之路” 博客，转载请与作者联系！
python 利用random的shuffle洗牌方法生产1个12位数的随机密码
原文地址：http://shiyiguo.blog.51cto.com/4949751/1843548
