Python：元组

tup1 = (‘physics‘, ‘chemistry‘, 1997, 2000)
tup2 = (1, 2, 3, 4, 5 )
tup3 = "a", "b", "c", "d"
tup4 = （50,）

>>> L = (‘Google‘, ‘Taobao‘, ‘Runoob‘)
>>> L[2]
‘Runoob‘
>>> L[-2]
‘Taobao‘
>>> L[1:]
(‘Taobao‘, ‘Runoob‘)

tup1 = (12, 34.56)
tup2 = (‘abc‘, ‘xyz‘)
tup3 = tup1 + tup2
print (tup3)

输出结果为：
(12, 34.56, ‘abc‘, ‘xyz‘)

tup = (‘physics‘, ‘chemistry‘, 1997, 2000, hema)
del tup  #删除元组，元组中的元素是不能单独删除的！

len(tuple)   #计算元组元素个数
>>> tuple1 = (‘Google‘, ‘Runoob‘, ‘Taobao‘)
>>> len(tuple1)
3
max(tuple)   #返回元组中元素最大值
min(tuple)   #返回元组中元素最小值
tuple(seq)   #将列表转换为元组
>>> list1= [‘Google‘, ‘Taobao‘, ‘Runoob‘, ‘Baidu‘]
>>> tuple1=tuple(list1)
>>> tuple1
(‘Google‘, ‘Taobao‘, ‘Runoob‘, ‘Baidu‘)