Leetcode 69. Sqrt(x) 求整数根 in Java

public class Solution {
    public int mySqrt(int x) {
        if(x==1) return 1;
        
        //注意此题返回值int，和sqrt返回值double不同
        double low=0;
        double high=x;
        
        while(low<high){
            double mid=(low+high)/2;
            
            if(Math.abs(mid*mid-x)<0.01){
             return (int)mid;
            }else if(mid*mid<x){
                low=mid;
            }else{
                high=mid;
            }
            
        }
        return (int)low;
    }
}