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Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 3148 Accepted Submission(s): 1549
1 /*树状数组模板题,若在区间a,b内开花则从a开始向上+1,从b开始向上-1,最后输出 2 某一点的值即可。*/ 3 #include<iostream> 4 #include<string> 5 #include<cstdio> 6 #include<cmath> 7 #include<cstring> 8 #include<algorithm> 9 #include<vector> 10 #include<iomanip> 11 #include<queue> 12 #include<stack> 13 using namespace std; 14 int t,n,m; 15 int A[100005]; 16 int lowbit(int x) 17 { 18 return x&(-x); 19 } 20 void add(int rt,int c) 21 { 22 while(rt<=100005) 23 { 24 A[rt]+=c; 25 rt+=lowbit(rt); 26 } 27 } 28 int sum(int rt) 29 { 30 int s=0; 31 while(rt>0) 32 { 33 s+=A[rt]; 34 rt-=lowbit(rt); 35 } 36 return s; 37 } 38 int main() 39 { 40 int a,b,c; 41 scanf("%d",&t); 42 for(int i=1;i<=t;i++) 43 { 44 memset(A,0,sizeof(A)); 45 printf("Case #%d:\n",i); 46 scanf("%d%d",&n,&m); 47 while(n--) 48 { 49 scanf("%d%d",&a,&b); 50 add(a,1); 51 add(b+1,-1); 52 } 53 while(m--) 54 { 55 scanf("%d",&c); 56 printf("%d\n",sum(c)); 57 } 58 } 59 return 0; 60 }
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原文地址:http://www.cnblogs.com/--ZHIYUAN/p/5877111.html