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3027 - Corporative Network

时间:2016-10-04 20:54:09      阅读:256      评论:0      收藏:0      [点我收藏+]

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3027 - Corporative Network

思路:并查集;

cost记录当前点到根节点的距离,每次合并时路径压缩将cost更新。

 1 #include<stdio.h>
 2 #include<algorithm>
 3 #include<iostream>
 4 #include<string.h>
 5 #include<math.h>
 6 #include<stack>
 7 #include<set>
 8 #include<queue>
 9 using namespace std;
10 int   bin[20005];
11 int   du[20005];
12 char str[20];
13 int main(void)
14 {
15         int i,j;
16         int n;
17         scanf("%d",&n);
18         while(n--)
19         {
20                 int m;
21                 scanf("%d",&m);
22                 for(i = 1; i <= 20005; i++)
23                         bin[i] = i,du[i] = 0;
24                 while(scanf("%s",str),str[0]!=O)
25                 {
26                         int x,y;
27                         if(str[0]==I)
28                         {
29                                 scanf("%d %d",&x,&y);
30                                 int xx;
31                                 for(xx = y; bin[xx]!=xx;)
32                                 {
33                                         xx = bin[xx];
34                                         du[y]+=du[xx];
35                                 }
36                                 bin[y] = xx;
37                                 bin[x] = xx;
38                                 du[x] = du[y]+abs(x-y)%1000;
39                         }
40                         else
41                         {      int sum = 0;
42                                 int xx;scanf("%d",&x);
43                                 for(xx = x; bin[xx]!=xx;)
44                                 {
45                                         xx=bin[xx],du[x]+=du[xx];
46                                 }
47                                 bin[x] = xx;
48                                 printf("%d\n",du[x]);
49                         }
50                 }
51         }
52         return 0;
53 }

 

3027 - Corporative Network

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原文地址:http://www.cnblogs.com/zzuli2sjy/p/5931103.html

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