码迷,mamicode.com
首页 > 数据库 > 详细

Oracle数据库中scott用户不存在的解决方法

时间:2016-10-30 23:57:18      阅读:660      评论:0      收藏:0      [点我收藏+]

标签:tin   primary   to_date   对象   manager   解决   存在   模式   base   

SCOTT用户是我们学习Oracle过程中一个非常重要的实验对象,在我们建立数据库的时候,如果是选择定制模式的话,SCOTT用户是不会默认出现的,不过我们可以通过使用几个简单命令来使这个用户出现。以下是解决方法(基于windows):

     1.开始——运行——cmd
       输入:sqlplus / as sysdba 连接到数据库
       SQL>conn scott/tiger 如果scott不存在,会报ORA-01017的错误,并会断开连接
 
     2.我们以SYS用户重新连接
       SQL>conn sys/密码 as sysdba 
       然后在我们按照oracle的目录F:\oracle\product\10.2.0\db_1\RDBMS\ADMIN中(以我的这个目录为例)找到scott.sql的这个文件
       运行 SQL>@F:\oracle\product\10.2.0\db_1\RDBMS\ADMIN\scott.sql
       这样scott用户就被添加进来,默认密码是tiger
       SQL>conn scott/tiger 连接成功
       SQL>SHOW USER; 
       USER为“SCOTT”
     3.如果想修改scott的默认密码可以执行下面命令(先以sys权限登录:sqlplus / as sysdba)
       修改scott的登录密码
       SQL> alter user scott identified by gg;你再拿scott/gg来登录就可以了
     4.如果scott.sql文件不存在的话,我们可以自己手动建一个。
       新建文本文档将以下内容复制到文件中,然后保存为scott.sql,放到2中的文件夹中,再按照2中的步骤
Rem Copyright (c) 1990 by Oracle Corporation
Rem NAME
REM    UTLSAMPL.SQL
Rem  FUNCTION
Rem  NOTES
Rem  MODIFIED
Rem gdudey   06/28/95 -  Modified for desktop seed database
Rem glumpkin   10/21/92 -  Renamed from SQLBLD.SQL
Rem blinden   07/27/92 -  Added primary and foreign keys to EMP and DEPT
Rem rlim   04/29/91 -      change char to varchar2
Rem mmoore   04/08/91 -      use unlimited tablespace priv
Rem pritto   04/04/91 -      change SYSDATE to 13-JUL-87
Rem   Mendels 12/07/90 - bug 30123;add to_date calls so language independent
Rem
rem
rem $Header: utlsampl.sql 7020100.1 94/09/23 22:14:24 cli Generic<base> $ sqlbld.sql
rem
SET TERMOUT OFF
SET ECHO OFF
 
rem CONGDON    Invoked in RDBMS at build time. 29-DEC-1988
rem OATES:     Created: 16-Feb-83
 
GRANT CONNECT,RESOURCE,UNLIMITED TABLESPACE TO SCOTT IDENTIFIED BY TIGER;
ALTER USER SCOTT DEFAULT TABLESPACE USERS;
ALTER USER SCOTT TEMPORARY TABLESPACE TEMP;
CONNECT SCOTT/TIGER
DROP TABLE DEPT;
CREATE TABLE DEPT
       (DEPTNO NUMBER(2) CONSTRAINT PK_DEPT PRIMARY KEY,
DNAME VARCHAR2(14) ,
LOC VARCHAR2(13) ) ;
DROP TABLE EMP;
CREATE TABLE EMP
       (EMPNO NUMBER(4) CONSTRAINT PK_EMP PRIMARY KEY,
ENAME VARCHAR2(10),
JOB VARCHAR2(9),
MGR NUMBER(4),
HIREDATE DATE,
SAL NUMBER(7,2),
COMM NUMBER(7,2),
DEPTNO NUMBER(2) CONSTRAINT FK_DEPTNO REFERENCES DEPT);
INSERT INTO DEPT VALUES
(10,‘ACCOUNTING‘,‘NEW YORK‘);
INSERT INTO DEPT VALUES (20,‘RESEARCH‘,‘DALLAS‘);
INSERT INTO DEPT VALUES
(30,‘SALES‘,‘CHICAGO‘);
INSERT INTO DEPT VALUES
(40,‘OPERATIONS‘,‘BOSTON‘);
INSERT INTO EMP VALUES
(7369,‘SMITH‘,‘CLERK‘,7902,to_date(‘17-12-1980‘,‘dd-mm-yyyy‘),800,NULL,20);
INSERT INTO EMP VALUES
(7499,‘ALLEN‘,‘SALESMAN‘,7698,to_date(‘20-2-1981‘,‘dd-mm-yyyy‘),1600,300,30);
INSERT INTO EMP VALUES
(7521,‘WARD‘,‘SALESMAN‘,7698,to_date(‘22-2-1981‘,‘dd-mm-yyyy‘),1250,500,30);
INSERT INTO EMP VALUES
(7566,‘JONES‘,‘MANAGER‘,7839,to_date(‘2-4-1981‘,‘dd-mm-yyyy‘),2975,NULL,20);
INSERT INTO EMP VALUES
(7654,‘MARTIN‘,‘SALESMAN‘,7698,to_date(‘28-9-1981‘,‘dd-mm-yyyy‘),1250,1400,30);
INSERT INTO EMP VALUES
(7698,‘BLAKE‘,‘MANAGER‘,7839,to_date(‘1-5-1981‘,‘dd-mm-yyyy‘),2850,NULL,30);
INSERT INTO EMP VALUES
(7782,‘CLARK‘,‘MANAGER‘,7839,to_date(‘9-6-1981‘,‘dd-mm-yyyy‘),2450,NULL,10);
INSERT INTO EMP VALUES
(7788,‘SCOTT‘,‘ANALYST‘,7566,to_date(‘13-JUL-87‘)-85,3000,NULL,20);
INSERT INTO EMP VALUES
(7839,‘KING‘,‘PRESIDENT‘,NULL,to_date(‘17-11-1981‘,‘dd-mm-yyyy‘),5000,NULL,10);
INSERT INTO EMP VALUES
(7844,‘TURNER‘,‘SALESMAN‘,7698,to_date(‘8-9-1981‘,‘dd-mm-yyyy‘),1500,0,30);
INSERT INTO EMP VALUES
(7876,‘ADAMS‘,‘CLERK‘,7788,to_date(‘13-JUL-87‘)-51,1100,NULL,20);
INSERT INTO EMP VALUES
(7900,‘JAMES‘,‘CLERK‘,7698,to_date(‘3-12-1981‘,‘dd-mm-yyyy‘),950,NULL,30);
INSERT INTO EMP VALUES
(7902,‘FORD‘,‘ANALYST‘,7566,to_date(‘3-12-1981‘,‘dd-mm-yyyy‘),3000,NULL,20);
INSERT INTO EMP VALUES
(7934,‘MILLER‘,‘CLERK‘,7782,to_date(‘23-1-1982‘,‘dd-mm-yyyy‘),1300,NULL,10);
DROP TABLE BONUS;
CREATE TABLE BONUS
(
ENAME VARCHAR2(10) ,
JOB VARCHAR2(9)  ,
SAL NUMBER,
COMM NUMBER
) ;
DROP TABLE SALGRADE;
CREATE TABLE SALGRADE
      ( GRADE NUMBER,
LOSAL NUMBER,
HISAL NUMBER );
INSERT INTO SALGRADE VALUES (1,700,1200);
INSERT INTO SALGRADE VALUES (2,1201,1400);
INSERT INTO SALGRADE VALUES (3,1401,2000);
INSERT INTO SALGRADE VALUES (4,2001,3000);
INSERT INTO SALGRADE VALUES (5,3001,9999);
COMMIT;
 
SET TERMOUT ON
SET ECHO ON

 

Oracle数据库中scott用户不存在的解决方法

标签:tin   primary   to_date   对象   manager   解决   存在   模式   base   

原文地址:http://www.cnblogs.com/zsq1993/p/6014333.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!