（转）面试题--JAVA中静态块、静态变量加载顺序详解

 1 public class Test {                         //1.第一步，准备加载类
 2 
 3     public static void main(String[] args) {
 4         new Test();                         //4.第四步，new一个类，但在new之前要处理匿名代码块        
 5     }
 6 
 7     static int num = 4;                    //2.第二步，静态变量和静态代码块的加载顺序由编写先后决定 
 8 
 9     {
10         num += 3;
11         System.out.println("b");           //5.第五步，按照顺序加载匿名代码块，代码块中有打印
12     }
13 
14     int a = 5;                             //6.第六步，按照顺序加载变量
15 
16     { // 成员变量第三个
17         System.out.println("c");           //7.第七步，按照顺序打印c
18     }
19 
20     Test() { // 类的构造函数，第四个加载
21         System.out.println("d");           //8.第八步，最后加载构造函数，完成对象的建立
22     }
23 
24     static {                              // 3.第三步，静态块，然后执行静态代码块，因为有输出，故打印a
25         System.out.println("a");
26     }
27 
28     static void run()                    // 静态方法，调用的时候才加载// 注意看，e没有加载
29     {
30         System.out.println("e");
31     }
32 }

1 public class Print {
2 
3      public Print(String s){
4          System.out.print(s + " ");
5      }
6  }

 1 public class Parent{
 2 
 3      public static Print obj1 = new Print("1");
 4 
 5      public Print obj2 = new Print("2");
 6 
 7      public static Print obj3 = new Print("3");
 8 
 9      static{
10          new Print("4");
11      }
12 
13      public static Print obj4 = new Print("5");
14 
15      public Print obj5 = new Print("6");
16 
17      public Parent(){
18          new Print("7");
19      }
20 
21  }

 1 public class Child extends Parent{
 2 
 3      static{
 4          new Print("a");
 5      }
 6 
 7      public static Print obj1 = new Print("b");
 8 
 9      public Print obj2 = new Print("c");
10 
11      public Child (){
12          new Print("d");
13      }
14 
15      public static Print obj3 = new Print("e");
16 
17      public Print obj4 = new Print("f");
18 
19      public static void main(String [] args){
20          Parent obj1 = new Child ();
21          Parent obj2 = new Child ();
22      }
23  }