标签:put rip roc blog function pre write cti heap
给出n和n个整数,希望你从小到大给他们排序
第一行一个正整数n
第二行n个用空格隔开的整数
输出仅一行,从小到大输出n个用空格隔开的整数
3
3 1 2
1 2 3
1<=n<=100000
大材小用,Heap模板
1 var
2 f:array [1..1000000] of longint;
3 a,i,n,len:longint;
4
5 procedure swap(var a,b:longint);
6 var x:longint;
7 begin
8 x:=a;a:=b;b:=x;
9 end;
10
11 procedure insert(a:longint);
12 var
13 x:longint;
14 begin
15 inc(len); f[len]:=a; x:=len;
16 while (x>>1>0) and (f[x>>1]>f[x]) do
17 begin
18 swap(f[x],f[x>>1]); x:=x>>1;
19 end;
20 end;
21
22 function get:longint;
23 var
24 x:longint;
25 begin
26 get:=f[1]; f[1]:=f[len]; dec(len); x:=1;
27 while (x<<1<=len) and ((f[x<<1]<f[x]) or (f[x]>f[x<<1+1])) do
28 begin
29 if (f[x<<1]<f[x<<1+1]) or (x<<1=len)
30 then begin swap(f[x],f[x<<1]);x:=x<<1; end
31 else begin swap(f[x],f[x<<1+1]);x:=x<<1+1; end;
32 end;
33 end;
34
35 begin
36 readln(n);
37 len:=0;
38 for i:=1 to n do
39 begin
40 read(a);
41 insert(a);
42 end;
43
44 for i:=1 to n do
45 write(get,‘ ‘);
46 writeln;
47 end.
学长写的模板
1 var 2 a,h:array[0..100001]of longint; 3 i,n,x,t,tmp:longint; 4 5 procedure put(x:longint); 6 var 7 now:longint; 8 begin 9 inc(t); h[t]:=x; now:=t; 10 while (now<>1)and(h[now]<h[now >> 1]) do 11 begin 12 tmp:=h[now]; h[now]:=h[now >> 1]; 13 h[now >> 1]:=tmp; now:=now >> 1; 14 end; 15 end; 16 17 function get:longint; 18 var 19 fa,son,now:longint; 20 begin 21 get:=h[1]; h[1]:=h[t]; dec(t); 22 fa:=1; 23 while fa << 1<=t do 24 begin 25 if (fa << 1=t)or(h[fa << 1]<h[fa << 1+1]) 26 then son:=fa << 1 else son:=fa << 1+1; 27 if h[son]>h[fa] then break; 28 tmp:=h[fa]; h[fa]:=h[son]; 29 h[son]:=tmp; fa:=son; 30 end; 31 end; 32 33 begin 34 readln(n); 35 for i:=1 to n do 36 begin read(x); put(x); end; 37 for i:=1 to n do write(get,‘ ‘); 38 writeln; 39 end.
标签:put rip roc blog function pre write cti heap
原文地址:http://www.cnblogs.com/raymondchen/p/6067668.html