标签:nbsp code image win har osi oat utc char
原地址https://www.zhihu.com/topic/19613730/top-answers
首先上一个动态的心
代码如下:
1 #include <stdio.h> 2 #include <math.h> 3 #include <windows.h> 4 #include <tchar.h> 5 6 float f(float x, float y, float z) { 7 float a = x * x + 9.0f / 4.0f * y * y + z * z - 1; 8 return a * a * a - x * x * z * z * z - 9.0f / 80.0f * y * y * z * z * z; 9 } 10 11 float h(float x, float z) { 12 for (float y = 1.0f; y >= 0.0f; y -= 0.001f) 13 if (f(x, y, z) <= 0.0f) 14 return y; 15 return 0.0f; 16 } 17 //跳动的心 18 int main() { 19 HANDLE o = GetStdHandle(STD_OUTPUT_HANDLE); 20 _TCHAR buffer[25][80] = { _T(‘ ‘) }; 21 _TCHAR ramp[] = _T(".:-=+*#%@"); 22 23 for (float t = 0.0f;; t += 0.1f) { 24 int sy = 0; 25 float s = sinf(t); 26 float a = s * s * s * s * 0.2f; 27 for (float z = 1.3f; z > -1.2f; z -= 0.1f) { 28 _TCHAR* p = &buffer[sy++][0]; 29 float tz = z * (1.2f - a); 30 for (float x = -1.5f; x < 1.5f; x += 0.05f) { 31 float tx = x * (1.2f + a); 32 float v = f(tx, 0.0f, tz); 33 if (v <= 0.0f) { 34 float y0 = h(tx, tz); 35 float ny = 0.01f; 36 float nx = h(tx + ny, tz) - y0; 37 float nz = h(tx, tz + ny) - y0; 38 float nd = 1.0f / sqrtf(nx * nx + ny * ny + nz * nz); 39 float d = (nx + ny - nz) * nd * 0.5f + 0.5f; 40 *p++ = ramp[(int)(d * 5.0f)]; 41 } 42 else 43 *p++ = ‘ ‘; 44 } 45 } 46 47 for (sy = 0; sy < 25; sy++) { 48 COORD coord = { 0, sy }; 49 SetConsoleCursorPosition(o, coord); 50 WriteConsole(o, buffer[sy], 79, NULL, 0); 51 } 52 Sleep(33); 53 } 54 }
代码:
1 #include <stdio.h> 2 #include <math.h> 3 4 float f(float x, float y, float z) { 5 float a = x * x + 9.0f / 4.0f * y * y + z * z - 1; 6 return a * a * a - x * x * z * z * z - 9.0f / 80.0f * y * y * z * z * z; 7 } 8 9 float h(float x, float z) { 10 for (float y = 1.0f; y >= 0.0f; y -= 0.001f) 11 if (f(x, y, z) <= 0.0f) 12 return y; 13 return 0.0f; 14 } 15 //3D黑白? 16 int main() { 17 for (float z = 1.5f; z > -1.5f; z -= 0.05f) { 18 for (float x = -1.5f; x < 1.5f; x += 0.025f) { 19 float v = f(x, 0.0f, z); 20 if (v <= 0.0f) { 21 float y0 = h(x, z); 22 float ny = 0.01f; 23 float nx = h(x + ny, z) - y0; 24 float nz = h(x, z + ny) - y0; 25 float nd = 1.0f / sqrtf(nx * nx + ny * ny + nz * nz); 26 float d = (nx + ny - nz) * nd * 0.5f + 0.5f; 27 putchar(".:-=+*#%@"[(int)(d * 5.0f)]); 28 } 29 else 30 putchar(‘ ‘); 31 } 32 putchar(‘\n‘); 33 } 34 getchar(); 35 }
标签:nbsp code image win har osi oat utc char
原文地址:http://www.cnblogs.com/dawenhao/p/6078890.html