标签：shc count ext current boolean sof turn style sse
为了防止用户误点退出键，很多应用都需要按两次退出键才会退出程序。下面介绍两种方法实现：
按照两次退出键的时间判断：
private long lastClickTime = 0; @Override public void onBackPressed() { if (lastClickTime <= 0) { Toast.makeText(this, "再按一次后退键退出应用", Toast.LENGTH_SHORT).show(); lastClickTime = System.currentTimeMillis(); } else { long currentClickTime = System.currentTimeMillis(); if (currentClickTime - lastClickTime < 2000){ finish(); } else { Toast.makeText(this, "再按一次后退键退出应用", Toast.LENGTH_SHORT).show(); lastClickTime = System.currentTimeMillis(); } }
按照是否连续点击退出键判断：
protected int mFinishCount = 0; @Override public boolean dispatchTouchEvent(MotionEvent ev) { mFinishCount = 0; return super.dispatchTouchEvent(ev); } @Override public void finish() { mFinishCount++; if (mFinishCount == 1) { Toast.makeText(this, "再按一次退出！", Toast.LENGTH_LONG).show(); } else if (mFinishCount == 2) { super.finish(); } }
标签：shc count ext current boolean sof turn style sse
原文地址：http://www.cnblogs.com/changchou/p/6212110.html
