标签：log employee 南京 牛津大学 逻辑 运算 turn lin pre
在student集合中插入一些数据
db.student.insert({
"学号":10010,
"姓名":"德莱文",
"年龄":26,
"地址":"淄博市"
});
var stuData1={
"学号":10020,
"姓名":"奥巴马",
"年龄":27,
"地址":"艾泽拉斯"
};
db.student.insert(stuData1);
var stuData2={
"学号":10030,
"姓名":"女枪",
"年龄":27,
"地址":"艾泽拉斯"
};
db.student.insert(stuData2);
var stuData3={
"学号":10050,
"姓名":"瑞雯",
"年龄":18,
"地址":"超神学院"
};
db.student.insert(stuData3);
插入数组（数据为json）
var stuData=[
{"姓名":"Anner","age":26},
{"姓名":"James","age":28},
{"姓名":"Allen","age":31},
{"姓名":"Smith","age":17}
];
db.student.insert(stuData);
插入insert()，用JavaScript操作
//添加1万条数据
for(var i=0;i<10000;i++){
db.student.insert({"vid":"www.oracle.com"+i+"line"});
};
查看数据
db.student.find();
●数据查询
示例1：查询学号为10020的记录
db.student.find({"学号":10020});
db.student.find({"学号":10020}).pretty();
示例2：不显示_id的查询
db.student.find({"学号":10020},{"_id":0});
●关系运算
> $gt
< $lt
>= $gte
<= $lte
!= $ne
= key:value $eq
定义一个员工信息集合
db.employee.drop();
db.employee.insert([
{"name":"Smith","age":25,"sex":"男","job":"教授","addr":"北京大学","cellphone":"17166660001"},
{"name":"Clark","age":29,"sex":"男","job":"讲师","addr":"燕京大学","cellphone":"17166660002"},
{"name":"Allen","age":28,"sex":"女","job":"主任","addr":"南京大学","cellphone":"17166660003"},
{"name":"Anner","age":15,"sex":"女","job":"宣传","addr":"东京大学","cellphone":"17166660004"},
{"name":"James","age":19,"sex":"男","job":"教务","addr":"西京大学","cellphone":"17166660005"}
]);
db.employee.find();
db.employee.find().pretty();
示例3：查询姓名为Anner的记录
db.employee.find({"name":"Anner"}).pretty();
示例4：查询性别为男的记录
db.employee.find({"sex":"男"}).pretty();
示例5：查询年龄大于19岁的记录
db.employee.find({"age":{"$gt":19}}).pretty();
示例6：查询年龄小于等于19岁的记录
db.employee.find({"age":{"$lte":19}}).pretty();
示例7：查询性别不是女的的记录
db.employee.find({"sex":{"$ne":"女"}}).pretty();
●逻辑运算
与 $and
或 $or
非 $not $nor
示例8：查询年龄在10~20之间的记录
db.employee.find({"age":{"$gt":10,"$lte":20}});
db.employee.find({"age":{"$gt":10,"$lte":20}}).pretty();
示例9：查询年龄不是19岁的记录
db.employee.find({"age":{"$ne":19}});
示例10：查询年龄大于19岁，或者性别为女的记录
db.employee.find({"age":{"$gt":19}},);
db.employee.find({"$or":[
{"age":{"$gt":19}},
{"sex":{"$eq":"女"}}
]});
示例11：对上一题求反
db.employee.find({"$nor":[
{"age":{"$gt":19}},
{"sex":{"$eq":"女"}}
]});
●模运算 "$mod"
示例12：求年龄mod27余1的记录，也就是28
db.employee.find({"age":{"$mod":[27,1]}});
●范围查询
$in $nin
示例13：查询姓名是Allen，Anner，James的记录
db.employee.find({"name":{"$in":["Allen","Anner","James"]}});
示例14：查询姓名不是Allen，Anner，James的记录
db.employee.find({"name":{"$nin":["Allen","Anner","James"]}})
构建一个集合 employee集合
db.employee.insert([
{"name":"Jones","age":31,"sex":"男","job":"技术员","addr":"哈佛大学","cellphone":"15166660001"},
{"name":"Blake","age":35,"sex":"男","job":"销售员","addr":"牛津大学","cellphone":"15166660002"},
{"name":"Martin","age":21,"sex":"男","job":"销售员","addr":"剑桥大学","cellphone":"15166660003"},
{"name":"Turner","age":25,"sex":"女","job":"后勤","addr":"北京大学","cellphone":"15166660004"},
{"name":"Miller","age":23,"sex":"女","job":"行政","addr":"南京大学","cellphone":"15166660005"}
]);
示例15：查询job不是"技术员"的记录
db.emp.find({"jod":{"$nin":["技术员"]}});
标签：log employee 南京 牛津大学 逻辑 运算 turn lin pre
原文地址：http://www.cnblogs.com/void-m/p/6258980.html
