java实现——008旋转数组的最小数字

 1 public class T008 {
 2     public static void main(String[] args) {
 3         int[] num = { 3, 4, 5, 1, 2 };
 4         System.out.println(min(num, 5));
 5     }
 6     public static int min(int num[], int len) {
 7         if (num == null || len <= 0) {
 8             System.out.println("invalid");
 9         }
10         int in1 = 0;
11         int in2 = len - 1;
12         int inm = in1;
13         while (num[in1] >= num[in2]) {
14             if (in2 - in1 == 1) {
15                 inm = in2;
16                 break;
17             }
18             inm = (in2 + in1) / 2;
19             if (num[in1] == num[inm] && num[in1] == num[in2])
20                 return minInOrder(num, in1, in2);
21             if (num[inm] >= num[in1]) {
22                 in1 = inm;
23             } else {
24                 in2 = inm;
25             }
26         }
27         return num[inm];
28     }
29 
30     public static int minInOrder(int num[], int in1, int in2) {
31         int result = num[in1];
32         for (int i = in1 + 1; i <= in2; i++) {
33             if (num[i] < result)
34                 result = num[i];
35         }
36         return result;
37     }
38 }