标签：stat person 百度网盘 color tin 处理 没有 json tps
本文中主要介绍JSONObject处理json数据时候的一些常用场景和方法。
（一）jar包下载
所需jar包打包下载百度网盘地址：https://pan.baidu.com/s/1c27Uyre
（二）常见场景及处理方法
1、解析简单的json字符串：
1 // 简单的json测试字符串 2 public static final String JSON_SIMPLE = "{‘name‘:‘tom‘,‘age‘:16}"; 3 4 JSONObject obj = JSONObject.fromObject(JSON_SIMPLE); 5 System.out.println("name is : " + obj.get("name")); 6 System.out.println("age is : " + obj.get("age"));
输出：
name is : tom
age is : 16
2、解析嵌套的json字符串：
1 // 嵌套的json字符串 2 public static final String JSON_MULTI = "{‘name‘:‘tom‘,‘score‘:{‘Math‘:98,‘English‘:90}}"; 3 JSONObject obj = JSONObject.fromObject(JSON_MULTI); 4 System.out.println("name is : " + obj.get("name")); 5 System.out.println("score is : " + obj.get("score")); 6 7 JSONObject scoreObj = (JSONObject) obj.get("score"); 8 System.out.println("Math score is : " + scoreObj.get("Math")); 9 System.out.println("English score is : " + scoreObj.get("English"));
输出：
name is : tom
score is : {"English":90,"Math":98}
Math score is : 98
English score is : 90
3、把bean对象转化成JSONObject对象：
Person、Info、Score类分别如下：（注：要定义成独立的三个public类，不能定义成内部类或非public类，否则会转换异常）
1 public class Person { 2 private String name; 3 4 private Info info; 5 6 public String getName() { 7 return name; 8 } 9 10 public void setName(String name) { 11 this.name = name; 12 } 13 14 public Info getInfo() { 15 return info; 16 } 17 18 public void setInfo(Info info) { 19 this.info = info; 20 } 21 22 @Override 23 public String toString() { 24 return "Person [name=" + name + ", info=" + info + "]"; 25 } 26 27 }
1 public class Info { 2 private int age; 3 private Score score; 4 5 public int getAge() { 6 return age; 7 } 8 9 public void setAge(int age) { 10 this.age = age; 11 } 12 13 public Score getScore() { 14 return score; 15 } 16 17 public void setScore(Score score) { 18 this.score = score; 19 } 20 21 @Override 22 public String toString() { 23 return "Info [age=" + age + ", score=" + score + "]"; 24 } 25 26 }
1 public class Score { 2 private String math; 3 private String english; 4 5 public String getMath() { 6 return math; 7 } 8 9 public void setMath(String math) { 10 this.math = math; 11 } 12 13 public String getEnglish() { 14 return english; 15 } 16 17 public void setEnglish(String english) { 18 this.english = english; 19 } 20 21 @Override 22 public String toString() { 23 return "Score [math=" + math + ", english=" + english + "]"; 24 } 25 26 }
转换方法：
1 Score score = new Score(); 2 score.setEnglish("A"); 3 score.setMath("B"); 4 5 Info info = new Info(); 6 info.setAge(20); 7 info.setScore(score); 8 9 Person person = new Person(); 10 person.setInfo(info); 11 person.setName("Tim"); 12 13 JSONObject obj = JSONObject.fromObject(person); 14 System.out.println(obj.toString());
输出：
{
"name": "Tim",
"info": {
"score": {
"english": "A",
"math": "B"
},
"age": 20
}
}
4、把json数组转换成JsonObject数组：
1 // 数组形式的json 2 public static final String JSON_ARRAY = "[{‘name‘:‘tom‘},{‘name‘:‘john‘,‘age‘:20},{}]"; 3 4 JSONArray arr = JSONArray.fromObject(JSON_ARRAY); 5 System.out.println(arr); 6 7 for (int i = 0; i < arr.size(); i++) { 8 JSONObject obj = arr.getJSONObject(i); 9 System.out.println(obj.toString()); 10 }
输出：
[{"name":"tom"},{"name":"john","age":20},{}]
{"name":"tom"}
{"name":"john","age":20}
{}
5、构造一个json字符串：
1 JSONObject obj = new JSONObject(); 2 obj.put("name", "tom"); 3 obj.put("age", 19); 4 5 // 子对象 6 JSONObject objContact = new JSONObject(); 7 objContact.put("tel", "123456"); 8 objContact.put("email", "tom@test.com"); 9 obj.put("contact", objContact); 10 11 // 子数组对象 12 JSONArray scoreArr = new JSONArray(); 13 JSONObject objEnglish = new JSONObject(); 14 objEnglish.put("course", "english"); 15 objEnglish.put("result", 100); 16 objEnglish.put("level", "A"); 17 18 JSONObject objMath = new JSONObject(); 19 objMath.put("course", "math"); 20 objMath.put("result", 50); 21 objMath.put("level", "D"); 22 23 scoreArr.add(objEnglish); 24 scoreArr.add(objMath); 25 26 obj.put("score", scoreArr); 27 28 System.out.println(obj.toString());
输出：
{
"score": [
{
"result": 100,
"level": "A",
"course": "english"
},
{
"result": 50,
"level": "D",
"course": "math"
}
],
"contact": {
"tel": "123456",
"email": "tom@test.com"
},
"name": "tom",
"age": 19
}
思考：输出的json中的字段的顺序有没有办法设置？
Java-json系列（二）：用JSONObject解析和处理json数据
标签：stat person 百度网盘 color tin 处理 没有 json tps
原文地址：http://www.cnblogs.com/jiayongji/p/6417862.html
