标签:数据 clu lan include str UI content 算法 htm
题目连接:http://acm.hdu.edu.cn/showproblem.php?pid=1102
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 21947 Accepted Submission(s):
8448
19970675 | 2017-03-02 20:21:34 | Accepted | 1102 | 15MS | 1456K | 878 B | G++ |
1 #include <stdio.h> 2 #include <string.h> 3 #define inf 0x3f3f3f3f 4 5 int map[110][110],vis[110],dis[110]; 6 int n; 7 8 void prim() 9 { 10 int i,j,pos,min,sum = 0; 11 for (i = 1; i <= n; i ++) 12 { 13 vis[i] = 0; 14 dis[i] = map[1][i]; 15 } 16 vis[1] = 1; dis[1] = 0; 17 for (i = 1; i < n; i ++) 18 { 19 pos = -1; min = inf; 20 for (j = 1; j <= n; j ++) 21 { 22 if (!vis[j] && min > dis[j]) 23 { 24 min = dis[j]; 25 pos = j; 26 } 27 } 28 vis[pos] = 1; 29 sum += min; 30 for (j = 1; j <= n; j ++) 31 if (!vis[j] && dis[j] > map[pos][j]) 32 dis[j] = map[pos][j]; 33 } 34 printf("%d\n",sum); 35 } 36 int main () 37 { 38 int i,j,m,a,b; 39 while (~scanf("%d",&n)) 40 { 41 for (i = 1; i <= n; i ++) 42 for (j = 1; j <= n; j ++) 43 scanf("%d",&map[i][j]); 44 scanf("%d",&m); 45 for (i = 0; i < m; i ++) 46 { 47 scanf("%d%d",&a,&b); 48 map[a][b] = map[b][a] = 0; 49 } 50 prim(); 51 } 52 return 0; 53 }
hdu 1102 Constructing Roads (Prim算法)
标签:数据 clu lan include str UI content 算法 htm
原文地址:http://www.cnblogs.com/yoke/p/6506392.html