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算法(Algorithms)第4版 练习 1.3.20

时间:2017-03-06 23:57:19      阅读:340      评论:0      收藏:0      [点我收藏+]

标签:nod   node   code   方法   exist   i++   thread   insert   next   

方法实现:

//1.3.20
    /**
     * delete the kth element in a linked list, if it exists. 
     * 
     * @param k the kth element, it should larger than 1
     * @throws IllegalArgumentException if k < 1
     * @throws NoSuchElementException if the size of the list is less than k
     */
    public Item delete(int k) {
        
        if(k < 1)
            throw new IllegalArgumentException("k must larger than 1");
        
        Node<Item> precurrent = new Node<Item>();
        precurrent.next = first;
        Item item;
        
        while(precurrent.next != null && k > 1) {
            precurrent = precurrent.next;
            k--;
        }
        
        if(precurrent.next == null) 
            throw new NoSuchElementException("LinkedList hasn‘t so many elements");
        
        item = precurrent.next.item;
        if(precurrent.next == first)
            first = precurrent.next.next;
        else
            precurrent.next = precurrent.next.next;
        
        return item;
    }

 

 

测试用例:

package com.qiusongde.linkedlist;

import edu.princeton.cs.algs4.StdIn;
import edu.princeton.cs.algs4.StdOut;

public class Exercise1320 {

    public static void main(String[] args) {
        
        LinkedList<String> list = new LinkedList<String>();
        
        while(!StdIn.isEmpty()) {
            String s = StdIn.readString();
            list.insertAtBeginning(s);
            StdOut.println("insertAtBeginning success: " + s);
            StdOut.println(list);
        }
        
        int k = 5;
        String s = list.delete(k);
        StdOut.println("delete " + k + "th Element success: "+ s);
        StdOut.println(list);
        
        for(int i = 0; i < 4; i++) {
            k = 1;
            s = list.delete(k);
            StdOut.println("delete " + k + "th Element success: "+ s);
            StdOut.println(list);
        }
        
        k = 5;
        s = list.delete(k);
        StdOut.println("delete " + k + "th Element success: "+ s);
        StdOut.println(list);
    }

}

 

 

测试数据:

to
be
or
not
to

 

 

输出结果:

insertAtBeginning success: to
to 
insertAtBeginning success: be
be to 
insertAtBeginning success: or
or be to 
insertAtBeginning success: not
not or be to 
insertAtBeginning success: to
to not or be to 
delete 5th Element success: to
to not or be 
delete 1th Element success: to
not or be 
delete 1th Element success: not
or be 
delete 1th Element success: or
be 
delete 1th Element success: be

Exception in thread "main" java.util.NoSuchElementException: LinkedList hasn‘t so many elements
    at com.qiusongde.linkedlist.LinkedList.delete(LinkedList.java:130)
    at com.qiusongde.linkedlist.Exercise1320.main(Exercise1320.java:32)

 

算法(Algorithms)第4版 练习 1.3.20

标签:nod   node   code   方法   exist   i++   thread   insert   next   

原文地址:http://www.cnblogs.com/songdechiu/p/6512590.html

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