标签:style io strong for ar amp size sp on
题意:
桌子上有M堆扑克牌;每堆牌的数量分别为Ni(i=1…M);
两人轮流进行;每走一步可以任意选择一堆并取走其中的任意张牌;
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
int a[200];
int main() {
int n;
while(~scanf("%d", &n)&&n) {
int sum = 0;
for(int i=0; i<n; ++i) {
scanf("%d", &a[i]);
sum ^= a[i];
}
int ans = 0;
for(int i=0; i<n; ++i)
if(a[i] > (sum^a[i]) ) ans++;
printf("%d\n", ans);
}
return 0;
}<span style="font-family:Arial, Helvetica, sans-serif;"><span style="white-space: normal;">
</span></span>
hdu1850 Being a Good Boy in Spring Festival ,尼姆博弈(Mimm game),Min sum
标签:style io strong for ar amp size sp on
原文地址:http://blog.csdn.net/yew1eb/article/details/38756583