Fibonacci数列定义为(1,1,2,3,5,8,.....),即每个元素是前两个元素的和。如果一个Fibonacci数与所有小于它的Fibonacci数互质,那么称之为Fibonacci质数。
现在要求你输出前n个Fibonacci数
The Fibonacci Numbers {0, 1, 1,
2, 3, 5, 8, 13, 21, 34, 55 ...} are defined by the recurrence:
F(0)=0
F(1)=1
F(i)=F(i-1)+F(i-2)
Write a program to calculate the Fibonacci Numbers.
The first line of the
input file contains a single integer T, the number of test cases. The following
T lines,each contains an integer n ( 0 <= n <= 45 ), and you are expected
to calculate Fn
Output Fn on a
separate line.
1 #include<stdio.h>
2 int main(){
3 int T,a[50]={0,1,1};
4 for(int i=3;i<=45;i++){
5 a[i]=a[i-1]+a[i-2];
6 }
7 scanf("%d",&T);
8 for(int i=0;i<T;i++){
9 int n;
10 scanf("%d",&n);
11 printf("%d\n",a[n]);
12 }
13 return 0;
14 }