标签:字符 input one python rod 分享 cart 手机 转换
% 取模,返回商的余数
10/3 3.33333333335
10//3 3 地板除,取整数,不是四舍五入
a = 3 b = 5 -----> a<b and a==4 or b<10 and a>1
or前面的条件成立,则不走or后面的式子;or前面的条件不成立,则不考虑前面的式子,直接运算后面的
‘123‘.isdigit() 判断一个字符串是否可以转换为数字
身份判断:type(123) is int type(‘123‘) is str
位运算:
128 64 32 16 8 4 2 1
a=60 0 0 1 1 1 1 0 0
b=13 0 0 0 0 1 1 0 1
&按位与 0 0 0 0 1 1 0 0
|按位或 0 0 1 1 1 1 0 1
三级菜单(low版)
menu = { ‘北京‘:{ ‘海淀‘:{ ‘五道口‘:{ ‘soho‘:{}, ‘网易‘:{}, ‘google‘:{} }, ‘中关村‘:{ ‘爱奇艺‘:{}, ‘汽车之家‘:{}, ‘youku‘:{}, }, ‘上地‘:{ ‘百度‘:{}, }, }, ‘昌平‘:{ ‘沙河‘:{ ‘老男孩‘:{}, ‘北航‘:{}, }, ‘天通苑‘:{}, ‘回龙观‘:{}, }, ‘朝阳‘:{}, ‘东城‘:{}, }, ‘上海‘:{ ‘闵行‘:{ "人民广场":{ ‘炸鸡店‘:{} } }, ‘闸北‘:{ ‘火车战‘:{ ‘携程‘:{} } }, ‘浦东‘:{}, }, ‘山东‘:{}, } break_flag = True while break_flag: for i in menu: print(i) choice1 = input(‘>:‘).strip() if len(choice1)==0:continue if choice1==‘q‘: break_flag = False continue if choice1 in menu: while break_flag: for j in menu[choice1]: print(j) choice2 = input(‘>>:‘).strip() if len(choice2)==0:continue if choice2==‘b‘:break if choice2==‘q‘: break_flag = False continue if choice2 in menu[choice1]: while break_flag: for k in menu[choice1][choice2]: print(k) choice3 = input(‘>>>:‘).strip() if len(choice3)==0:continue if choice3==‘b‘:break if choice3==‘q‘: break_flag = False continue if choice3 in menu[choice1][choice2]: while break_flag: for m in menu[choice1][choice2][choice3]: print(m) choice4 = input(‘>>>>:‘) if len(choice4)==0:continue if choice4==‘b‘:break if choice4==‘q‘: break_flag = False continue
购物车优化作业
shopping_cart = {} #购物车
product_list = [
[‘iphone‘,5800],
[‘小米手机‘,2000],
[‘茅台酒‘,650],
[‘笔‘,5],
[‘电饭锅‘,200]
]
salary = int(input(‘Input your salary:‘))
while True:
index = 0
for product in product_list:
print(index,product)
index+=1
choice = input(‘请输入商品编号:‘)
if choice.isdigit():
choice = int(choice)
if choice>=0 and choice<=len(product_list):
product = product_list[choice]
if product[1] <= salary:
if product[0] in shopping_cart:
shopping_cart[product[1]]+=1
else:
shopping_cart[product[0]]=[product[1],1]
salary-=product[1]
print(‘购物车已添加:‘+product[0]+‘ ,您的余额为:‘+str(salary))
else:
print("工资不够,商品的价格为:%s ,还差:%s"%(str(product[1]),product[1]-salary))
else:
print(‘编号不存在,请重新输入‘)
elif choice==‘q‘:
print(‘-----------您已购买以下商品-----------‘)
id_count = 1
total_cost = 0
print(‘id 商品 单价 数量 总价‘)
for key in shopping_cart:
print("%s\t\t%s\t\t%s\t\t%s\t\t%s"
%(id_count,
key,
shopping_cart[key][0],
shopping_cart[key][1],
shopping_cart[key][0]*shopping_cart[key][1]
)
)
id_count+=1
total_cost+=shopping_cart[key][0]*shopping_cart[key][1]
print(‘您的总花费为:%s‘%total_cost)
print(‘您的余额为:%s‘%salary)
print(‘----------------end---------------‘)
else:
print(‘编号输入错误‘)
标签:字符 input one python rod 分享 cart 手机 转换
原文地址:http://www.cnblogs.com/guotianbao/p/6718349.html