sqlserver实现树形结构递归查询(无限极分类)

--菜单目录结构表  
create table tb_menu(  
 id int not null, --主键id  
title varchar(50), --标题  
 parent int --parent id  
);  
--父菜单  
insert into tb_menu(id, title, parent) values(1, ‘父菜单1‘,null);  
insert into tb_menu(id, title, parent) values(2, ‘父菜单2‘,null);  
insert into tb_menu(id, title, parent) values(3, ‘父菜单3‘,null);  
insert into tb_menu(id, title, parent) values(4, ‘父菜单4‘,null);  
insert into tb_menu(id, title, parent) values(5, ‘父菜单5‘,null);  
--一级菜单  
insert into tb_menu(id, title, parent) values(6, ‘一级菜单6‘,1);  
insert into tb_menu(id, title, parent) values(7, ‘一级菜单7‘,1);  
insert into tb_menu(id, title, parent) values(8, ‘一级菜单8‘,1);  
insert into tb_menu(id, title, parent) values(9, ‘一级菜单9‘,2);  
insert into tb_menu(id, title, parent) values(10, ‘一级菜单10‘,2);  
insert into tb_menu(id, title, parent) values(11, ‘一级菜单11‘,2);  
insert into tb_menu(id, title, parent) values(12, ‘一级菜单12‘,3);  
insert into tb_menu(id, title, parent) values(13, ‘一级菜单13‘,3);  
insert into tb_menu(id, title, parent) values(14, ‘一级菜单14‘,3);  
insert into tb_menu(id, title, parent) values(15, ‘一级菜单15‘,4);  
insert into tb_menu(id, title, parent) values(16, ‘一级菜单16‘,4);  
insert into tb_menu(id, title, parent) values(17, ‘一级菜单17‘,4);  
insert into tb_menu(id, title, parent) values(18, ‘一级菜单18‘,5);  
insert into tb_menu(id, title, parent) values(19, ‘一级菜单19‘,5);  
insert into tb_menu(id, title, parent) values(20, ‘一级菜单20‘,5);  
--二级菜单  
insert into tb_menu(id, title, parent) values(21, ‘二级菜单21‘,6);  
insert into tb_menu(id, title, parent) values(22, ‘二级菜单22‘,6);  
insert into tb_menu(id, title, parent) values(23, ‘二级菜单23‘,7);  
insert into tb_menu(id, title, parent) values(24, ‘二级菜单24‘,7);  
insert into tb_menu(id, title, parent) values(25, ‘二级菜单25‘,8);  
insert into tb_menu(id, title, parent) values(26, ‘二级菜单26‘,9);  
insert into tb_menu(id, title, parent) values(27, ‘二级菜单27‘,10);  
insert into tb_menu(id, title, parent) values(28, ‘二级菜单28‘,11);  
insert into tb_menu(id, title, parent) values(29, ‘二级菜单29‘,12);  
insert into tb_menu(id, title, parent) values(30, ‘二级菜单30‘,13);  
insert into tb_menu(id, title, parent) values(31, ‘二级菜单31‘,14);  
insert into tb_menu(id, title, parent) values(32, ‘二级菜单32‘,15);  
insert into tb_menu(id, title, parent) values(33, ‘二级菜单33‘,16);  
insert into tb_menu(id, title, parent) values(34, ‘二级菜单34‘,17);  
insert into tb_menu(id, title, parent) values(35, ‘二级菜单35‘,18);  
insert into tb_menu(id, title, parent) values(36, ‘二级菜单36‘,19);  
insert into tb_menu(id, title, parent) values(37, ‘二级菜单37‘,20);  
  
--三级菜单  
insert into tb_menu(id, title, parent) values(38, ‘三级菜单38‘,21);  
insert into tb_menu(id, title, parent) values(39, ‘三级菜单39‘,22);  
insert into tb_menu(id, title, parent) values(40, ‘三级菜单40‘,23);  
insert into tb_menu(id, title, parent) values(41, ‘三级菜单41‘,24);  
insert into tb_menu(id, title, parent) values(42, ‘三级菜单42‘,25);  
insert into tb_menu(id, title, parent) values(43, ‘三级菜单43‘,26);  
insert into tb_menu(id, title, parent) values(44, ‘三级菜单44‘,27);  
insert into tb_menu(id, title, parent) values(45, ‘三级菜单45‘,28);  
insert into tb_menu(id, title, parent) values(46, ‘三级菜单46‘,28);  
insert into tb_menu(id, title, parent) values(47, ‘三级菜单47‘,29);  
insert into tb_menu(id, title, parent) values(48, ‘三级菜单48‘,30);  
insert into tb_menu(id, title, parent) values(49, ‘三级菜单49‘,31);  
insert into tb_menu(id, title, parent) values(50, ‘三级菜单50‘,31);  
commit;  

--查询树状结构某节点(44)的上级所有根节点  
  
with cte_parent(id,title,parent)  
  
as  
  
(  
  
    --起始条件  
  
    select id,title,parent  
  
    from tb_menu  
  
    where id = 44   --列出子节点查询条件  
  
    union all  
  
    --递归条件  
  
    select a.id,a.title,a.parent  
  
    from tb_menu a  
  
    inner join   
  
    cte_parent b          --执行递归，这里就要理解下了   
  
    on a.id=b.parent    
  
)                         
  
select * from cte_parent;  

--查询树状结构某节点下的所有子节点(  
  
with cte_child(id,title,parent,level)  
  
as  
  
(  
  
    --起始条件  
  
    select id,title,parent,0 as level  
  
    from tb_menu  
  
    where id = 6--列出父节点查询条件  
  
    union all  
  
    --递归条件  
  
    select a.id,a.title,a.parent,b.level+1  
  
    from tb_menu a  
  
    inner join   
  
    cte_child b  
  
    on ( a.parent=b.id)    
  
)  
  
select  * from cte_child;