var startTime ="20170501"
var endTime = "20170430"
var pattern = /(\d{4})(\d{2})(\d{2})/;
var startTime_f = startTime.replace(pattern, ‘$1-$2-$3‘)
var endTime_f = endTime.replace(pattern, ‘$1-$2-$3‘)
//转化后的时间格式 startTime_f=“2017-05-01” endTime_f="2017-04-30"
var time1 = Date.parse(new Date(startTime_f));
var time2 = Date.parse(new Date(endTime_f));
var nDays = Math.abs(parseInt((time2 - time1)/1000/3600/24));
本文出自 “编程” 博客,请务必保留此出处http://lizijun.blog.51cto.com/6392394/1927521
原文地址:http://lizijun.blog.51cto.com/6392394/1927521