码迷,mamicode.com
首页 > 编程语言 > 详细

JavaScript 图

时间:2017-06-12 11:49:49      阅读:239      评论:0      收藏:0      [点我收藏+]

标签:this   add   func   empty   实现   splay   sso   ros   结构   

TypeScript方式实现源码

 

// 图的遍历算法
// 算  法         数据结构     描  述 
// 深度优先搜索    栈          通过将顶点存入栈中,顶点是沿着路径被探索的,存在新的相
// 邻顶点就去访问 
// 广度优先搜索    队列        通过将顶点存入队列中,最先入队列的顶点先被探索 
// 当要标注已经访问过的顶点时,我们用三种颜色来反映它们的状态。 
// ? 白色:表示该顶点还没有被访问。 
// ? 灰色:表示该顶点被访问过,但并未被探索过。 
// ? 黑色:表示该顶点被访问过且被完全探索过。 
// 广度优先搜索算法会从指定的第一个顶点开始遍历图, 先访问其所有的相邻点, 就像一次访
// 问图的一层

 

技术分享
  1 class Graph {
  2     vertices = [];
  3     adjList = new Dictionary();
  4     public addVertex(v) {
  5         this.vertices.push(v);
  6         this.adjList.set(v, []);
  7     }
  8     public addEdge(v, w) {
  9         this.adjList.get(v).push(w);
 10         this.adjList.get(w).push(v);
 11     }
 12     public initializeColor() {
 13         let color = [], length = this.vertices.length;
 14         for (var i = 0; i < length; i++) {
 15             color[this.vertices[i]] = white;
 16         }
 17         return color;
 18     }
 19     /**
 20      * 宽度优先搜索
 21      * @param v 
 22      * @param callback 
 23      */
 24     public bfs(v, callback) {
 25         let color = this.initializeColor(),
 26             queue = new Queue();
 27         queue.enqueue(v);
 28         while (!queue.isEmpty()) {
 29             let u = queue.dequeue(),
 30                 neighbors = this.adjList.get(u);
 31             color[u] = grey;
 32             for (let i = 0; i < neighbors.length; i++) {
 33                 let w = neighbors[i];
 34                 if (color[w] === white) {
 35                     color[w] = grey;
 36                     queue.enqueue(w);
 37                 }
 38             }
 39             color[u] = black;
 40             if (callback) {
 41                 callback(u);
 42             }
 43         }
 44     }
 45     /**
 46      * 寻找最短路径
 47      * @param v 
 48      */
 49     public BFS(v) {
 50         let color = this.initializeColor(),
 51             queue = new Queue(),
 52             d = [],
 53             pred = [];
 54         queue.enqueue(v);
 55         for (var i = 0; i < this.vertices.length; i++) {
 56             d[this.vertices[i]] = 0;
 57             pred[this.vertices[i]] = null;
 58         }
 59         while (!queue.isEmpty()) {
 60             let u = queue.dequeue(),
 61                 neighbors = this.adjList.get(u);
 62             color[u] = grey;
 63             for (let i = 0; i < neighbors.length; i++) {
 64                 let w = neighbors[i];
 65                 if (color[w] === white) {
 66                     color[w] = grey;
 67                     d[w] = d[u] + 1;
 68                     pred[w] = u;
 69                     queue.enqueue(w);
 70                 }
 71             }
 72             color[u] = black;
 73         }
 74         return {
 75             distances: d,
 76             predecessors: pred
 77         }
 78     }
 79     public toString() {
 80         let s = ‘‘;
 81         for (let i = 0; i < this.vertices.length; i++) {
 82             s += this.vertices[i] +  -> ;
 83             let neighbors = this.adjList.get(this.vertices[i]);
 84             for (var j = 0; j < neighbors.length; j++) {
 85                 s += neighbors[j] +  ;
 86             }
 87             s += \n;
 88         }
 89         return s;
 90     }
 91 }
 92 var graph = new Graph();
 93 var myVertices = [A, B, C, D, E, F, G, H, I]; //{7} 
 94 for (var i = 0; i < myVertices.length; i++) { //{8} 
 95     graph.addVertex(myVertices[i]);
 96 }
 97 graph.addEdge(A, B); //{9} 
 98 graph.addEdge(A, C);
 99 graph.addEdge(A, D);
100 graph.addEdge(C, D);
101 graph.addEdge(C, G);
102 graph.addEdge(D, G);
103 graph.addEdge(D, H);
104 graph.addEdge(B, E);
105 graph.addEdge(B, F);
106 graph.addEdge(E, I);
107 
108 console.log(graph.toString());
109 
110 function printNode(value) {
111     console.log(Visited vertex: + value);
112 }
113 graph.bfs(myVertices[0], printNode);
114 
115 var shortestPathA = graph.BFS(myVertices[0]);
116 console.log(shortestPathA);
View Code

 

 

JavaScript方式实现源码

 

技术分享
 1 var Graph = (function () {
 2     function Graph() {
 3         this.vertices = [];
 4         this.adjList = new Dictionary();
 5     }
 6     Graph.prototype.addVertex = function (v) {
 7         this.vertices.push(v);
 8         this.adjList.set(v, []);
 9     };
10     Graph.prototype.addEdge = function (v, w) {
11         this.adjList.get(v).push(w);
12         this.adjList.get(w).push(v);
13     };
14     Graph.prototype.initializeColor = function () {
15         var color = [], length = this.vertices.length;
16         for (var i = 0; i < length; i++) {
17             color[this.vertices[i]] = white;
18         }
19         return color;
20     };
21     /**
22      * 宽度优先搜索
23      * @param v
24      * @param callback
25      */
26     Graph.prototype.bfs = function (v, callback) {
27         var color = this.initializeColor(), queue = new Queue();
28         queue.enqueue(v);
29         while (!queue.isEmpty()) {
30             var u = queue.dequeue(), neighbors = this.adjList.get(u);
31             color[u] = grey;
32             for (var i_1 = 0; i_1 < neighbors.length; i_1++) {
33                 var w = neighbors[i_1];
34                 if (color[w] === white) {
35                     color[w] = grey;
36                     queue.enqueue(w);
37                 }
38             }
39             color[u] = black;
40             if (callback) {
41                 callback(u);
42             }
43         }
44     };
45     /**
46      * 寻找最短路径
47      * @param v
48      */
49     Graph.prototype.BFS = function (v) {
50         var color = this.initializeColor(), queue = new Queue(), d = [], pred = [];
51         queue.enqueue(v);
52         for (var i = 0; i < this.vertices.length; i++) {
53             d[this.vertices[i]] = 0;
54             pred[this.vertices[i]] = null;
55         }
56         while (!queue.isEmpty()) {
57             var u = queue.dequeue(), neighbors = this.adjList.get(u);
58             color[u] = grey;
59             for (var i_2 = 0; i_2 < neighbors.length; i_2++) {
60                 var w = neighbors[i_2];
61                 if (color[w] === white) {
62                     color[w] = grey;
63                     d[w] = d[u] + 1;
64                     pred[w] = u;
65                     queue.enqueue(w);
66                 }
67             }
68             color[u] = black;
69         }
70         return {
71             distances: d,
72             predecessors: pred
73         };
74     };
75     Graph.prototype.toString = function () {
76         var s = ‘‘;
77         for (var i_3 = 0; i_3 < this.vertices.length; i_3++) {
78             s += this.vertices[i_3] +  -> ;
79             var neighbors = this.adjList.get(this.vertices[i_3]);
80             for (var j = 0; j < neighbors.length; j++) {
81                 s += neighbors[j] +  ;
82             }
83             s += \n;
84         }
85         return s;
86     };
87     return Graph;
88 }());
View Code

 

JavaScript 图

标签:this   add   func   empty   实现   splay   sso   ros   结构   

原文地址:http://www.cnblogs.com/menu/p/6991945.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!