标签：通过 时间间隔 连接 睡眠 private auth catch 银行 sed
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前段时间去银行办业务，排队的人那是真多。自己正式办理业务也就不到5分钟，可是却足足等了两个小时（相信非常多人都遇到过这样的情况），对这样的服务水平真的是无语了，可是问题又来了。银行应该开几个窗体，既能保证总体的服务质量，又能保证资源资源的利用率呢？以下我们就通过排队论来模拟这个问题。
排队论简单介绍
排队论是研究系统随机聚散现象和随机系统工作project的数学理论和方法，又称随机服务系统理论。为运筹学的一个分支。
我们以下对排队论做下简化处理，先看下图：
我们在图的左側安排若干个蓝色服务台，右側为可能会过来的红色顾客，中间为黄色的等候区，假设有服务台处于空暇状态。顾客能够直接去接受服务，否则就要在黄色区域等候，顾客服务的顺序採用先到现服务的原则。如今假设我们知道顾客过来的概率分布，那么我们在左側安排几个服务台既能达到更好的服务水平，又能保证服务台的使用率？以下我们就构建模型来模拟这个问题。
排队论分步实现
1）对于排队论，我们首先要确定顾客属性，知道顾客什么时候到达，须要的服务耗时等，我们首先创建一个顾客类。在这里我们指定了顾客服务的最大、最小时间，这里我们为了简化就直接觉得服务时间全然随机：
public class CustomerBean {
//最小服务时间
private static int minServeTime = 3 * 1000;
//最大服务时间
private static int maxServeTime = 15 * 1000;
//顾客达到时间
private long arriveTime;
//顾客须要服务耗时
private int serveTime;
public CustomerBean() {
//设置到达时间
arriveTime = System.currentTimeMillis();
//随机设置顾客的服务时间
serveTime = (int) (Math.random() * (maxServeTime - minServeTime) + minServeTime);
}
}public class CustomerQuene {
//等待顾客队列
private LinkedList<CustomerBean> customers = new LinkedList<CustomerBean>();
//下一个顾客过来最短时间
private int minTime = 0;
//下一个顾客过来最大时间
private int maxTime = 1 * 1000;
//来顾客的概率
private double rate = 0.9;
//标识是否继续产生顾客
private boolean flag = true;
//最大排队人数
private int maxWaitNum = 0;
}/**
*@Description: 生成顾客线程
*@Author:lulei
*@Version:1.1.0
*/
private class CustomerThread extends Thread {
private CustomerThread(String name) {
super(name);
}
@Override
public void run() {
while (flag) {
//队尾加入一个新顾客
if (Math.random() < rate) {
customers.addLast(new CustomerBean());
if (maxWaitNum < customers.size()) {
maxWaitNum = customers.size();
}
}
int sleepTime = (int) (Math.random() * (maxTime - minTime) + minTime);
try {
TimeUnit.MILLISECONDS.sleep(sleepTime);
} catch (Exception e) {
e.printStackTrace();
}
}
}
}4）假设队列中有顾客排队切有空暇的服务台，就须要获取队头的顾客去接受服务
public synchronized CustomerBean getCustomerBean() {
if (customers == null || customers.size() < 1) {
return null;
}
return customers.removeFirst();
}
public class ServantThread extends Thread{
//服务顾客数目
private static int customerNum = 0;
//总等待时间
private static int sumWaitTime = 0;
//总服务时间
private static int sumServeTime = 0;
//最大等待时间
private static int maxWaitTime = 0;
private boolean flag = false;
private String name;
}public void run() {
flag = true;
while (flag) {
CustomerBean customer = CustomerQuene.getCustomerQuene().getCustomerBean();
//假设顾客线程已经关闭且队列中没有顾客。服务台线程关闭释放
if (customer == null) {
if (!CustomerQuene.getCustomerQuene().isFlag()) {
flag = false;
print();
}
continue;
}
long now = System.currentTimeMillis();
int waitTime = (int) (now - customer.getArriveTime());
//保存最大的等待时间
if (waitTime > maxWaitTime) {
maxWaitTime = waitTime;
}
//睡眠时间为顾客的服务时间。代表这段时间在服务顾客
try {
TimeUnit.MILLISECONDS.sleep(customer.getServeTime());
} catch (Exception e) {
e.printStackTrace();
}
System.err.println(name + " 服务顾客耗时：" + customer.getServeTime() + "ms\t顾客等待：" + waitTime + "ms");
customerNum++;
sumWaitTime += waitTime;
sumServeTime += customer.getServeTime();
}
} /**
*@Description:
*/
package com.lulei.opsearch.quene;
import java.util.concurrent.TimeUnit;
public class Test {
public static void main(String[] args) {
//开门
System.out.println("开门接客啦。");
boolean flag = true;
CustomerQuene.getCustomerQuene();
long a = System.currentTimeMillis();
int servantNum = 10;
for (int i = 0; i < servantNum; i++) {
ServantThread thread = new ServantThread("服务台" + i);
thread.start();
}
while (flag) {
long b = System.currentTimeMillis();
if (b - a > 1 * 60 * 1000 && flag) {
//关门
flag = false;
CustomerQuene.getCustomerQuene().close();
System.out.println("关门不接客啦！");
}
System.out.println("系统执行时间：" + (b -a) + "ms");
System.out.println("系统空暇时间：" + ((b -a) * servantNum - ServantThread.getSumServeTime()));
ServantThread.print();
try {
TimeUnit.SECONDS.sleep(2);
} catch (Exception e) {
e.printStackTrace();
}
}
}
}
1）执行開始
2）顾客产生线程关闭
3）最后服务水平
通过改动服务台的个数就能够评估在当前的顾客情况下应该设置几个服务台。
完整代码
1）顾客类
/**
*@Description:
*/
package com.lulei.opsearch.quene;
public class CustomerBean {
//最小服务时间
private static int minServeTime = 3 * 1000;
//最大服务时间
private static int maxServeTime = 15 * 1000;
//顾客达到时间
private long arriveTime;
//顾客须要服务耗时
private int serveTime;
public CustomerBean() {
//设置到达时间
arriveTime = System.currentTimeMillis();
//随机设置顾客的服务时间
serveTime = (int) (Math.random() * (maxServeTime - minServeTime) + minServeTime);
}
public static int getMinServeTime() {
return minServeTime;
}
public static void setMinServeTime(int minServeTime) {
CustomerBean.minServeTime = minServeTime;
}
public static int getMaxServeTime() {
return maxServeTime;
}
public static void setMaxServeTime(int maxServeTime) {
CustomerBean.maxServeTime = maxServeTime;
}
public long getArriveTime() {
return arriveTime;
}
public void setArriveTime(long arriveTime) {
this.arriveTime = arriveTime;
}
public int getServeTime() {
return serveTime;
}
public void setServeTime(int serveTime) {
this.serveTime = serveTime;
}
}
/**
*@Description:
*/
package com.lulei.opsearch.quene;
import java.util.LinkedList;
import java.util.concurrent.TimeUnit;
public class CustomerQuene {
//等待顾客队列
private LinkedList<CustomerBean> customers = new LinkedList<CustomerBean>();
//下一个顾客过来最短时间
private int minTime = 0;
//下一个顾客过来最大时间
private int maxTime = 1 * 1000;
//来顾客的概率
private double rate = 0.9;
//标识是否继续产生顾客
private boolean flag = true;
//最大排队人数
private int maxWaitNum = 0;
public int getMaxWaitNum() {
return maxWaitNum;
}
public boolean isFlag() {
return flag;
}
/**
* @return
* @Author:lulei
* @Description: 获取排在队头的顾客
*/
public synchronized CustomerBean getCustomerBean() {
if (customers == null || customers.size() < 1) {
return null;
}
return customers.removeFirst();
}
public void close() {
if (flag) {
flag = false;
}
}
/**
* @return
* @Author:lulei
* @Description: 获取等待顾客数量
*/
public int getWaitCustomerNum() {
return customers.size();
}
/**
*@Description: 生成顾客线程
*@Author:lulei
*@Version:1.1.0
*/
private class CustomerThread extends Thread {
private CustomerThread(String name) {
super(name);
}
@Override
public void run() {
while (flag) {
//队尾加入一个新顾客
if (Math.random() < rate) {
customers.addLast(new CustomerBean());
if (maxWaitNum < customers.size()) {
maxWaitNum = customers.size();
}
}
int sleepTime = (int) (Math.random() * (maxTime - minTime) + minTime);
try {
TimeUnit.MILLISECONDS.sleep(sleepTime);
} catch (Exception e) {
e.printStackTrace();
}
}
}
}
//单例模式開始
private static class CustomerQueneDao {
private static CustomerQuene customerQuene = new CustomerQuene();
}
private CustomerQuene() {
CustomerThread customerThread = new CustomerThread("顾客产生线程");
customerThread.start();
}
public static CustomerQuene getCustomerQuene() {
return CustomerQueneDao.customerQuene;
}
//单例模式结束
public int getMinTime() {
return minTime;
}
public void setMinTime(int minTime) {
this.minTime = minTime;
}
public int getMaxTime() {
return maxTime;
}
public void setMaxTime(int maxTime) {
this.maxTime = maxTime;
}
public double getRate() {
return rate;
}
public void setRate(double rate) {
this.rate = rate;
}
}
/**
*@Description:
*/
package com.lulei.opsearch.quene;
import java.util.concurrent.TimeUnit;
import com.lulei.util.ParseUtil;
public class ServantThread extends Thread{
//服务顾客数目
private static int customerNum = 0;
//总等待时间
private static int sumWaitTime = 0;
//总服务时间
private static int sumServeTime = 0;
//最大等待时间
private static int maxWaitTime = 0;
private boolean flag = false;
private String name;
public ServantThread(String name) {
super(name);
this.name = name;
}
public static int getMaxWaitTime() {
return maxWaitTime;
}
public static int getSumServeTime() {
return sumServeTime;
}
@Override
public void run() {
flag = true;
while (flag) {
CustomerBean customer = CustomerQuene.getCustomerQuene().getCustomerBean();
//假设顾客线程已经关闭且队列中没有顾客。服务台线程关闭释放
if (customer == null) {
if (!CustomerQuene.getCustomerQuene().isFlag()) {
flag = false;
print();
}
continue;
}
long now = System.currentTimeMillis();
int waitTime = (int) (now - customer.getArriveTime());
//保存最大的等待时间
if (waitTime > maxWaitTime) {
maxWaitTime = waitTime;
}
//睡眠时间为顾客的服务时间，代表这段时间在服务顾客
try {
TimeUnit.MILLISECONDS.sleep(customer.getServeTime());
} catch (Exception e) {
e.printStackTrace();
}
System.err.println(name + " 服务顾客耗时：" + customer.getServeTime() + "ms\t顾客等待：" + waitTime + "ms");
customerNum++;
sumWaitTime += waitTime;
sumServeTime += customer.getServeTime();
}
}
public static void print() {
if (customerNum > 0) {
System.out.println("--------------------------------------");
System.out.println("服务顾客数目：" + customerNum);
System.out.println("最大等待时间：" + maxWaitTime);
System.out.println("等待顾客数目：" + CustomerQuene.getCustomerQuene().getWaitCustomerNum());
System.out.println("最大等待顾客数目：" + CustomerQuene.getCustomerQuene().getMaxWaitNum());
//输出顾客平均等待时间。保留两位小数
System.out.println("顾客平均等待时间：" + ParseUtil.parseDoubleToDouble((sumWaitTime * 1.0 / customerNum), 2) + "ms");
System.out.println("顾客平均服务时间：" + ParseUtil.parseDoubleToDouble((sumServeTime * 1.0 / customerNum), 2) + "ms");
System.out.println("系统总服务时间：" + sumServeTime + "ms");
}
}
}
/**
*@Description:
*/
package com.lulei.opsearch.quene;
import java.util.concurrent.TimeUnit;
public class Test {
public static void main(String[] args) {
//开门
System.out.println("开门接客啦！");
boolean flag = true;
CustomerQuene.getCustomerQuene();
long a = System.currentTimeMillis();
int servantNum = 10;
for (int i = 0; i < servantNum; i++) {
ServantThread thread = new ServantThread("服务台" + i);
thread.start();
}
while (flag) {
long b = System.currentTimeMillis();
if (b - a > 1 * 60 * 1000 && flag) {
//关门
flag = false;
CustomerQuene.getCustomerQuene().close();
System.out.println("关门不接客啦！");
}
System.out.println("系统执行时间：" + (b -a) + "ms");
System.out.println("系统空暇时间：" + ((b -a) * servantNum - ServantThread.getSumServeTime()));
ServantThread.print();
try {
TimeUnit.SECONDS.sleep(2);
} catch (Exception e) {
e.printStackTrace();
}
}
}
}
标签：通过 时间间隔 连接 睡眠 private auth catch 银行 sed
原文地址：http://www.cnblogs.com/clnchanpin/p/7009811.html
