标签:atp file dns ntp word waf lvf fmb res
1. 题目:找出100~200内所有的素数。
2. 要求:将100~200内所有的素数找出并显示值,要求每行显示5个素数。
3. 要求素数的判定算法用子程序来实现,子程序在判定数是否为素数后有不同的返回参数。
1 ; Example assembly language program -- adds two numbers 2 ; Author: Karllen 3 ; Date: revised 05/2014 4 5 .386 6 .MODEL FLAT 7 8 ExitProcess PROTO NEAR32 stdcall, dwExitCode:DWORD 9 10 INCLUDE io.h ; header file for input/output 11 12 cr EQU 0dh ; carriage return character 13 Lf EQU 0ah ; line feed 14 15 .STACK 4096 ; reserve 4096-byte stack 16 17 .DATA ; reserve storage for data 18 promot BYTE "The program is to find primes from 100 to 200",cr,Lf,0 19 cmm BYTE " ",0 20 crlf BYTE cr,Lf,0 21 number DWORD ? 22 flai DWORD ? 23 value BYTE 11 DUP(?) 24 PUBLIC _start ; make entry point public 25 .CODE ; start of main program code 26 _start: 27 output promot 28 mov number,99 29 mov flai,0 30 31 doFirstWhile: 32 inc number 33 cmp number,200 34 jg endFirstWhile 35 mov eax,number 36 push eax 37 call findPrime 38 add esp,4 39 ; 40 cmp eax,0 41 je endSecond 42 inc flai 43 dtoa value,number 44 output value 45 output cmm 46 mov eax,flai 47 mov ecx,5 48 cdq 49 idiv ecx 50 cmp edx,0 51 je printCrlf 52 53 endSecond: 54 jmp doFirstWhile 55 printCrlf: 56 output crlf 57 jmp doFirstWhile 58 59 endFirstWhile: 60 INVOKE ExitProcess, 0 ; exit with return code 0 61 62 63 findPrime PROC NEAR32 64 push ebp 65 mov ebp,esp 66 67 mov ebx,2 68 mov eax,[ebp+8] 69 mov ecx,eax 70 docuWhile: 71 cmp ebx,ecx 72 je found 73 mov eax,ecx 74 cdq 75 idiv ebx 76 cmp edx,0 77 je noFound 78 inc ebx 79 jmp docuWhile 80 found: 81 mov eax,1 82 jmp endcuWhile 83 noFound: 84 mov eax,0 85 endcuWhile: 86 pop ebp 87 ret 88 findPrime ENDP 89 90 END ; end of source code
测试结果
标签:atp file dns ntp word waf lvf fmb res
原文地址:http://www.cnblogs.com/xieyulin/p/7056425.html