#include <queue>
#include <cstdio>
#include <iostream>
#define N 100001
#define ls now << 1
#define rs now << 1 | 1
#define max(x, y) (p[x].a * 2 + p[x].b > p[y].a * 2 + p[y].b ? (x) : (y))

int n, last, now, ans, M[N];
std::priority_queue <int> q; 

struct node
{
	int a, b;
}p[N];

inline int read()
{
	int x = 0, f = 1;
	char ch = getchar();
	for(; !isdigit(ch); ch = getchar()) if(ch == ‘-‘) f = -1;
	for(; isdigit(ch); ch = getchar()) x = (x << 1) + (x << 3) + ch - ‘0‘;
	return x * f;
}

inline void add(int x, int d)
{
	for(; x; x -= x & -x) M[x] = max(M[x], d);
}

inline int query(int x)
{
	int ret = 0;
	for(; x <= n; x += x & -x) ret = max(ret, M[x]);
	return ret;
}

int main()
{
	int i, j, x;
	n = read();
	for(i = 1; i <= n; i++) p[i].a = read();
	for(i = 1; i <= n; i++) p[i].b = read();
	for(i = 1; i <= n; i++) add(i, i);
	last = 0;
	for(i = 1; i <= n; i++)
	{
		now = query(last + 1);
		if(q.empty() || (q.top() < (p[now].a - p[last].a) * 2 + p[now].b))
		{
			for(j = last + 1; j < now; j++) q.push(p[j].b);
			ans += (p[now].a - p[last].a) * 2 + p[now].b;
			last = now;
		}
		else
		{
			ans += q.top();
			q.pop();
		}
		printf("%d\n", ans);
	}
	return 0;
}