标签:cti 连续 bool make turn ide builder main uil
private void exitDialog() { AlertDialog.Builder aa=new AlertDialog.Builder(this); aa.setTitle("消息提示"); aa.setMessage("确认退出?"); aa.setIcon(R.drawable.icon); aa.setPositiveButton("确定",new DialogInterface.OnClickListener() { @Override public void onClick(DialogInterface dialog, int which) { // TODO Auto-generated method stub MainActivity.this.finish(); } }); aa.setNegativeButton("取消", null); aa.create(); aa.show(); } @Override public boolean onKeyDown(int keyCode, KeyEvent event) { if(keyCode == KeyEvent.KEYCODE_BACK) { exitDialog(); } return true; }
现在还流行连续按两次返回退出,代码:
private static boolean isExit=false; private static boolean hasTask=false; Timer tExit=new Timer(); TimerTask task=new TimerTask() { @Override public void run() { // TODO Auto-generated method stub isExit=false; hasTask=true; } }; @Override public boolean onKeyDown(int keyCode, KeyEvent event) { if(keyCode == KeyEvent.KEYCODE_BACK) { //exitDialog(); if(isExit==false) { isExit=true; Toast.makeText(this, "再按一次退出程序", Toast.LENGTH_SHORT).show(); if(!hasTask) { tExit.schedule(task, 2000); } } else { finish(); System.exit(0); } } //return true; return false; }
标签:cti 连续 bool make turn ide builder main uil
原文地址:http://www.cnblogs.com/gisoracle/p/7101936.html