字符串排序，返回符合格式的元组数据

s = ‘2kd4-1124*2|^2sdAmZ%fkMcv‘
def fun(s):
    li = []
    li2 = []
    tu = ()
    for i in s:
        li.append(i)
    print(‘排序前：‘,end=‘‘)
    print(li)
    n = len(li)
    for i in range(n-1):
        for j in range(n-1-i):
            if li[j]<li[j+1]:
                li[j],li[j+1] = li[j+1],li[j]
    if n%2==0:
        for i in range(n//2):
            li2.append(‘({},{})‘.format(li[i],li[n-1-i]))
    else:
        for i in range(n//2):
            li2.append(‘({},{})‘.format(li[i], li[n-1-i]))
        li2.append(‘({})‘.format(li[n//2]))

    print(‘排序后：‘,end=‘‘)
    print(li)    
    return tuple(li2)
tu = fun(s)
print(‘新格式：‘,end=‘‘)
print(tu)