标签:middle compare i++ let 回文数 int always with string
function palindrome(str) { return str.replace(/[\W_]/g, ‘‘).toLowerCase() === str.replace(/[\W_]/g, ‘‘).toLowerCase().split(‘‘).reverse().join(‘‘); }
function palindrome(str) { str = str.toLowerCase().replace(/[\W_]/g, ‘‘); for(var i = 0, len = str.length - 1; i < len/2; i++) { if(str[i] !== str[len-i]) { return false; } } return true; }
function palindrome(str) { let front = 0; let back = str.length - 1; //back and front pointers won‘t always meet in the middle, so use (back > front) while (back > front) { //increments front pointer if current character doesn‘t meet criteria while ( str[front].match(/[\W_]/) ) { front++; continue; } //decrements back pointer if current character doesn‘t meet criteria while ( str[back].match(/[\W_]/) ) { back--; continue; } //finally does the comparison on the current character if ( str[front].toLowerCase() !== str[back].toLowerCase() ) return false front++; back--; } //if the whole string has been compared without returning false, it‘s a palindrome! return true; }
标签:middle compare i++ let 回文数 int always with string
原文地址:http://www.cnblogs.com/littlewriter/p/7181399.html