如何使用ajax 提交easyUI form表单

<form id="Login" method="post">
...
</form>

 $(function(){
  $("#log").click(function(){
        $("#Login").form("submit",{
            url:"LoginServlet",
            onSubmit: function(){
                var s= $("#Login").form("validate");
                if(s){
                    return true;
                }else{
                    $.messager.alert("提示","信息填写不完整","info"); 
                    return false;
                }
            },    
            success:function(data){    
                   var data1 = eval("("+data+")");
                   if(data1.success){
                       window.location.href="indexZhu.jsp";
                   }else if(data1.error){
                       $.messager.alert("提示","用户名或密码错误","info");
                   }else if(data1.success1){
                       $.messager.alert("提示","登录通道错误！","info");
                   }else{
                       $.messager.alert("提示","请输入完整的信息","info");
                   }
            }
        });
    });

});