标签:alt bsp sni reserve 元素 name value water roo
自己偶尔看到了下图。于是用php打印出下图。
两种方法解决此问题:
方法一:依据图分析该图是一个二维数组,可用二维数组解决此类问题,6行就是6个数组,每一行就代表数组有多少个元素。知道每一个数组元素的个数。不就能够知道数组中有哪几个元素吗?
function array_chunk_vertical($arr, $colun)
{
$arr_length = count($arr);
$parem = floor($arr_length / $colun);
$pare = $arr_length % $colun;
$ar = array();
for ($i = 0; $i < $colun; $i ++) {
$par = $i == $colun - 1 ? 1 : 5;
$ar[] = $par;
}
$newarray = array();
foreach ($ar as $value) {
for ($i = 0; $i < $value; $i ++) {
$newarray[$i][] = array_shift($arr);
}
}
return $newarray;
}
$arr = range(1, 31);
$data = array_chunk_vertical($arr, 7);
foreach ($data as $value) {
foreach ($value as $va) {
printf('[%2s]', $va);
}
echo "<br/>";
}
方法二:如代码。先给出size个空数组。在空数组中填充元素。
详细方法例如以下:
<?php function array_chunk_vertical($input, $size, $preserve_keys = FALSE, $size_is_horizontal = false) { $chunks = array(); if ($size_is_horizontal) { $chunk_count = ceil(count($input) / $size); } else { $chunk_count = $size; } for ($chunk_index = 0; $chunk_index < $chunk_count; $chunk_index++) { $chunks[] = array(); } $chunk_index = 0; foreach ($input as $key => $value) { if ($preserve_keys) { $chunks[$chunk_index][$key] = $value; } else { $chunks[$chunk_index][] = $value; } if (++$chunk_index == $chunk_count) { $chunk_index = 0; } } return $chunks; } $data=range(1,31); $newdata=array_chunk_vertical($data,6); foreach ($newdata as $root){ foreach ($root as $val){ printf('[%2s]',$val); } echo "<br/>"; }
标签:alt bsp sni reserve 元素 name value water roo
原文地址:http://www.cnblogs.com/lxjshuju/p/7222897.html