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HDU 1061-Rightmost Digit(快速幂)

时间:2014-09-03 09:43:26      阅读:189      评论:0      收藏:0      [点我收藏+]

标签:乘方取模   快速幂   acm   

Rightmost Digit

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 32258    Accepted Submission(s): 12403


Problem Description
Given a positive integer N, you should output the most right digit of N^N.
 

Input
The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains a single positive integer N(1<=N<=1,000,000,000).
 

Output
For each test case, you should output the rightmost digit of N^N.
 

Sample Input
2 3 4
O(logn)的复杂度就是快QAQ
题意 :求n^n%10 n<1000000000
#include <iostream>
#include <cstring>
#include <cstdio>
#include <cctype>
#include <cstdlib>
#include <algorithm>
#include <set>
#include <vector>
#include <string>
#include <map>
#include <queue>
using namespace std;
#define LL long long
LL multimod(LL a,LL n,LL m)
{
    LL ans=1,tem=a;
    while(n)
    {
        if(n&1)
            ans=ans*tem%m;
        tem=tem*tem%m;
        n/=2;
    }
    return ans;
}
int main()
{
    LL a,b;int T;
    cin>>T;
    while(T--)
    {
        cin>>a;
        cout<<multimod(a,a,10)<<endl;
    }
    return 0;
}


HDU 1061-Rightmost Digit(快速幂)

标签:乘方取模   快速幂   acm   

原文地址:http://blog.csdn.net/qq_16255321/article/details/39022315

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